I have a sql query and I want to fetch all the conditions in where
clause into a Python dictionary.
e.g.,
import sqlparse
s = "select count(*) from users where employee_type = 'Employee' AND (employment_status = 'Active' OR employment_status = 'On Leave') AND (time_type='Full time' OR country_code <> 'US') AND hire_date < NOW() AND email_work IS NOT NULL AND LENGTH(email_work) > 0 AND NOT (job_profile_id IN ('8802 - Comm Ops - 1', '8801 - CityOps - 2', '10034', '10455', '21014', '21015', '21016', '21018', '21017', '21019') AND country_code = 'IE') AND job_profile_id NOT IN ('20992', '20993', '20994', '20995', '20996', '20997') AND country_code NOT IN ('CN', 'MO', 'SG', 'MY', 'TH', 'VN', 'MM', 'KH', 'PH', 'ID')"
parsed = sqlparse.parse(s)
where = parsed[0][-1]
sql_tokens = []
def get_tokens(where):
for i in where.tokens:
try:
name = i.get_real_name()
if name and not isinstance(i, sqlparse.sql.Parenthesis):
# sql_tokens.append("{0} - {1} - {2}".format(str(i), str(name), i.value))
sql_tokens.append({
'key': str(name),
'value': i.value,
})
else:
get_tokens(i)
except Exception as e:
pass
get_tokens(where)
for i in sql_tokens:
print i
Following is the output
{'value': u"employee_type = 'Employee'", 'key': 'employee_type'}
{'value': u"employment_status = 'Active'", 'key': 'employment_status'}
{'value': u"employment_status = 'On Leave'", 'key': 'employment_status'}
{'value': u"time_type='Full time'", 'key': 'time_type'}
{'value': u"country_code <> 'US'", 'key': 'country_code'}
{'value': u'hire_date < NOW()', 'key': 'hire_date'}
{'value': u'email_work', 'key': 'email_work'}
{'value': u'LENGTH(email_work) > 0', 'key': 'LENGTH'}
{'value': u'job_profile_id', 'key': 'job_profile_id'}
{'value': u"country_code = 'IE'", 'key': 'country_code'}
{'value': u'job_profile_id', 'key': 'job_profile_id'}
{'value': u'country_code', 'key': 'country_code'}
The problem here is with the IN
operator.
Check job_profile_id
, it doesn't contain the list.
On debugging, it doesn't show the list.
I am unable to resolve this issue.
Please help.
Appreciate the help.