Best way to repeat a character in C#

Question

What it's the best way to generate a string of \t's in C#

I am learning C# and experimenting with different ways of saying the same thing.

Tabs(uint t) is a function that returns a string with t amount of \t's

For example Tabs(3) returns "\t\t\t"

Which of these three ways of implementing Tabs(uint numTabs) is best?

Of course that depends on what "best" means.

1. The LINQ version is only two lines, which is nice. But are the calls to Repeat and Aggregate unnecessarily time/resource consuming?

2. The StringBuilder version is very clear but is the StringBuilder class somehow slower?

3. The string version is basic, which means it is easy to understand.

4. Does it not matter at all? Are they all equal?

These are all questions to help me get a better feel for C#.

private string Tabs(uint numTabs)
{
    IEnumerable<string> tabs = Enumerable.Repeat("\t", (int) numTabs);
    return (numTabs > 0) ? tabs.Aggregate((sum, next) => sum + next) : ""; 
}  

private string Tabs(uint numTabs)
{
    StringBuilder sb = new StringBuilder();
    for (uint i = 0; i < numTabs; i++)
        sb.Append("\t");

    return sb.ToString();
}  

private string Tabs(uint numTabs)
{
    string output = "";
    for (uint i = 0; i < numTabs; i++)
    {
        output += '\t';
    }
    return output; 
}

Answer 1

What about this:

string tabs = new String('\t', n);

Where n is the number of times you want to repeat the string.

Or better:

static string Tabs(int n)
{
    return new String('\t', n);
}

Answer 2

string.Concat(Enumerable.Repeat("ab", 2));

Returns

"abab"

And

string.Concat(Enumerable.Repeat("a", 2));

Returns

"aa"

from...

Is there a built-in function to repeat string or char in .net?

Answer 3

In all versions of .NET, you can repeat a string thus:

public static string Repeat(string value, int count)
{
    return new StringBuilder(value.Length * count).Insert(0, value, count).ToString();
}

To repeat a character, new String('\t', count) is your best bet. See the answer by @CMS.

Answer 4

The best version is certainly to use the builtin way:

string Tabs(int len) { return new string('\t', len); }

Of the other solutions, prefer the easiest; only if this is proving too slow, strive for a more efficient solution.

If you use a StringBuilder and know its resulting length in advance, then also use an appropriate constructor, this is much more efficient because it means that only one time-consuming allocation takes place, and no unnecessary copying of data. Nonsense: of course the above code is more efficient.

Answer 5

Extension methods:

public static string Repeat(this string s, int n)
{
    return new String(Enumerable.Range(0, n).SelectMany(x => s).ToArray());
}

public static string Repeat(this char c, int n)
{
    return new String(c, n);
}

Answer 6

What about using extension method?

---

public static class StringExtensions
{
   public static string Repeat(this char chatToRepeat, int repeat) {

       return new string(chatToRepeat,repeat);
   }
   public  static string Repeat(this string stringToRepeat,int repeat)
   {
       var builder = new StringBuilder(repeat*stringToRepeat.Length);
       for (int i = 0; i < repeat; i++) {
           builder.Append(stringToRepeat);
       }
       return builder.ToString();
   }
}

---

You could then write :

Debug.WriteLine('-'.Repeat(100)); // For Chars  
Debug.WriteLine("Hello".Repeat(100)); // For Strings

Note that a performance test of using the stringbuilder version for simple characters instead of strings gives you a major preformance penality : on my computer the difference in mesured performance is 1:20 between: Debug.WriteLine('-'.Repeat(1000000)) //char version and
Debug.WriteLine("-".Repeat(1000000)) //string version

Answer 7

How about this:

//Repeats a character specified number of times
public static string Repeat(char character,int numberOfIterations)
{
    return "".PadLeft(numberOfIterations, character);
}

//Call the Repeat method
Console.WriteLine(Repeat('\t',40));

Answer 8

I know that this question is five years old already but there is a simple way to repeat a string that even works in .Net 2.0.

To repeat a string:

string repeated = new String('+', 3).Replace("+", "Hello, ");

Returns

"Hello, Hello, Hello, "

To repeat a string as an array:

// Two line version.
string repeated = new String('+', 3).Replace("+", "Hello,");
string[] repeatedArray = repeated.Split(',');

// One line version.
string[] repeatedArray = new String('+', 3).Replace("+", "Hello,").Split(',');

Returns

{"Hello", "Hello", "Hello", ""}

Keep it simple.

Answer 9

Let's say you want to repeat '\t' n number of times, you can use;

String.Empty.PadRight(n,'\t')

Answer 10

Your first example which uses Enumerable.Repeat:

private string Tabs(uint numTabs)
{
    IEnumerable<string> tabs = Enumerable.Repeat(
                                 "\t", (int) numTabs);
    return (numTabs > 0) ? 
            tabs.Aggregate((sum, next) => sum + next) : ""; 
} 

can be rewritten more compactly with String.Concat:

private string Tabs(uint numTabs)
{       
    return String.Concat(Enumerable.Repeat("\t", (int) numTabs));
}

Answer 11

Using String.Concat and Enumerable.Repeat which will be less expensive than using String.Join

public static Repeat(this String pattern, int count)
{
    return String.Concat(Enumerable.Repeat(pattern, count));
}

Answer 12

var str = new string(Enumerable.Repeat('\t', numTabs).ToArray());

Answer 13

The answer really depends on the complexity you want. For example, I want to outline all my indents with a vertical bar, so my indent string is determined as follows:

return new string(Enumerable.Range(0, indentSize*indent).Select(
  n => n%4 == 0 ? '|' : ' ').ToArray());

Answer 14

And yet another method

new System.Text.StringBuilder().Append('\t', 100).ToString()

Answer 15

For me is fine:

public static class Utils
{
    public static string LeftZerosFormatter(int zeros, int val)
    {
        string valstr = val.ToString();

        valstr = new string('0', zeros) + valstr;

        return valstr.Substring(valstr.Length - zeros, zeros);
    }
}

Answer 16

You can create an extension method

static class MyExtensions
{
    internal static string Repeat(this char c, int n)
    {
        return new string(c, n);
    }
}

Then you can use it like this

Console.WriteLine('\t'.Repeat(10));

Answer 17

Without a doubt the accepted answer is the best and fastest way to repeat a single character.

Binoj Anthony's answer is a simple and quite efficient way to repeat a string.

However, if you don't mind a little more code, you can use my array fill technique to efficiently create these strings even faster. In my comparison tests, the code below executed in about 35% of the time of the StringBuilder.Insert code.

public static string Repeat(this string value, int count)
{
    var values = new char[count * value.Length];
    values.Fill(value.ToCharArray());
    return new string(values);
}

public static void Fill<T>(this T[] destinationArray, params T[] value)
{
    if (destinationArray == null)
    {
        throw new ArgumentNullException("destinationArray");
    }

    if (value.Length > destinationArray.Length)
    {
        throw new ArgumentException("Length of value array must not be more than length of destination");
    }

    // set the initial array value
    Array.Copy(value, destinationArray, value.Length);

    int copyLength, nextCopyLength;

    for (copyLength = value.Length; (nextCopyLength = copyLength << 1) < destinationArray.Length; copyLength = nextCopyLength)
    {
        Array.Copy(destinationArray, 0, destinationArray, copyLength, copyLength);
    }

    Array.Copy(destinationArray, 0, destinationArray, copyLength, destinationArray.Length - copyLength);
}

For more about this array fill technique, see Fastest way to fill an array with a single value

Answer 18

Try this:

1. Add Microsoft.VisualBasic reference
2. Use: String result = Microsoft.VisualBasic.Strings.StrDup(5,"hi");
3. Let me know if it works for you.

Answer 19

Fill the screen with 6,435 z's $str = [System.Linq.Enumerable]::Repeat([string]::new("z", 143), 45)

$str

Answer 20

Albeit very similar to a previous suggestion, I like to keep it simple and apply the following:

string MyFancyString = "*";
int strLength = 50;
System.Console.WriteLine(MyFancyString.PadRight(strLength, "*");

Standard .Net really,