How to implement "LIKE ANY" in BigQuery (standard SQL)?

Question

I would like to use "like any" function. However, BigQuery doesnot recognize "ANY" operator. Is there any function which can replace "LIKE ANY" ?

Bigquery - Standard SQL

    SELECT
      date,
      CONCAT(fullvisitorid, CAST(visitid AS string)) ord_browsers,
      hits.appInfo.landingScreenName,
      channelgrouping,
      trafficSource.source,
      trafficSource.medium,
      CASE
        WHEN channelgrouping = 'seo_brand' THEN 'Branded'
        WHEN hits.appInfo.landingScreenName LIKE '%/article%'
      OR hits.appInfo.landingScreenName LIKE '%/p/%' THEN 'ADS'
        WHEN (hits.appInfo.landingScreenName LIKE ANY ('%/damesmode/%',  '%/herenkleding/%',  '%/kinderkleding/%',  '%/sportkleding/%')) THEN 'Plist'
        ELSE 'rest'
      END Landing_page
    FROM
      `meta-geography-145406.81187684.ga_sessions_*`,
      UNNEST(hits) AS hits
    WHERE
      (_table_suffix BETWEEN '20190201'
        AND '20190207')

Syntax error: Unexpected keyword ANY at [12:47]

Answer 1

Simpler query with the same problem:

WITH table AS (
  SELECT 'XXXX/herenkleding/XXX' x
)

SELECT x
FROM TABLE
WHERE x LIKE ANY ( 
  '%/damesmode/%'  '%/herenkleding/%',  '%/kinderkleding/%',  '%/sportkleding/%'
)

Syntax error: Unexpected keyword ANY at [2:6]

Alternative 1: Replace with a series of LIKE OR

SELECT x
FROM TABLE
WHERE (x LIKE '%/damesmode/%' 
OR x LIKE '%/herenkleding/%'
OR x LIKE '%/kinderkleding/%'
OR x LIKE'%/sportkleding/%')

XXXX/herenkleding/XXX

Alternative 2: Combine into one regular expression

WITH table AS (
  SELECT 'XXXX/herenkleding/XXX' x
)

SELECT x
FROM TABLE
WHERE REGEXP_CONTAINS(x
  , '/(damesmode|herenkleding|kinderkleding|sportkleding)/')

XXXX/herenkleding/XXX

Answer 2

Here is an alternative approach. This will keep your original query intact, while implementing what you want:

 SELECT
      date,
      CONCAT(fullvisitorid, CAST(visitid AS string)) ord_browsers,
      hits.appInfo.landingScreenName,
      channelgrouping,
      trafficSource.source,
      trafficSource.medium,
      CASE
        WHEN channelgrouping = 'seo_brand' THEN 'Branded'
        WHEN hits.appInfo.landingScreenName LIKE '%/article%'
      OR hits.appInfo.landingScreenName LIKE '%/p/%' THEN 'ADS'
        WHEN (hits.appInfo.landingScreenName LIKE c) THEN 'Plist'
        ELSE 'rest'
      END Landing_page
    FROM
      `meta-geography-145406.81187684.ga_sessions_*`,
      UNNEST(hits) AS hits, UNNEST([
       '%/damesmode/%',
       '%/herenkleding/%',
       '%/kinderkleding/%',
       '%/sportkleding/%']) AS c
    WHERE
      (_table_suffix BETWEEN '20190201'
        AND '20190207')

Notice the array being unnested and each item is being compared in the CASE statement.

Answer 3

Below is for BigQuery Standard SQL

#standardSQL
SELECT
  DATE,
  CONCAT(fullvisitorid, CAST(visitid AS STRING)) ord_browsers,
  hits.appInfo.landingScreenName,
  channelgrouping,
  trafficSource.source,
  trafficSource.medium,
  CASE
    WHEN channelgrouping = 'seo_brand' THEN 'Branded'
    WHEN REGEXP_CONTAINS(hits.appInfo.landingScreenName , '/(article|p)/') THEN 'ADS'
    WHEN REGEXP_CONTAINS(hits.appInfo.landingScreenName , '/(damesmode|herenkleding|kinderkleding|sportkleding)/') THEN 'Plist'
    ELSE 'rest'
  END Landing_page
FROM `meta-geography-145406.81187684.ga_sessions_*`,
UNNEST(hits) AS hits
WHERE _TABLE_SUFFIX BETWEEN '20190201' AND '20190207'