13
votes

I am trying to send data to my PHP script to handle some stuff and generate some items.

$.ajax({  
    type: "POST",  
    url: "test.php", 
    data: "album="+ this.title,
    success: function(response) {
        content.html(response);
    }
});

In my PHP file I try to retrieve the album name. Though when I validate it, I created an alert to show what the albumname is I get nothing, I try to get the album name by $albumname = $_GET['album'];

Though it will say undefined :/

3

3 Answers

47
votes

You are sending a POST AJAX request so use $albumname = $_POST['album']; on your server to fetch the value. Also I would recommend you writing the request like this in order to ensure proper encoding:

$.ajax({  
    type: 'POST',  
    url: 'test.php', 
    data: { album: this.title },
    success: function(response) {
        content.html(response);
    }
});

or in its shorter form:

$.post('test.php', { album: this.title }, function() {
    content.html(response);
});

and if you wanted to use a GET request:

$.ajax({  
    type: 'GET',
    url: 'test.php', 
    data: { album: this.title },
    success: function(response) {
        content.html(response);
    }
});

or in its shorter form:

$.get('test.php', { album: this.title }, function() {
    content.html(response);
});

and now on your server you wil be able to use $albumname = $_GET['album'];. Be careful though with AJAX GET requests as they might be cached by some browsers. To avoid caching them you could set the cache: false setting.

12
votes

Try sending the data like this:

var data = {};
data.album = this.title;

Then you can access it like

$_POST['album']

Notice not a 'GET'

4
votes

You can also use bellow code for pass data using ajax.

var dataString = "album" + title;
$.ajax({  
    type: 'POST',  
    url: 'test.php', 
    data: dataString,
    success: function(response) {
        content.html(response);
    }
});