python - efficiently replace bad characters

Question

I often work with utf-8 text containing characters like:

\xc2\x99

\xc2\x95

\xc2\x85

etc

These characters confuse other libraries I work with so need to be replaced.

What is an efficient way to do this, rather than:

text.replace('\xc2\x99', ' ').replace('\xc2\x85, '...')

Answer 1

There is always regular expressions; just list all of the offending characters inside square brackets like so:

import re
print re.sub(r'[\xc2\x99]'," ","Hello\xc2There\x99")

This prints: 'Hello There ', with the unwanted characters replaced by spaces.

Alternately, if you have a different replacement character for each:

# remove annoying characters
chars = {
    '\xc2\x82' : ',',        # High code comma
    '\xc2\x84' : ',,',       # High code double comma
    '\xc2\x85' : '...',      # Tripple dot
    '\xc2\x88' : '^',        # High carat
    '\xc2\x91' : '\x27',     # Forward single quote
    '\xc2\x92' : '\x27',     # Reverse single quote
    '\xc2\x93' : '\x22',     # Forward double quote
    '\xc2\x94' : '\x22',     # Reverse double quote
    '\xc2\x95' : ' ',
    '\xc2\x96' : '-',        # High hyphen
    '\xc2\x97' : '--',       # Double hyphen
    '\xc2\x99' : ' ',
    '\xc2\xa0' : ' ',
    '\xc2\xa6' : '|',        # Split vertical bar
    '\xc2\xab' : '<<',       # Double less than
    '\xc2\xbb' : '>>',       # Double greater than
    '\xc2\xbc' : '1/4',      # one quarter
    '\xc2\xbd' : '1/2',      # one half
    '\xc2\xbe' : '3/4',      # three quarters
    '\xca\xbf' : '\x27',     # c-single quote
    '\xcc\xa8' : '',         # modifier - under curve
    '\xcc\xb1' : ''          # modifier - under line
}
def replace_chars(match):
    char = match.group(0)
    return chars[char]
return re.sub('(' + '|'.join(chars.keys()) + ')', replace_chars, text)

Answer 2

I think that there is an underlying problem here, and it might be a good idea to investigate and maybe solve it, rather than just trying to cover up the symptoms.

\xc2\x95 is the UTF-8 encoding of the character U+0095, which is a C1 control character (MESSAGE WAITING). It is not surprising that your library cannot handle it. But the question is, how did it get into your data?

Well, one very likely possibility is that it started out as the character 0x95 (BULLET) in the Windows-1252 encoding, was wrongly decoded as U+0095 instead of the correct U+2022, and then encoded into UTF-8. (The Japanese term mojibake describes this kind of mistake.)

If this is correct, then you can recover the original characters by putting them back into Windows-1252 and then decoding them into Unicode correctly this time. (In these examples I am using Python 3.3; these operations are a bit different in Python 2.)

>>> b'\x95'.decode('windows-1252')
'\u2022'
>>> import unicodedata
>>> unicodedata.name(_)
'BULLET'

If you want to do this correction for all the characters in the range 0x80–0x99 that are valid Windows-1252 characters, you can use this approach:

def restore_windows_1252_characters(s):
    """Replace C1 control characters in the Unicode string s by the
    characters at the corresponding code points in Windows-1252,
    where possible.

    """
    import re
    def to_windows_1252(match):
        try:
            return bytes([ord(match.group(0))]).decode('windows-1252')
        except UnicodeDecodeError:
            # No character at the corresponding code point: remove it.
            return ''
    return re.sub(r'[\u0080-\u0099]', to_windows_1252, s)

For example:

>>> restore_windows_1252_characters('\x95\x99\x85')
'•™…'

Answer 3

If you want to remove all non-ASCII characters from a string, you can use

text.encode("ascii", "ignore")

Answer 4

import unicodedata

# Convert to unicode
text_to_uncicode = unicode(text, "utf-8")           

# Convert back to ascii
text_fixed = unicodedata.normalize('NFKD',text_to_unicode).encode('ascii','ignore')         

Answer 5

This is not "Unicode characters" - it feels more like this an UTF-8 encoded string. (Although your prefix should be \xC3, not \xC2 for most chars). You should not just throw them away in 95% of the cases, unless you are comunicating with a COBOL backend. The World is not limited to 26 characters, you know.

There is a concise reading to explain the differences between Unicode strings (what is used as an Unicode object in python 2 and as strings in Python 3 here: http://www.joelonsoftware.com/articles/Unicode.html - please, for your sake do read that. Even if you are never planning to have anything that is not English in all of your applications, you still will stumble on symbols like € or º that won't fit in 7 bit ASCII. That article will help you.

That said, maybe the libraries you are using do accept Unicode python objects, and you can transform your UTF-8 Python 2 strings into unidoce by doing:

var_unicode = var.decode("utf-8")

If you really need 100% pure ASCII, replacing all non ASCII chars, after decoding the string to unicode, re-encode it to ASCII, telling it to ignore characters that don't fit in the charset with:

var_ascii = var_unicode.encode("ascii", "replace")

Answer 6

These characters are not in ASCII Library and that is the reason why you are getting the errors. To avoid these errors, you can do the following while reading the file.

import codecs   
f = codecs.open('file.txt', 'r',encoding='utf-8')

To know more about these kind of errors, go through this link.