PHP How to use variable from one if statement in another?

Question

I have a little problem.

I'm making form that submits simple article to database and then displays it on admin.php page.

Everything works fine, except image. First i upload it to my server and then I try to add string(path of this image) to database.

However I can't use variable $filepath in second if statement. I can echo it after image upload but can't use in other if.

Could u help me? Thanks in advance.

Here's code:

<?php session_start();
  if (!isset($_SESSION['logged-in']))
  {
    header('Location: index.php');
    exit();
  }
?>
<?php
include('db_connect.php');
if(isset($_POST['btn_upload'])) {
  $filetmp = $_FILES["file_img"]["tmp_name"];
  $filename = $_FILES["file_img"]["name"];
  $filetype = $_FILES["file_img"]["type"];
  $filepath = "photo/".$filename;

  move_uploaded_file($filetmp,$filepath);

  $result = mysqli_query($mysqli, "INSERT INTO upload_img (img_name,img_path,img_type) VALUES ('$filename','$filepath','$filetype')");

  echo '<img src="' . $filepath . '" alt="">';
  echo $filepath;
}

if ( isset($_POST['add']) ) {
  $title = strip_tags($_POST['title']);
  $content = strip_tags($_POST['content']);
  $image = strip_tags($filepath);
  $statement = $mysqli->prepare("INSERT bikes (title,image,content) VALUES (?,?,?)");
  $statement->bind_param("sss",$title,$image,$content);
  $statement->execute();
  $statement->close();
  header('Location: admin.php');
}
?>


<form method="post" action="" class="ui form">
  <div class="required field">
    <label>Title</label>
    <input type="text" name="title" id="title">
  </div>
  <div class="required field">
    <label>Content</label>
    <textarea name="content" id="content" cols="30" rows="10"></textarea>
  </div>
  <div class="required field">
    <label>Image</label>
    <input type="text" name="image" id="image">
  </div>
    <input type="submit" class="ui primary button" id="add" name="add" value="Add article"></input>
</form> 

<form action="addbike.php" method="post" enctype="multipart/form-data">
  <input type="file" name="file_img" />
  <input type="submit" name="btn_upload" value="Upload">  
</form>

Rajdeep Paul Rajdeep Paul · Accepted Answer · 2017-07-02T18:15:39

Since both of your forms work independently(with co-relation with each other whatsoever), $filepath variable won't be accessible in the second if block. However, what you can do is, merge both of your forms together so that all of your form's textual data and image would be accessible in a single submit button.

HTML:

<form method="post" action="" class="ui form" enctype="multipart/form-data">
    <div class="required field">
        <label>Title</label>
        <input type="text" name="title" id="title">
    </div>
    <div class="required field">
        <label>Content</label>
        <textarea name="content" id="content" cols="30" rows="10"></textarea>
    </div>
    <div class="required field">
        <label>Image</label>
        <input type="text" name="image" id="image">
    </div>
    <input type="file" name="file_img" />
    <input type="submit" class="ui primary button" id="add" name="add" value="Add article"></input>
</form>

PHP:

if (isset($_POST['add']) && is_uploaded_file($_FILES["file_img"]["tmp_name"])) {
    $filetmp = $_FILES["file_img"]["tmp_name"];
    $filename = $_FILES["file_img"]["name"];
    $filetype = $_FILES["file_img"]["type"];
    $filepath = "photo/".$filename;

    if(move_uploaded_file($filetmp, $filepath)){
        $result = mysqli_query($mysqli, "INSERT INTO upload_img (img_name,img_path,img_type) VALUES ('$filename','$filepath','$filetype')");
        if($result){
            $title = strip_tags($_POST['title']);
            $content = strip_tags($_POST['content']);
            $image = strip_tags($filepath);
            $statement = $mysqli->prepare("INSERT bikes (title,image,content) VALUES (?,?,?)");
            $statement->bind_param("sss",$title,$image,$content);
            $statement->execute();
            $statement->close();

            header('Location: admin.php');
            exit();
        }else{
            // error handling
        }
    }else{
        // error handling
    }
}

PHP How to use variable from one if statement in another?

2 Answers