Context menu for specific dynamic column for datagrid wpf

Question

I really need help to figure out how to add a context menu for a specific column on a datagrid.

Currently my datagrid looks like this: Datagrid and all columns are added to the datagrid dynamically with the itemsource: ItemsSource="{Binding Data.DefaultView}" and I have AutoGenerateColumns="True". Currently I can add different contextmenu for all the headers by using a style and a trigger. Example:

<Style TargetType="{x:Type DataGridColumnHeader}">
                <Style.Triggers>
                    <Trigger Property="Content" Value="CoreRefDes">
                        <Setter Property="ContextMenu"
                        Value="{StaticResource DataGridColumnHeaderContextMenuSpecific}" />
                    </Trigger>
                    <Trigger Property="Content" Value="CorePartNumber">
                        <Setter Property="ContextMenu"
                        Value="{StaticResource DataGridColumnHeaderContextMenuSpecific}" />
                    </Trigger>
                    <Trigger Property="Content" Value="CoreDescription">
                        <Setter Property="ContextMenu"
                        Value="{StaticResource DataGridColumnHeaderContextMenuSpecific}" />
                    </Trigger>
                    <Trigger Property="Content" Value="Split">
                        <Setter Property="ContextMenu"
                        Value="{StaticResource DataGridColumnHeaderContextMenuSpecific}" />
                    </Trigger>
                </Style.Triggers>

I want something similar but instead of the contextmenu on the header I want it on the cells or the datagrid based on the header name. Currently my contextmenu appears on the datagrid like this:

                <Style TargetType="{x:Type DataGrid}">
                <Setter Property="ContextMenu" Value="{DynamicResource DatagridCellContextmenuItems}"/>
            </Style>

Problem with this is I get the same contextmenu for all the columns. I want a different contextmenu for column 1 and 2. Any idea on how to solve this?

Thank you very much!

Andrew Stephens Andrew Stephens · Accepted Answer · 2019-12-20T15:05:22

This one is a bit of a pain to achieve, but this is how I've done in the past.

I have a context menu on the data grid that contains every possible menu item that I might need. I then hide or show each one depending on which row/column/cell was r.clicked.

Here's the datagrid XAML snippet:

<DataGrid ContextMenuOpening="GridContextMenuOpening" ...>
    <DataGrid.ContextMenu>
        <ContextMenu>
            <MenuItem x:Name="mnuOpen" ... />
            <MenuItem x:Name="mnuNew" ... />
            <!-- and so on -->
        </ContextMenu>
    </DataGrid.ContextMenu>

    <!-- rest of datagrid - columns etc -->
</DataGrid>

Note the DataGrid's ContextMenuOpening event handler - here is the code-behind:-

private void GridContextMenuOpening(object sender, ContextMenuEventArgs e)
{
    DataGridCell cell;
    DataGridRow row;

    var dep = DataGridMiscHelpers.FindVisualParentAsDataGridSubComponent(
        (DependencyObject)e.OriginalSource);
    if (dep == null)
    {
        return;
    }

    DataGridMiscHelpers.FindCellAndRow(dep, out cell, out row);
    if (dep is DataGridColumnHeader || dep is DataGridRow)
    {
        e.Handled = true;
        return;
    }

    // Hide/show the menu items depending on the cell and/or row clicked.
    // (You could programmatically add/remove menu items here instead).
    mnuOpen.Visibility = (cell.Column.Header == "whatever") ? Visibility.Hidden : Visibility.Visible;
    mnuNew.Visibility = ((row.Item as MyViewModel).SomeProperty == 123) ? Visibility.Hidden : Visibility.Visible;
}

And here's my "DataGridMiscHelpers" static class used by the above code:-

using System.Windows;
using System.Windows.Controls;
using System.Windows.Controls.Primitives;
using System.Windows.Media;
using System.Windows.Media.Media3D;

public static class DataGridMiscHelpers
{
    /// <summary>
    /// Finds the visual parent of the given object
    /// </summary>
    /// <param name="originalSource">The original source.</param>
    /// <returns></returns>
    public static DependencyObject FindVisualParentAsDataGridSubComponent(
        DependencyObject originalSource)
    {
        // iteratively traverse the visual tree
        while ((originalSource != null) 
            && !(originalSource is DataGridCell) 
            && !(originalSource is DataGridColumnHeader) 
            && !(originalSource is DataGridRow))
        {
            if (originalSource is Visual || originalSource is Visual3D)
            {
                originalSource = VisualTreeHelper.GetParent(originalSource);
            }
            else
            {
                // If we're in Logical Land then we must walk 
                // up the logical tree until we find a 
                // Visual/Visual3D to get us back to Visual Land.
                originalSource = LogicalTreeHelper.GetParent(originalSource);
            }
        }

        return originalSource;
    }

    /// <summary>
    /// Finds the cell and row data for the given source.
    /// </summary>
    /// <param name="originalSource">The original source.</param>
    /// <param name="cell">The cell.</param>
    /// <param name="row">The row.</param>
    public static void FindCellAndRow(DependencyObject originalSource, 
        out DataGridCell cell, out DataGridRow row)
    {
        cell = originalSource as DataGridCell;
        if (cell == null)
        {
            row = null;
            return;
        }

        // Walk the visual tree to find the cell's parent row.
        while ((originalSource != null) && !(originalSource is DataGridRow))
        {
            if (originalSource is Visual || originalSource is Visual3D)
            {
                originalSource = VisualTreeHelper.GetParent(originalSource);
            }
            else
            {
                // If we're in Logical Land then we must walk up the logical tree 
                // until we find a Visual/Visual3D to get us back to Visual Land.
                // See: http://www.codeproject.com/Articles/21495/Understanding-the-Visual-Tree-and-Logical-Tree-in
                originalSource = LogicalTreeHelper.GetParent(originalSource);
            }
        }

        row = originalSource as DataGridRow;
    }
}

}

Disclaimer: I've just copied/pasted some of these snippets out of a larger codebase so it may not be 100% correct, but hopefully enough to get you started.

Context menu for specific dynamic column for datagrid wpf

2 Answers