library(lme4)
fm1 <- lmer(Reaction ~ Days + (Days|Subject), data = sleepstudy)
To generate a 95% CI, I can use the predictInterval()
function from the package merTools
.
library(merTools)
head(predictInterval(fm1, level = 0.95, seed = 123, n.sims = 100))
# fit upr lwr
# 1 255.4179 313.8781 184.1400
# 2 273.2944 333.2005 231.3584
# 3 291.8451 342.8701 240.8226
# 4 311.3562 359.2908 250.4980
# 5 330.3671 384.2520 270.7094
# 6 353.4378 409.9307 289.4760
In the documentation, it says about the predictInterval()
function
This function provides a way to capture model uncertainty in predictions from multi-level models fit with lme4. By drawing a sampling distribution for the random and the fixed effects and then estimating the fitted value across that distribution, it is possible to generate a prediction interval for fitted values that includes all variation in the model except for variation in the covariance parameters, theta. This is a much faster alternative than bootstrapping for models fit to medium to large datasets.
My goal is to get all the fitted values instead of the the upper and lower CI i.e. for each row, I need the original n simulations from which these 95% CI are calculated. I checked the argument in the documentation and followed this:
head(predictInterval(fm1, n.sims = 100, returnSims = TRUE, seed = 123, level = 0.95))
# fit upr lwr
# 1 255.4179 313.8781 184.1400
# 2 273.2944 333.2005 231.3584
# 3 291.8451 342.8701 240.8226
# 4 311.3562 359.2908 250.4980
# 5 330.3671 384.2520 270.7094
# 6 353.4378 409.9307 289.4760
Instead of getting the 100 simulations, it still gives me the same output. What is it I am doing wrong here?
A second question though I believe this is more of a StatsExchange one.
"By drawing a sampling distribution for the random and the fixed effects and then."`
How does it draws the sampling distribution if some could explain me?