How can I convert String to Int?

Question

I have a TextBoxD1.Text and I want to convert it to an int to store it in a database.

How can I do this?

Answer 1

Try this:

int x = Int32.Parse(TextBoxD1.Text);

or better yet:

int x = 0;

Int32.TryParse(TextBoxD1.Text, out x);

Also, since Int32.TryParse returns a bool you can use its return value to make decisions about the results of the parsing attempt:

int x = 0;

if (Int32.TryParse(TextBoxD1.Text, out x))
{
    // you know that the parsing attempt
    // was successful
}

If you are curious, the difference between Parse and TryParse is best summed up like this:

The TryParse method is like the Parse method, except the TryParse method does not throw an exception if the conversion fails. It eliminates the need to use exception handling to test for a FormatException in the event that s is invalid and cannot be successfully parsed. - MSDN

Answer 2

Convert.ToInt32( TextBoxD1.Text );

Use this if you feel confident that the contents of the text box is a valid int. A safer option is

int val = 0;
Int32.TryParse( TextBoxD1.Text, out val );

This will provide you with some default value you can use. Int32.TryParse also returns a Boolean value indicating whether it was able to parse or not, so you can even use it as the condition of an if statement.

if( Int32.TryParse( TextBoxD1.Text, out val ){
  DoSomething(..);
} else {
  HandleBadInput(..);
}

Answer 3

int.TryParse()

It won't throw if the text is not numeric.

Answer 4

int myInt = int.Parse(TextBoxD1.Text)

Another way would be:

bool isConvertible = false;
int myInt = 0;

isConvertible = int.TryParse(TextBoxD1.Text, out myInt);

The difference between the two is that the first one would throw an exception if the value in your textbox can't be converted, whereas the second one would just return false.

Answer 5

You need to parse the string, and you also need to ensure that it is truly in the format of an integer.

The easiest way is this:

int parsedInt = 0;
if (int.TryParse(TextBoxD1.Text, out parsedInt))
{
   // Code for if the string was valid
}
else
{
   // Code for if the string was invalid
}

Answer 6

Be careful when using Convert.ToInt32() on a char! It will return the UTF-16 code of the character!

If you access the string only in a certain position using the [i] indexing operator, it will return a char and not a string!

String input = "123678";
                    ^
                    |
int indexOfSeven =  4;

int x = Convert.ToInt32(input[indexOfSeven]);             // Returns 55

int x = Convert.ToInt32(input[indexOfSeven].toString());  // Returns 7

Answer 7

int x = 0;
int.TryParse(TextBoxD1.Text, out x);

The TryParse statement returns a boolean representing whether the parse has succeeded or not. If it succeeded, the parsed value is stored into the second parameter.

See Int32.TryParse Method (String, Int32) for more detailed information.

Answer 8

Enjoy it...

int i = 0;
string s = "123";
i =int.Parse(s);
i = Convert.ToInt32(s);

Answer 9

While there are already many solutions here that describe int.Parse, there's something important missing in all the answers. Typically, the string representations of numeric values differ by culture. Elements of numeric strings such as currency symbols, group (or thousands) separators, and decimal separators all vary by culture.

If you want to create a robust way to parse a string to an integer, it's therefore important to take the culture information into account. If you don't, the current culture settings will be used. That might give a user a pretty nasty surprise -- or even worse, if you're parsing file formats. If you just want English parsing, it's best to simply make it explicit, by specifying the culture settings to use:

var culture = CultureInfo.GetCulture("en-US");
int result = 0;
if (int.TryParse(myString, NumberStyles.Integer, culture, out result))
{
    // use result...
}

For more information, read up on CultureInfo, specifically NumberFormatInfo on MSDN.

Answer 10

You can write your own extension method

public static class IntegerExtensions
{
    public static int ParseInt(this string value, int defaultValue = 0)
    {
        int parsedValue;
        if (int.TryParse(value, out parsedValue))
        {
            return parsedValue;
        }

        return defaultValue;
    }

    public static int? ParseNullableInt(this string value)
    {
        if (string.IsNullOrEmpty(value))
        {
            return null;
        }

        return value.ParseInt();
    }
}

And wherever in code just call

int myNumber = someString.ParseInt(); // Returns value or 0
int age = someString.ParseInt(18); // With default value 18
int? userId = someString.ParseNullableInt(); // Returns value or null

In this concrete case

int yourValue = TextBoxD1.Text.ParseInt();

Answer 11

int x = Int32.TryParse(TextBoxD1.Text, out x) ? x : 0;

Answer 12

As explained in the TryParse documentation, TryParse() returns a Boolean which indicates that a valid number was found:

bool success = Int32.TryParse(TextBoxD1.Text, out val);

if (success)
{
    // Put val in database
}
else
{
    // Handle the case that the string doesn't contain a valid number
}

Answer 13

You also may use an extension method, so it will be more readable (although everybody is already used to the regular Parse functions).

public static class StringExtensions
{
    /// <summary>
    /// Converts a string to int.
    /// </summary>
    /// <param name="value">The string to convert.</param>
    /// <returns>The converted integer.</returns>
    public static int ParseToInt32(this string value)
    {
        return int.Parse(value);
    }

    /// <summary>
    /// Checks whether the value is integer.
    /// </summary>
    /// <param name="value">The string to check.</param>
    /// <param name="result">The out int parameter.</param>
    /// <returns>true if the value is an integer; otherwise, false.</returns>
    public static bool TryParseToInt32(this string value, out int result)
    {
        return int.TryParse(value, out result);
    }
}

And then you can call it that way:

1. If you are sure that your string is an integer, like "50".

   int num = TextBoxD1.Text.ParseToInt32();
   

2. If you are not sure and want to prevent crashes.

   int num;
   if (TextBoxD1.Text.TryParseToInt32(out num))
   {
       //The parse was successful, the num has the parsed value.
   }
   

To make it more dynamic, so you can parse it also to double, float, etc., you can make a generic extension.

Answer 14

//May be quite some time ago but I just want throw in some line for any one who may still need it

int intValue;
string strValue = "2021";

try
{
    intValue = Convert.ToInt32(strValue);
}
catch
{
    //Default Value if conversion fails OR return specified error
    // Example 
    intValue = 2000;
}

Answer 15

You can use either,

int i = Convert.ToInt32(TextBoxD1.Text);

or

int i = int.Parse(TextBoxD1.Text);

Answer 16

You can convert a string to int in C# using:

Functions of convert class i.e. Convert.ToInt16(), Convert.ToInt32(), Convert.ToInt64() or by using Parse and TryParse Functions. Examples are given here.

Answer 17

This would do

string x = TextBoxD1.Text;
int xi = Convert.ToInt32(x);

Or you can use

int xi = Int32.Parse(x);

Refer Microsoft Developer Network for more information

Answer 18

You can do like below without TryParse or inbuilt functions:

static int convertToInt(string a)
{
    int x = 0;
    for (int i = 0; i < a.Length; i++)
    {
        int temp = a[i] - '0';
        if (temp != 0)
        {
            x += temp * (int)Math.Pow(10, (a.Length - (i+1)));
        }
    }
    return x;
}

Answer 19

You can convert string to int many different type methods in C#

First one is mostly use :

string test = "123";
int x = Convert.ToInt16(test);

if int value is higher you should use int32 type.

Second one:

int x = int.Parse(text);

if you want to error check, you can use TryParse method. In below I add nullable type;

int i=0;
Int32.TryParse(text, out i) ? i : (int?)null);

Enjoy your codes....

Answer 20

Conversion of string to int can be done for: int, Int32, Int64 and other data types reflecting integer data types in .NET

Below example shows this conversion:

This shows (for info) data adapter element initialized to int value. The same can be done directly like,

int xxiiqVal = Int32.Parse(strNabcd);

Ex.

string strNii = "";
UsrDataAdapter.SelectCommand.Parameters["@Nii"].Value = Int32.Parse(strNii );

Link to see this demo.

Answer 21

int i = Convert.ToInt32(TextBoxD1.Text);

Answer 22

You can convert string to an integer value with the help of parse method.

Eg:

int val = Int32.parse(stringToBeParsed);
int x = Int32.parse(1234);

Answer 23

The way I always do this is like this:

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace example_string_to_int
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            string a = textBox1.Text;
            // This turns the text in text box 1 into a string
            int b;
            if (!int.TryParse(a, out b))
            {
                MessageBox.Show("This is not a number");
            }
            else
            {
                textBox2.Text = a+" is a number" ;
            }
            // Then this 'if' statement says if the string is not a number, display an error, else now you will have an integer.
        }
    }
}

This is how I would do it.

Answer 24

In C# v.7 you could use an inline out parameter, without an additional variable declaration:

int.TryParse(TextBoxD1.Text, out int x);

Answer 25

In case you know the string is an integer do:

int value = int.Parse(TextBoxD1.Text);

In case you don't know the string is an integer do it safely with TryParse.

In C# 7.0 you can use inline variable declaration.

• If parse successes - value = its parsed value.
• If parse fails - value = 0.

Code:

if (int.TryParse(TextBoxD1.Text, out int value))
{
    // Parse succeed
}

Drawback:

You cannot differentiate between a 0 value and a non parsed value.

Answer 26

METHOD 1

int  TheAnswer1 = 0;
bool Success = Int32.TryParse("42", out TheAnswer1);
if (!Success) {
    Console.WriteLine("String not Convertable to an Integer");
}

METHOD 2

int TheAnswer2 = 0;
try {
    TheAnswer2 = Int32.Parse("42");
}
catch {
    Console.WriteLine("String not Convertable to an Integer");
}

METHOD 3

int TheAnswer3 = 0;
try {
    TheAnswer3 = Int32.Parse("42");
}
catch (FormatException) {
    Console.WriteLine("String not in the correct format for an Integer");
}
catch (ArgumentNullException) {
    Console.WriteLine("String is null");
}
catch (OverflowException) {
    Console.WriteLine("String represents a number less than"
                      + "MinValue or greater than MaxValue");
}

Answer 27

This code works for me in Visual Studio 2010:

int someValue = Convert.ToInt32(TextBoxD1.Text);

Answer 28

You can try the following. It will work:

int x = Convert.ToInt32(TextBoxD1.Text);

The string value in the variable TextBoxD1.Text will be converted into Int32 and will be stored in x.

Answer 29

While I agree on using the TryParse method, a lot of people dislike the use of out parameter (myself included). With tuple support having been added to C#, an alternative is to create an extension method that will limit the number of times you use out to a single instance:

public static class StringExtensions
{
    public static (int result, bool canParse) TryParse(this string s)
    {
        int res;
        var valid = int.TryParse(s, out res);
        return (result: res, canParse: valid);
    }
}

(Source: C# how to convert a string to int)

Answer 30

If you're looking for the long way, just create your one method:

static int convertToInt(string a)
{
    int x = 0;
        
    Char[] charArray = a.ToCharArray();
    int j = charArray.Length;

    for (int i = 0; i < charArray.Length; i++)
    {
        j--;
        int s = (int)Math.Pow(10, j);

        x += ((int)Char.GetNumericValue(charArray[i]) * s);
    }
    return x;
}