376
votes

How do you do jQuery’s hasClass with plain ol’ JavaScript? For example,

<body class="foo thatClass bar">

What’s the JavaScript way to ask if <body> has thatClass?

15
I suppose you would have to parse the class property (which in case of multiple classes will have multiple class names in random order separated by a space) and check whether your class name is in it. Not terribly difficult, but still terribly inconvenient if not for learning purposes :)Pekka
don't know if I'm late for the party but a good site that gives alternatives to jQuery functions is youmightnotneedjquery.comithil

15 Answers

116
votes

You can check whether element.className matches /\bthatClass\b/.
\b matches a word break.

Or, you can use jQuery's own implementation:

var className = " " + selector + " ";
if ( (" " + element.className + " ").replace(/[\n\t]/g, " ").indexOf(" thatClass ") > -1 ) 

To answer your more general question, you can look at jQuery's source code on github or at the source for hasClass specifically in this source viewer.

1253
votes

Simply use classList.contains():

if (document.body.classList.contains('thatClass')) {
    // do some stuff
}

Other uses of classList:

document.body.classList.add('thisClass');
// $('body').addClass('thisClass');

document.body.classList.remove('thatClass');
// $('body').removeClass('thatClass');

document.body.classList.toggle('anotherClass');
// $('body').toggleClass('anotherClass');

Browser Support:

  • Chrome 8.0
  • Firefox 3.6
  • IE 10
  • Opera 11.50
  • Safari 5.1

classList Browser Support

35
votes

The most effective one liner that

  • returns a boolean (as opposed to Orbling's answer)
  • Does not return a false positive when searching for thisClass on an element that has class="thisClass-suffix".
  • is compatible with every browser down to at least IE6

function hasClass( target, className ) {
    return new RegExp('(\\s|^)' + className + '(\\s|$)').test(target.className);
}
31
votes

// 1. Use if for see that classes:

if (document.querySelector(".section-name").classList.contains("section-filter")) {
  alert("Grid section");
  // code...
}
<!--2. Add a class in the .html:-->

<div class="section-name section-filter">...</div>
29
votes

The attribute that stores the classes in use is className.

So you can say:

if (document.body.className.match(/\bmyclass\b/)) {
    ....
}

If you want a location that shows you how jQuery does everything, I would suggest:

http://code.jquery.com/jquery-1.5.js

13
votes

hasClass function:

HTMLElement.prototype.hasClass = function(cls) {
    var i;
    var classes = this.className.split(" ");
    for(i = 0; i < classes.length; i++) {
        if(classes[i] == cls) {
            return true;
        }
    }
    return false;
};

addClass function:

HTMLElement.prototype.addClass = function(add) {
    if (!this.hasClass(add)){
        this.className = (this.className + " " + add).trim();
    }
};

removeClass function:

HTMLElement.prototype.removeClass = function(remove) {
    var newClassName = "";
    var i;
    var classes = this.className.replace(/\s{2,}/g, ' ').split(" ");
    for(i = 0; i < classes.length; i++) {
        if(classes[i] !== remove) {
            newClassName += classes[i] + " ";
        }
    }
    this.className = newClassName.trim();
};
11
votes

I use a simple/minimal solution, one line, cross browser, and works with legacy browsers as well:

/\bmyClass/.test(document.body.className) // notice the \b command for whole word 'myClass'

This method is great because does not require polyfills and if you use them for classList it's much better in terms of performance. At least for me.

Update: I made a tiny polyfill that's an all round solution I use now:

function hasClass(element,testClass){
  if ('classList' in element) { return element.classList.contains(testClass);
} else { return new Regexp(testClass).exec(element.className); } // this is better

//} else { return el.className.indexOf(testClass) != -1; } // this is faster but requires indexOf() polyfill
  return false;
}

For the other class manipulation, see the complete file here.

9
votes

a good solution for this is to work with classList and contains.

i did it like this:

... for ( var i = 0; i < container.length; i++ ) {
        if ( container[i].classList.contains('half_width') ) { ...

So you need your element and check the list of the classes. If one of the classes is the same as the one you search for it will return true if not it will return false!

6
votes

Use something like:

Array.prototype.indexOf.call(myHTMLSelector.classList, 'the-class');
5
votes
if (document.body.className.split(/\s+/).indexOf("thatClass") !== -1) {
    // has "thatClass"
}
4
votes

This 'hasClass' function works in IE8+, FireFox and Chrome:

hasClass = function(el, cls) {
    var regexp = new RegExp('(\\s|^)' + cls + '(\\s|$)'),
        target = (typeof el.className === 'undefined') ? window.event.srcElement : el;
    return target.className.match(regexp);
}

[Updated Jan'2021] A better way:

hasClass = (el, cls) => {
  [...el.classList].includes(cls); //cls without dot
};
3
votes

Element.matches()

Instead of $(element).hasClass('example') in jQuery, you can use element.matches('.example') in plain JavaScript:

if (element.matches('.example')) {
  // Element has example class ...
}

View Browser Compatibility

1
votes

Well all of the above answers are pretty good but here is a small simple function I whipped up. It works pretty well.

function hasClass(el, cn){
    var classes = el.classList;
    for(var j = 0; j < classes.length; j++){
        if(classes[j] == cn){
            return true;
        }
    }
}
1
votes

What do you think about this approach?

<body class="thatClass anotherClass"> </body>

var bodyClasses = document.querySelector('body').className;
var myClass = new RegExp("thatClass");
var trueOrFalse = myClass.test( bodyClasses );

https://jsfiddle.net/5sv30bhe/

-1
votes

Here is the simplest way Only with javascript:

var allElements = document.querySelectorAll('*');
for (var i = 0; i < allElements.length; i++) {
    if (allElements[i].hasAttribute("class")) {
         //console.log(allElements[i].className);
         if (allElements[i].className.includes("_the _class ")) { 
              console.log("I see the class");
         }
    }
}