embed block anywhere fails at drupal 7

2
votes

It's been a week I have played around with drupal 7. With drupal 6, I used to be able to place (login) block anywhere with this:

  $block = (object) module_invoke($module, 'block', 'view', $delta);
  $block->module = $module;
  $block->delta = $delta;
  return theme('block', $block);

or this:

$block = module_invoke('user', 'block', 'view', 0); 
$vars['login'] = $block['content'];

I changed the delta '0' for Drupal 7:

$block = module_invoke('user', 'block', 'view', 'login'); // I have changed from 0 to 'login' for delta at drupal 7
$vars['login'] = $block['content'];

Both result in Fatal error. Any change that I am not aware of with module_invoke? There is no specific change at http://api.drupal.org/api/drupal/includes--module.inc/function/module_invoke/7

Any hint would be very much appreciated.

3
drupaldrupal-blocks

3 Answers

6
votes

hook_block($op) was changed to hook_block_op() in Drupal 7. Try:

$block = module_invoke('user', 'block_view', 'login');
$vars['login'] = $block['content'];

Or why not use the form directly:

$vars['login'] = drupal_get_form('user_login_block');
2
votes

Drupal 7 keeps all objects now in render arrays until the last output, this allows for a greater degree of control over content. In which case to get a final output use the render() function. Simples.

   <?php
              $block = module_invoke('user', 'block_view', 'login');
              print render($block); 
    ?>
1
votes

Better solution, which respects Drupal theming.

function block_render($module, $block_id) {
  $block = block_load($module, $block_id);
  $block_content = _block_render_blocks(array($block));
  $build = _block_get_renderable_array($block_content);
  $block_rendered = drupal_render($build);
  return $block_rendered;
}