How do I convert a nullable int
to an int
? Suppose I have 2 type of int as below:
int? v1;
int v2;
I want to assign v1
's value to v2
. v2 = v1;
will cause an error. How do I convert v1
to v2
?
The other answers so far are all correct; I just wanted to add one more that's slightly cleaner:
v2 = v1 ?? default(int);
Any Nullable<T>
is implicitly convertible to its T
, PROVIDED that the entire expression being evaluated can never result in a null assignment to a ValueType. So, the null-coalescing operator ??
is just syntax sugar for the ternary operator:
v2 = v1 == null ? default(int) : v1.Value;
...which is in turn syntax sugar for an if/else:
if(v1==null)
v2 = default(int);
else
v2 = v1.Value;
Also, as of .NET 4.0, Nullable<T>
has a "GetValueOrDefault()" method, which is a null-safe getter that basically performs the null-coalescing shown above, so this works too:
v2 = v1.GetValueOrDefault();
If you know that v1
has a value, you can use the Value
property:
v2 = v1.Value;
Using the GetValueOrDefault
method will assign the value if there is one, otherwise the default for the type, or a default value that you specify:
v2 = v1.GetValueOrDefault(); // assigns zero if v1 has no value
v2 = v1.GetValueOrDefault(-1); // assigns -1 if v1 has no value
You can use the HasValue
property to check if v1
has a value:
if (v1.HasValue) {
v2 = v1.Value;
}
There is also language support for the GetValueOrDefault(T)
method:
v2 = v1 ?? -1;
If the default value for a given type is an acceptable result:
if (v1.HasValue)
v2 = v1.GetValueOrDefault();
If you want a different default value when the result is undefined:
v2 = v1.GetValueOrDefault(255); // or any valid value for int in place of 255
If you just want the value returned (no matter if the method failed or not):
v2 = v1.GetValueOrDefault();
.NET 4.7.2.: GetValueOrDefault()
returns the field value without any checking.
Depending on your usage context, you may use C# 7's pattern-matching feature:
int? v1 = 100;
if (v1 is int v2)
{
Console.WriteLine($"I'm not nullable anymore: {v2}");
}
Since some people are downvoting without leaving an explanation, I'd like to add some details to explain the rationale for including this as a viable solution.
C# 7's pattern matching now allows us check the type of a value and cast it implicitly. In the above snippet, the if-condition will only pass when the value stored in v1
is type-compatible to the type for v2
, which in this case is int
. It follows that when the value for v1
is null
, the if-condition will fail since null cannot be assigned to an int
. More properly, null
is not an int
.
I'd like to highlight that the that this solution may not always be the optimal choice. As I suggest, I believe this will depend on the developer's exact usage context. If you already have an int?
and want to conditionally operate on its value if-and-only-if the assigned value is not null (this is the only time it is safe to convert a nullable int to a regular int without losing information), then pattern matching is perhaps one of the most concise ways to do this.
A simple conversion between v1
and v2
is not possible because v1
has a larger domain of values than v2
. It's everything v1
can hold plus the null
state. To convert you need to explicitly state what value in int
will be used to map the null
state. The simplest way to do this is the ??
operator
v2 = v1 ?? 0; // maps null of v1 to 0
This can also be done in long form
int v2;
if (v1.HasValue) {
v2 = v1.Value;
} else {
v2 = 0;
}
In C# 7.1 and later, type can be inferred by using the default
literal instead of the default
operator so it can be written as below:
v2 = v1 ?? default;
Normal TypeConversion will throw an exception
Eg:
int y = 5;
int? x = null;
y = x.value; //It will throw "Nullable object must have a value"
Console.WriteLine(y);
Use Convert.ToInt32()
method
int y = 5;
int? x = null;
y = x.Convert.ToInt32(x);
Console.WriteLine(y);
This will return 0 as output because y is an integer.
v1
isnull
? – Solomon Ucko