3
votes

I have videos on my website, and I would like to display them streming with Php and html5.

I tri to follow this tutorial (http://codesamplez.com/programming/php-html5-video-streaming-tutorial) of streaming video creation with php class.

<?php
/**
 * Description of VideoStream
 *
 * @author Rana
 * @link http://codesamplez.com/programming/php-html5-video-streaming-tutorial
 */
class VideoStream
{
    private $path = "";
    private $stream = "";
    private $buffer = 102400;
    private $start  = -1;
    private $end    = -1;
    private $size   = 0;
 
    function __construct($filePath) 
    {
        $this->path = $filePath;
    }
     
    /**
     * Open stream
     */
    private function open()
    {
        if (!($this->stream = fopen($this->path, 'rb'))) {
            die('Could not open stream for reading');
        }
         
    }
     
    /**
     * Set proper header to serve the video content
     */
    private function setHeader()
    {
        ob_get_clean();
        header("Content-Type: video/mp4");
        header("Cache-Control: max-age=2592000, public");
        header("Expires: ".gmdate('D, d M Y H:i:s', time()+2592000) . ' GMT');
        header("Last-Modified: ".gmdate('D, d M Y H:i:s', @filemtime($this->path)) . ' GMT' );
        $this->start = 0;
        $this->size  = filesize($this->path);
        $this->end   = $this->size - 1;
        header("Accept-Ranges: 0-".$this->end);
         
        if (isset($_SERVER['HTTP_RANGE'])) {
  
            $c_start = $this->start;
            $c_end = $this->end;
 
            list(, $range) = explode('=', $_SERVER['HTTP_RANGE'], 2);
            if (strpos($range, ',') !== false) {
                header('HTTP/1.1 416 Requested Range Not Satisfiable');
                header("Content-Range: bytes $this->start-$this->end/$this->size");
                exit;
            }
            if ($range == '-') {
                $c_start = $this->size - substr($range, 1);
            }else{
                $range = explode('-', $range);
                $c_start = $range[0];
                 
                $c_end = (isset($range[1]) && is_numeric($range[1])) ? $range[1] : $c_end;
            }
            $c_end = ($c_end > $this->end) ? $this->end : $c_end;
            if ($c_start > $c_end || $c_start > $this->size - 1 || $c_end >= $this->size) {
                header('HTTP/1.1 416 Requested Range Not Satisfiable');
                header("Content-Range: bytes $this->start-$this->end/$this->size");
                exit;
            }
            $this->start = $c_start;
            $this->end = $c_end;
            $length = $this->end - $this->start + 1;
            fseek($this->stream, $this->start);
            header('HTTP/1.1 206 Partial Content');
            header("Content-Length: ".$length);
            header("Content-Range: bytes $this->start-$this->end/".$this->size);
        }
        else
        {
            header("Content-Length: ".$this->size);
        }  
         
    }
    
    /**
     * close curretly opened stream
     */
    private function end()
    {
        fclose($this->stream);
        exit;
    }
     
    /**
     * perform the streaming of calculated range
     */
    private function stream()
    {
        $i = $this->start;
        set_time_limit(0);
        while(!feof($this->stream) && $i <= $this->end) {
            $bytesToRead = $this->buffer;
            if(($i+$bytesToRead) > $this->end) {
                $bytesToRead = $this->end - $i + 1;
            }
            $data = fread($this->stream, $bytesToRead);
            echo $data;
            flush();
            $i += $bytesToRead;
        }
    }
     
    /**
     * Start streaming video content
     */
    function start()
    {
        $this->open();
        $this->setHeader();
        $this->stream();
        $this->end();
    }
}

So i have two problems :

1 - I am also trying to stream to a player but the video is taking over my whole page how do i make the video is just added to my html5 player.

2 - when I make a url http video (http://video.newsmed.fr/pdv/0616.mp4) that does not work

Thanks to help me solve this problem or suggest me other solutions php.

3

3 Answers

1
votes
  1. I am also trying to stream to a player but the video is taking over my whole >page how do i make the video is just added to my html5 player.

Did you just copy the HTML example without changing a thing? look at the HTML5 example, you will see that theres width="100%", you can change the value to your fit.

2 - when I make a url http video (http://video.newsmed.fr/pdv/0616.mp4) that does >not work

the URL should point to your php code, not the video file path. for example: yourdomain.com/dir/your-php-file.php?video=0616.mp4

try to put your-php-file.php code instead of the videostream.php class on your question.

0
votes

try insert on up to class on top

$stream = new VideoStream("file.mp4 or www//file.mp4");
$stream->start();exit;
0
votes

So here is my html

<a href="#" onclick="play_video(event,`<?PHP echo $video_url?>`)">
<video  style="height:100%;width:100%" controls autoplay >
                    <source src="" type="video/mp4" id='video_player'>   
                </video>

and then use the below jQuery

<script>
    var play_video;
    $(document).ready(function(){

        play_video=function(event,video_url){
            event.preventDefault();
            console.log("play video");
            $('#video_player').attr('src',`index.php?action=play_video&file_path=${video_url}`);
        };

    });
    </script>

and here is your index.php

<?php
include "../util/VideoStream.php";

$action = filter_input(INPUT_POST, 'action');
if ($action === NULL) {
    $action = filter_input(INPUT_GET, 'action');
    if ($action === NULL) {
        $action = 'play_video';
    }
} else {
    $action = trim(strtolower($action));
}

switch ($action) {

    case 'play_video':
        $file_path = filter_input(INPUT_GET, 'file_path');
        $stream = new VideoStream($file_path);
        $stream->start();
        exit;
}
?>