It is not a bug, MSVC compiles your code because it has an extension which enables binding temporary object (Rvalue) to non-const Lvalue reference.
Below code compiles with MSVC:
void foo(int& i) {}
foo(20); // you are passing Rvalue and it is bound to Lvalue reference
Above code doesn't compile under G++ or CLang, when you add const to make reference to
const Lvalue, it works:
void foo(const int&){}
foo(20); // you can bind Rvalue to const Lvalue reference
A few words about vector. operator[] for vector<T> where T is every type except bool returns T&:
T& vector<T>::operator[](index) // where T is not bool
For bool vector class template has specialization. Values of bool are stored to hold one bit space, because you cannot use address-of operator for one bit, vector<bool>::operator[](index) cannot return reference. vector<bool> has inner proxy class which manipulates bits (call this class as reference).
vector<bool>::reference vector<bool>::operator[](index)
^^^^^^^^^
as you see object of proxy is passed by value.
So when you call
return std::exchange(lifeTimes[index], false);
you are passing temporary objecy (Rvalue) to exchange which takes first argument by reference to non-const Lvalue. This is the cause that G++ discards this code. If you want to compile it you can explicitly create Lvalue object of proxy class and pass it:
bool kill(std::size_t index)
{
std::vector<bool>::reference proxyForBit = lifeTimes[index];
return std::exchange(proxyForBit, false);
}