I want to convert a raw type vector that contains 2-byte hex numbers (little-endian) into a vector of integers in R (e.g. ff ff -> 0xffff = 65535). One way to do this is to extract even and odd elements from a raw vector, and paste into characters, and then convert into integers as below:
> a <- c(as.raw(255), as.raw(254), as.raw(253), as.raw(252))
> a
[1] ff fe fd fc
> even_elem <- a[seq(2,length(a),2)]
> odd_elem <- a[seq(1,length(a),2)]
> as.integer(paste0("0x", even_elem, odd_elem))
[1] 65279 64765
> c(0xfeff, 0xfcfd)
[1] 65279 64765
The problem is that I want to do this for a vector with >10^8 elements. If I do this with the approach above, it takes minutes. I wanted something more efficient. I thought I could try to use Rcpp to speed this up, so I wrote a piece of cpp code (I'm new to Rcpp/c++),
#include <Rcpp.h>
using namespace Rcpp;
// [[Rcpp::export]]
IntegerVector raw2intC(CharacterVector vec){
int n = vec.size();
int m;
Rcpp::IntegerVector x(n/2);
for (int i = 0; i < n/2; i++) {
std::string h1 = Rcpp::as<std::string>(vec[i*2]);
std::string h2 = Rcpp::as<std::string>(vec[i*2 + 1]);
h2 += h1;
std::stringstream ss;
ss << std::hex << h2;
ss >> m;
x[i] = m;
}
return(x);
}
and an R script.
raw2intR <- function(obj){
val <- raw2intC(obj)
val
}
This Rcpp code worked, and the result of microbenchmark looked encouraging.
> microbenchmark(raw2intR(a), as.integer(paste0("0x", even_elem, odd_elem)))
Unit: microseconds
expr min lq mean median uq max
raw2intR(a) 4.953 5.9130 7.68194 7.4800 8.4585 42.658
as.integer(...) 36.297 40.4275 44.06539 42.8565 44.9420 147.110
> identical(raw2intR(a), as.integer(paste0("0x", even_elem, odd_elem)))
[1] TRUE
However, when tested with a larger vector, there was not much difference in execution time between the R and Rcpp solutions. In fact, the R solution was slightly faster.
> b <- raw(1000000)
> even_elem <- b[seq(2,length(a),2)]
> odd_elem <- b[seq(1,length(a),2)]
> microbenchmark(raw2intR(b), as.integer(paste0("0x", even_elem, odd_elem)), times=10)
Unit: milliseconds
expr min lq mean median uq
raw2intR(b) 309.4139 309.7920 316.6345 313.6219 321.5353
as.integer(...) 274.3523 279.6978 287.5415 288.1744 291.1616
> identical(raw2intR(b), as.integer(paste0("0x", even_elem, odd_elem)))
[1] TRUE
How can this task be sped up? I'm hoping to achieve 10x improvement.
Thanks for your advice.