How to hard code the color for the displayed variable in plotly pie chart?

Question

Do we have something similar to our ggplot where we define the color panel for each variable ?

scale_manual <- function(...){
ggplot2::manual_scale(
"fill",
values = setnames(c("green","red","blue","yellow","grey"),
c("var1","var2","var3","var4","var5")),
...
)
}

Although this Q seems to answer, How can I change the colors of the slices in pie charts in plotly for r using hexadecimal strings?

but it is not working here.

Please consider an reprex below:

library(plotly)

USPersonalExpenditure <- data.frame("Categorie"=rownames(USPersonalExpenditure), USPersonalExpenditure)
data <- USPersonalExpenditure[,c('Categorie', 'X1960')]

p <- plot_ly(data, labels = ~Categorie, values = ~X1960, type = 'pie') %>%
  layout(title = 'United States Personal Expenditures by Categories in 1960',
         xaxis = list(showgrid = FALSE, zeroline = FALSE, showticklabels = FALSE),
         yaxis = list(showgrid = FALSE, zeroline = FALSE, showticklabels = FALSE))

#trial 1
plot_ly(data, labels = ~Categorie, values = ~X1960, type = 'pie', marker = list(color = rainbow(5))) %>%
layout(title = 'United States Personal Expenditures by Categories in 1960', 
xaxis = list(showgrid = FALSE, zeroline = FALSE, showticklabels = FALSE),
yaxis = list(showgrid = FALSE, zeroline = FALSE, showticklabels = FALSE))

# trial 2
plot_ly(data, labels = ~Categorie, values = ~X1960, type = 'pie', marker = list(color = brewer_pal(5, "Set3"))) %>%
layout(title = 'United States Personal Expenditures by Categories in 1960', 
xaxis = list(showgrid = FALSE, zeroline = FALSE, showticklabels = FALSE),
yaxis = list(showgrid = FALSE, zeroline = FALSE, showticklabels = FALSE))

Since there are many plots using the same data, color need to be consistent.

So, trying to hard code for each variable.

maaniB maaniB · Accepted Answer · 2019-08-22T08:08:13

I usually use Color mapping functions from the leaflet package before making interactive plots for shiny apps and plotly charts:

Hard code the color variable using your desired palette.

data$color <- leaflet::colorFactor(
  palette = "Dark2", domain = data$Categorie
  )(data$Categorie)

plot_ly(
  data, labels = ~Categorie,  values = ~X1960, type = 'pie',
  marker = list( colors = ~color)
  ) %>%
  layout(
    title = 'United States Personal Expenditures by Categories in 1960', 
    xaxis = list(showgrid = FALSE, zeroline = FALSE, showticklabels = FALSE),
    yaxis = list(showgrid = FALSE, zeroline = FALSE, showticklabels = FALSE)
    )

You may also hardcode it manually:

colors_list <- list(
  "Food and Tobacco" = "#1B9E77",
  "Household Operation" = "#D95F02",
  "Medical and Health" = "#7570B3",
  "Personal Care" = "#E7298A",
  "Private Education" = "#66A61E"
)

data$color <- dplyr::recode(data$Categorie, !!!colors_list)


plot_ly(
  data, labels = ~Categorie,  values = ~X1960, type = 'pie',
  marker = list( colors = ~color)
) %>%
  layout(
    title = 'United States Personal Expenditures by Categories in 1960', 
    xaxis = list(showgrid = FALSE, zeroline = FALSE, showticklabels = FALSE),
    yaxis = list(showgrid = FALSE, zeroline = FALSE, showticklabels = FALSE)
  )

How to hard code the color for the displayed variable in plotly pie chart?

1 Answers