In a QML application I have an item that is moving around the screen (not rotating). I want to display an indicator that rotates around this item, pointing away from the center of the screen, a fixed distance away from the center of the item.
The following simplified QML application performs this goal, by making the indicator a child of the item, and translating it to the desired location. However, when I try to rotate the indicator (the commented-out code) I cannot find any values for origin.x
and .y
that work. It feels like the QML scene graph calculates X/Y positioning in a way unlike any I've experienced.
import QtQuick 2.7
import QtQuick.Window 2.2
Window {
id: win
visible:true; width:600; height:300
property real padding: 50
property real angle: 0
property real _rads: angle * Math.PI/180
Timer {
interval:50; running:true; repeat:true
onTriggered:win.angle = (new Date/50) % 360
}
Rectangle {
id:object; color:'blue'
width:50; height:width
property real xOffset: Math.cos(_rads)
property real yOffset: Math.sin(_rads)
x: win.width/2 + xOffset * (win.width/2 - padding*2)
y: win.height/2 + yOffset * (win.height/2 - padding*2)
Rectangle {
id:indicator; color:'red'
property real centerOffset: 40
width:10; height:width*2
x: object.width/2 + object.xOffset * centerOffset - width/2
y: object.height/2 + object.yOffset * centerOffset - height/2
// transform: Rotation { origin.x:0; origin.y:0; angle:win.angle }
}
}
}
I've tried making the indicator not be a child of the item. I've tried using Translate
in the transform
stack instead of X/Y positions. All of them result in amusing-but-incorrect rotations.
How can I simply rotate the indicator around it's own center, or otherwise achieve my goal?