Error when trying to specify VHDL standard in GHDL

Question

New with GHDL. This is my VHDL code:

/*
Name: test.vhd
Description: Demonstrates basic design in VHDL code.
Date: 04. August 2017 AD
*/

--first part: libraries
library IEEE;
use IEEE.STD_LOGIC_1164.all;

--second part: entity declaration
entity myEntity is
    port(a, b, c: in STD_LOGIC; y: out STD_LOGIC);
end;

--third part: entity implementation
architecture aom of myEntity is
begin
    y <= not b and (c or a and b);
end;

Trying to compile this with ghdl -s test.vhd gives me this error: test.vhd:1:1:error: block comment are not allowed before vhdl 2008.

So I try this: ghdl --std=08 -s test.vhd and I get this: ghdl:error: unknown command '--std=08', try --help.

command (-s) first. Invoking GHDL — GHDL 2017-03-01 documentation — user1155120
myentity.vhdl:19:28:error: only one type of logical operators may be used to combine relation Use y <= not b and (c or a) and b; See IEEE Std 1076-2008 9. Expressions, 9.1 General. The BNF defines the syntax requirement for the parentheses in a relation - shift_expression - simple_expression - term - factor - primary production expansion involving different logical operators. — user1155120

Hanlon Hanlon · Accepted Answer · 2017-11-09T17:31:13

It should be compiled this way: ghdl -s --std=08 test.vhd. So, -s flag should go first. All credits go to user1155120.

Error when trying to specify VHDL standard in GHDL

1 Answers