[1,2,3].forEach(function(el) {
if(el === 1) break;
});
How can I do this using the new forEach method in JavaScript? I've tried return;, return false; and break. break crashes and return does nothing but continue iteration.
1858
votes
29 Answers
2481
votes
There's no built-in ability to break in forEach. To interrupt execution you would have to throw an exception of some sort. eg.
var BreakException = {};
try {
[1, 2, 3].forEach(function(el) {
console.log(el);
if (el === 2) throw BreakException;
});
} catch (e) {
if (e !== BreakException) throw e;
}JavaScript exceptions aren't terribly pretty. A traditional for loop might be more appropriate if you really need to break inside it.
Use Array#some
Instead, use Array#some:
[1, 2, 3].some(function(el) {
console.log(el);
return el === 2;
});This works because some returns true as soon as any of the callbacks, executed in array order, return true, short-circuiting the execution of the rest.
some, its inverse every (which will stop on a return false), and forEach are all ECMAScript Fifth Edition methods which will need to be added to the Array.prototype on browsers where they're missing.
647
votes
There is now an even better way to do this in ECMAScript2015 (aka ES6) using the new for of loop. For example, this code does not print the array elements after the number 5:
let arr = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
for (let el of arr) {
console.log(el);
if (el === 5) {
break;
}
}From the docs:
Both for...in and for...of statements iterate over something. The main difference between them is in what they iterate over. The for...in statement iterates over the enumerable properties of an object, in original insertion order. The for...of statement iterates over data that iterable object defines to be iterated over.
Need the index in the iteration? You can use Array.entries():
for (const [index, el] of arr.entries()) {
if ( index === 5 ) break;
}
220
votes
You can use every method:
[1,2,3].every(function(el) {
return !(el === 1);
});
ES6
[1,2,3].every( el => el !== 1 )
for old browser support use:
if (!Array.prototype.every)
{
Array.prototype.every = function(fun /*, thisp*/)
{
var len = this.length;
if (typeof fun != "function")
throw new TypeError();
var thisp = arguments[1];
for (var i = 0; i < len; i++)
{
if (i in this &&
!fun.call(thisp, this[i], i, this))
return false;
}
return true;
};
}
more details here.
107
votes
Quoting from the MDN documentation of Array.prototype.forEach():
There is no way to stop or break a
forEach()loop other than by throwing an exception. If you need such behaviour, the.forEach()method is the wrong tool, use a plain loop instead. If you are testing the array elements for a predicate and need a boolean return value, you can useevery()orsome()instead.
For your code (in the question), as suggested by @bobince, use Array.prototype.some() instead. It suits very well to your usecase.
Array.prototype.some()executes the callback function once for each element present in the array until it finds one where callback returns a truthy value (a value that becomes true when converted to aBoolean). If such an element is found,some()immediately returns true. Otherwise,some()returns false. callback is invoked only for indexes of the array which have assigned values; it is not invoked for indexes which have been deleted or which have never been assigned values.
94
votes
34
votes
From your code example, it looks like Array.prototype.find is what you are looking for: Array.prototype.find() and Array.prototype.findIndex()
[1, 2, 3].find(function(el) {
return el === 2;
}); // returns 2
30
votes
Consider to use jquery's each method, since it allows to return false inside callback function:
$.each(function(e, i) {
if (i % 2) return false;
console.log(e)
})
Lodash libraries also provides takeWhile method that can be chained with map/reduce/fold etc:
var users = [
{ 'user': 'barney', 'active': false },
{ 'user': 'fred', 'active': false },
{ 'user': 'pebbles', 'active': true }
];
_.takeWhile(users, function(o) { return !o.active; });
// => objects for ['barney', 'fred']
// The `_.matches` iteratee shorthand.
_.takeWhile(users, { 'user': 'barney', 'active': false });
// => objects for ['barney']
// The `_.matchesProperty` iteratee shorthand.
_.takeWhile(users, ['active', false]);
// => objects for ['barney', 'fred']
// The `_.property` iteratee shorthand.
_.takeWhile(users, 'active');
// => []
21
votes
If you would like to use Dean Edward's suggestion and throw the StopIteration error to break out of the loop without having to catch the error, you can use the following the function (originally from here):
// Use a closure to prevent the global namespace from be polluted.
(function() {
// Define StopIteration as part of the global scope if it
// isn't already defined.
if(typeof StopIteration == "undefined") {
StopIteration = new Error("StopIteration");
}
// The original version of Array.prototype.forEach.
var oldForEach = Array.prototype.forEach;
// If forEach actually exists, define forEach so you can
// break out of it by throwing StopIteration. Allow
// other errors will be thrown as normal.
if(oldForEach) {
Array.prototype.forEach = function() {
try {
oldForEach.apply(this, [].slice.call(arguments, 0));
}
catch(e) {
if(e !== StopIteration) {
throw e;
}
}
};
}
})();
The above code will give you the ability to run code such as the following without having to do your own try-catch clauses:
// Show the contents until you get to "2".
[0,1,2,3,4].forEach(function(val) {
if(val == 2)
throw StopIteration;
alert(val);
});
One important thing to remember is that this will only update the Array.prototype.forEach function if it already exists. If it doesn't exist already, it will not modify the it.
15
votes
Short answer: use for...break for this or change your code to avoid breaking of forEach. Do not use .some() or .every() to emulate for...break. Rewrite your code to avoid for...break loop, or use for...break. Every time you use these methods as for...break alternative God kills kitten.
Long answer:
.some() and .every() both return boolean value, .some() returns true if there any element for which passed function returns true, every returns false if there any element for which passed function returns false. This is what that functions mean. Using functions for what they doesn't mean is much worse then using tables for layout instead of CSS, because it frustrates everybody who reads your code.
Also, the only possible way to use these methods as for...break alternative is to make side-effects (change some vars outside of .some() callback function), and this is not much different from for...break.
So, using .some() or .every() as for...break loop alternative isn't free of side effects, this isn't much cleaner then for...break, this is frustrating, so this isn't better.
You can always rewrite your code so that there will be no need in for...break. You can filter array using .filter(), you can split array using .slice() and so on, then use .forEach() or .map() for that part of array.
7
votes
This is just something I came up with to solve the problem... I'm pretty sure it fixes the problem that the original asker had:
Array.prototype.each = function(callback){
if(!callback) return false;
for(var i=0; i<this.length; i++){
if(callback(this[i], i) == false) break;
}
};
And then you would call it by using:
var myarray = [1,2,3];
myarray.each(function(item, index){
// do something with the item
// if(item != somecondition) return false;
});
Returning false inside the callback function will cause a break. Let me know if that doesn't actually work.
6
votes
As mentioned before, you can't break .forEach().
Here's a slightly more modern way of doing a foreach with ES6 Iterators. Allows you to get direct access to index/value when iterating.
const array = ['one', 'two', 'three'];
for (const [index, val] of array.entries()) {
console.log('item:', { index, val });
if (index === 1) {
console.log('break!');
break;
}
}
Output:
item: { index: 0, val: 'one' }
item: { index: 1, val: 'two' }
break!
Links
6
votes
Another concept I came up with:
function forEach(array, cb) {
var shouldBreak;
function _break() { shouldBreak = true; }
for (var i = 0, bound = array.length; i < bound; ++i) {
if (shouldBreak) { break; }
cb(array[i], i, array, _break);
}
}
// Usage
forEach(['a','b','c','d','e','f'], function (char, i, array, _break) {
console.log(i, char);
if (i === 2) { _break(); }
});5
votes
If you don't need to access your array after iteration you can bail out by setting the array's length to 0. If you do still need it after your iteration you could clone it using slice..
[1,3,4,5,6,7,8,244,3,5,2].forEach(function (item, index, arr) {
if (index === 3) arr.length = 0;
});
Or with a clone:
var x = [1,3,4,5,6,7,8,244,3,5,2];
x.slice().forEach(function (item, index, arr) {
if (index === 3) arr.length = 0;
});
Which is a far better solution then throwing random errors in your code.
4
votes
Found this solution on another site. You can wrap the forEach in a try / catch scenario.
if(typeof StopIteration == "undefined") {
StopIteration = new Error("StopIteration");
}
try {
[1,2,3].forEach(function(el){
alert(el);
if(el === 1) throw StopIteration;
});
} catch(error) { if(error != StopIteration) throw error; }
More details here: http://dean.edwards.name/weblog/2006/07/enum/
4
votes
3
votes
2
votes
1
votes
If you want to keep your forEach syntax, this is a way to keep it efficient (although not as good as a regular for loop). Check immediately for a variable that knows if you want to break out of the loop.
This example uses a anonymous function for creating a function scope around the forEach which you need to store the done information.
(function(){
var element = document.getElementById('printed-result');
var done = false;
[1,2,3,4].forEach(function(item){
if(done){ return; }
var text = document.createTextNode(item);
element.appendChild(text);
if (item === 2){
done = true;
return;
}
});
})();<div id="printed-result"></div>My two cents.
0
votes
Use the array.prototype.every function, which provide you the utility to break the looping. See example here Javascript documentation on Mozilla developer network
0
votes
Agree with @bobince, upvoted.
Also, FYI:
Prototype.js has something for this purpose:
<script type="text/javascript">
$$('a').each(function(el, idx) {
if ( /* break condition */ ) throw $break;
// do something
});
</script>
$break will be catched and handled by Prototype.js internally, breaking the "each" cycle but not generating external errors.
See Prototype.JS API for details.
jQuery also has a way, just return false in the handler to break the loop early:
<script type="text/javascript">
jQuery('a').each( function(idx) {
if ( /* break condition */ ) return false;
// do something
});
</script>
See jQuery API for details.
0
votes
0
votes
0
votes
0
votes
If you need to break based on the value of elements that are already in your array as in your case (i.e. if break condition does not depend on run-time variable that may change after array is assigned its element values) you could also use combination of slice() and indexOf() as follows.
If you need to break when forEach reaches 'Apple' you can use
var fruits = ["Banana", "Orange", "Lemon", "Apple", "Mango"];
var fruitsToLoop = fruits.slice(0, fruits.indexOf("Apple"));
// fruitsToLoop = Banana,Orange,Lemon
fruitsToLoop.forEach(function(el) {
// no need to break
});
As stated in W3Schools.com the slice() method returns the selected elements in an array, as a new array object. The original array will not be changed.
See it in JSFiddle
Hope it helps someone.
0
votes
try with "find" :
var myCategories = [
{category: "start", name: "Start", color: "#AC193D"},
{category: "action", name: "Action", color: "#8C0095"},
{category: "exit", name: "Exit", color: "#008A00"}
];
function findCategory(category) {
return myCategories.find(function(element) {
return element.category === category;
});
}
console.log(findCategory("start"));
// output: { category: "start", name: "Start", color: "#AC193D" }
0
votes
Why don't you try wrapping the function in a Promise?
The only reason I bring it up is that I am using a function in an API that acts in a similar manner to forEach. I don't want it to keep iterating once it finds a value, and I need to return something so I am simply going to resolve a Promise and do it that way.
traverseTree(doc): Promise<any> {
return new Promise<any>((resolve, reject) => {
this.gridOptions.api.forEachNode((node, index) => {
//the above function is the one I want to short circuit.
if(node.data.id === doc.id) {
return resolve(node);
}
});
});
}
Then all you need to do is do something with the result like
this.traverseTree(doc).then((result) => {
this.doSomething(result);
});
My above example is in typescript, simply ignore the types. The logic should hopefully help you "break" out of your loop.
0
votes
how about a simple array splicing by reducing the array length ???
It will messed up with your current array so you will have to make a copy by using a the destructuring features ...
eg:
const arr = [1, 2, 3, 4, 5];
// Don't forget to work with a copy of the original array otherwise you will loose your data contained inside
[...arr].forEach(function(value, index, copiedArrInstance) {
if (index === 2) copiedArrInstance.length = 0;
console.log(value);
});
// you will still have your array intact
console.log(arr);-2
votes
You can create a variant of forEach that allows for break, continue, return, and even async/await: (example written in TypeScript)
export type LoopControlOp = "break" | "continue" | ["return", any];
export type LoopFunc<T> = (value: T, index: number, array: T[])=>LoopControlOp;
Array.prototype.ForEach = function ForEach<T>(this: T[], func: LoopFunc<T>) {
for (let i = 0; i < this.length; i++) {
const controlOp = func(this[i], i, this);
if (controlOp == "break") break;
if (controlOp == "continue") continue;
if (controlOp instanceof Array) return controlOp[1];
}
};
// this variant lets you use async/await in the loop-func, with the loop "awaiting" for each entry
Array.prototype.ForEachAsync = async function ForEachAsync<T>(this: T[], func: LoopFunc<T>) {
for (let i = 0; i < this.length; i++) {
const controlOp = await func(this[i], i, this);
if (controlOp == "break") break;
if (controlOp == "continue") continue;
if (controlOp instanceof Array) return controlOp[1];
}
};
Usage:
function GetCoffee() {
const cancelReason = peopleOnStreet.ForEach((person, index)=> {
if (index == 0) return "continue";
if (person.type == "friend") return "break";
if (person.type == "boss") return ["return", "nevermind"];
});
if (cancelReason) console.log("Coffee canceled because: " + cancelReason);
}
returndoes indeed continue the iteration, it will skip any code that comes after it in the block. Take this code for instance:[1,2,3].forEach(function(el) { if(el === 2) { console.log(`Match on 2!`); return; } console.log(el); });.Theconsole.log(el);will be skipped when 2 is matched. – Shane