How to disable the nesting made by hue in Seaborn?

Question

When using hue parameter on barplot in Seaborn it changes the color and the position of the bars. Like the following exemple:

Plot without hue:

import seaborn as sns
df = {'x': [1, 2, 3, 4], 'y': [5, 6, 7, 8], 'hue': ['a', 'b', 'b', 'a']}
sns.barplot(
    data = df,
    x = 'x',
    y = 'y',
)

Output: Seaborn barplot without hue

Plot with hue:

df = {'x': [1, 2, 3, 4], 'y': [5, 6, 7, 8], 'hue': ['a', 'b', 'b', 'a']}
sns.barplot(
    data = df,
    x = 'x',
    y = 'y',
    hue = 'hue'
)

Output: Seaborn barplot with hue

So how can I make a plot with the default bar position and the colors made by hue?

thorntonc thorntonc · Accepted Answer · 2020-08-11T20:20:41

Setting dodge=False fixes it for me.

import seaborn as sns

df = {'x': [1, 2, 3, 4], 'y': [5, 6, 7, 8], 'hue': ['a', 'b', 'b', 'a']}
sns.barplot(
    data = df,
    x = 'x',
    y = 'y',
    hue = 'hue',
    dodge=False 
)

From the docs:

dodge (bool, optional) - When hue nesting is used, whether elements should be shifted along the categorical axis.

How to disable the nesting made by hue in Seaborn?

1 Answers