Renaming multiple files in a directory using Python

Question

I'm trying to rename multiple files in a directory using this Python script:

import os
path = '/Users/myName/Desktop/directory'
files = os.listdir(path)
i = 1

for file in files:
    os.rename(file, str(i)+'.jpg')
    i = i+1

When I run this script, I get the following error:

Traceback (most recent call last):
  File "rename.py", line 7, in <module>
    os.rename(file, str(i)+'.jpg')
OSError: [Errno 2] No such file or directory

Why is that? How can I solve this issue?

Thanks.

Answer 1

You are not giving the whole path while renaming, do it like this:

import os
path = '/Users/myName/Desktop/directory'
files = os.listdir(path)


for index, file in enumerate(files):
    os.rename(os.path.join(path, file), os.path.join(path, ''.join([str(index), '.jpg'])))

Edit: Thanks to tavo, The first solution would move the file to the current directory, fixed that.

Answer 2

You have to make this path as a current working directory first. simple enough. rest of the code has no errors.

to make it current working directory:

os.chdir(path)

Answer 3

import os
from os import path
import shutil

Source_Path = 'E:\Binayak\deep_learning\Datasets\Class_2'
Destination = 'E:\Binayak\deep_learning\Datasets\Class_2_Dest'
#dst_folder = os.mkdir(Destination)


def main():
    for count, filename in enumerate(os.listdir(Source_Path)):
        dst =  "Class_2_" + str(count) + ".jpg"

        # rename all the files
        os.rename(os.path.join(Source_Path, filename),  os.path.join(Destination, dst))


# Driver Code
if __name__ == '__main__':
    main()

Answer 4

As per @daniel's comment, os.listdir() returns just the filenames and not the full path of the file. Use os.path.join(path, file) to get the full path and rename that.

import os
path = 'C:\\Users\\Admin\\Desktop\\Jayesh'
files = os.listdir(path)
for file in files:
   os.rename(os.path.join(path, file), os.path.join(path, 'xyz_' + file + '.csv'))

Answer 5

If your files are renaming in random manner then you have to sort the files in the directory first. The given code first sort then rename the files.

import os
import re
path = 'target_folder_directory'
files = os.listdir(path)
files.sort(key=lambda var:[int(x) if x.isdigit() else x for x in re.findall(r'[^0-9]|[0-9]+', var)])
for i, file in enumerate(files):
    os.rename(path + file, path + "{}".format(i)+".jpg")

Answer 6

Just playing with the accepted answer define the path variable and list:

path = "/Your/path/to/folder/"
files = os.listdir(path)

and then loop over that list:

for index, file in enumerate(files):
    #print (file)
    os.rename(path+file, path +'file_' + str(index)+ '.jpg')

or loop over same way with one line as python list comprehension :

[os.rename(path+file, path +'jog_' + str(index)+ '.jpg')  for index, file in enumerate(files)]

I think the first is more readable, in the second the first part of the loop is just the second part of the list comprehension

Answer 7

I wrote a quick and flexible script for renaming files, if you want a working solution without reinventing the wheel.

It renames files in the current directory by passing replacement functions.

Each function specifies a change you want done to all the matching file names. The code will determine the changes that will be done, and displays the differences it would generate using colors, and asks for confirmation to perform the changes.

You can find the source code here, and place it in the folder of which you want to rename files https://gist.github.com/aljgom/81e8e4ca9584b481523271b8725448b8

It works in pycharm, I haven't tested it in other consoles

The interaction will look something like this, after defining a few replacement functions

when it's running the first one, it would show all the differences from the files matching in the directory, and you can confirm to make the replacements or no, like this