Using jq with bash variables results in error

Question

I have the following json file

{
  "result": {
    "run": {
      "runtime": "runc"
    },
    "software": {
      "runc": "1.1.2",
      "kata": "1.3.7"
    }
  }
}

I can extract the runtime info using this

# jq -r '.result.software .runc' input.json
1.1.2

However, if I try to extract the version number dynamically, it does not work (The runtime can change)

# runtime=$(jq -r '.result.run .runtime' input.json)
# jq --arg key "$runtime" '.result.software .[$key]' 
jq: error: syntax error, unexpected '[', expecting FORMAT or QQSTRING_START (Unix shell quoting issues?) at <top-level>, line 1:
.result.software .[$key]                  
jq: 1 compile error

pmf pmf · Accepted Answer · 2022-07-19T08:52:04

The combined dot notation only works with literal names. Use .result.software[$key] instead:

runtime="$(jq -r '.result.run.runtime' input.json)"
jq -r --arg key "$runtime" '.result.software[$key]'

1.1.2

If the dynamic value is always a result of evaluating the same JSON file, and you don't need that value elsewhere in the shell script, you can resolve that internally and reduce the script to just one call to jq:

jq -r '.result.run.runtime as $key | .result.software[$key]' input.json

Demo

Or without using variables at all:

jq -r '.result | .software[.run.runtime]' input.json

Demo

Note: Never use double quotes to inject data into code. --arg is always a better choice.

Using jq with bash variables results in error

1 Answers