How to pass function argument into a list in Erlang?

0
votes

I'm trying to follow a tutorial on Erlang lists and I'm having difficulty passing an argument to a list. The following is the code, I'm unsure how to run it, I get the error,

exception error: no function clause matching insert

I've tried

cases:insert(1,[0]).

on the command line and many others...

-module(cases).
-export([insert/2]).

insert(X,[]) ->
    [X];
insert(X,Set) ->
    case lists:member(X,Set) of
        true  -> Set;
        false -> [X|Set]
    end.
1
listerlang

1 Answers

2
votes

The code you've posted works fine.

You may want to recompile it with c(cases) then give it a shot.

But it works just fine for me, I've copied and pasted it into cases.erl and this is the result of the command line:

7> cases:insert(0,[1]).                                                                             
[0,1]