I want to make paging in the table using Pagedlist and get an error
The model item passed into the dictionary is of type 'PagedList.PagedList
1[System.Collections.Generic.KeyValuePair
2[MyProject.Data.Models.User,System.Collections.Generic.IEnumerable`1[MyProject.Data.Models.Role]]]', but this dictionary requires a model item of type
I can make paging but only for one model like using code "View(db.Roles.ToList().ToPagedList(pageNumber, pageSize))". But for this case it's different, here I use two models namely User and Role. I use a dictionary to call the two models. I am confused about how to implement it in view using PagedList. This is the code that I have tried.Thanks
public ActionResult Index(int? page)
{
int pageSize = 2;
int pageNumber = (page ?? 1);
Dictionary<User, IEnumerable<Role>> userRoles = userRoleRepo.GetDictionary_UserAndRolesOfEachUser();
return View(userRoles.ToPagedList(pageNumber, pageSize));
}
View
@model PagedList.IPagedList<Dictionary<MyProject.Data.Models.User, IEnumerable<MyProject.Data.Models.Role>>>
<table class="table">
<tr class="header">
<th> UserName</th>
<th> FullName</th>
</tr>
@foreach (Dictionary<MyProject.Data.Models.User, IEnumerable<MyProject.Data.Models.Role>> item in Model)
{
<tr class="detail">
<td>
@Html.DisplayFor(modelItem => item.First().Key.UserName)
</td>
<td>
@Html.DisplayFor(modelItem => item.First().Key.FullName)
</td>
<td>
<ul>
@foreach (var role in item.First().Value)
{
<li>
@Html.DisplayFor(modelItem => role.RoleName)
</li>
}
</ul>
</td>
</tr>
}
</table>
Page @(Model.PageCount < Model.PageNumber ? 0 : Model.PageNumber) of @Model.PageCount
@Html.PagedListPager(Model, page => Url.Action("Index", new { page}))