get all 4 digit combinations out of a list of strings

Question

I have a list consisting of 4 digit strings (ie: list = ['0000', '1111', ...]) now I want to get a list of all possible 4 digit combinations (w/o rep) for each of these items

This is the code I have using permutations (of course it has repetitions but I will post this one since when I tried combinations it worked really bad)

permutes = defaultdict(list)
for item in funo_clean: ## funo_clean is the list with 4 digit numbers
    for permutation in list(itertools.permutations(item)):
        permutes[item].append("".join([str(x) for x in permutation]))
    print ("\n")

Also, I don't want the list of combinations to contain the same number I am using to generate it (i.e: if I am using '8800' to generate it this number should not be in the list)

Thank you!

@JohnGordon Yes, but results were not good (maybe I am not using it right) that's why I posted the code using permutations since it worked better to my goals. — SJPRO
Show us what you tried, and explain why the results weren't what you wanted, and maybe we can help. — John Gordon
only difference is the change in itertools.permutations(item) to itertools.combinations (item, len(item)) but with the permutations code I get, for example: 0647 => [0647, 0674, 0467, ...] ## And all possible permutations with the combinations code I just get one item inside list 0647 => [0647] — SJPRO

endless endless · Accepted Answer · 2018-02-24T18:23:02

set the permutations:

permutes = {}
for item in funo_clean:
    permutes[item] = [''.join(permutation) for permutation in set(itertools.permutations(item))]
    permutes[item].remove(item)
    permutes[item].sort()

get all 4 digit combinations out of a list of strings

1 Answers