581
votes

How can I define a route in my routes.jsx file to capture the __firebase_request_key parameter value from a URL generated by Twitter's single sign on process after the redirect from their servers?

http://localhost:8000/#/signin?_k=v9ifuf&__firebase_request_key=blablabla

I tried with the following routes configuration, but the :redirectParam is not catching the mentioned param:

<Router>
  <Route path="/" component={Main}>
    <Route path="signin" component={SignIn}>
      <Route path=":redirectParam" component={TwitterSsoButton} />
    </Route>
  </Route>
</Router>
30
There's a Github discussion herevsync
unfortunate that the question says "query strings" but is actually asking about "url parameters"SeanMC
query strings "?var1=val&var2=val2" , url paramters: "/photos/:companyiD/new"Maddocks

30 Answers

637
votes

React Router v4 and React Router v5, generic

React Router v4 does not parse the query for you any more, but you can only access it via this.props.location.search (or useLocation, see below). For reasons see nbeuchat's answer.

E.g. with qs library imported as qs you could do

qs.parse(this.props.location.search, { ignoreQueryPrefix: true }).__firebase_request_key

Another library would be query-string. See this answer for some more ideas on parsing the search string. If you do not need IE-compatibility you can also use

new URLSearchParams(this.props.location.search).get("__firebase_request_key")

For functional components you would replace this.props.location with the hook useLocation. Note, you could use window.location.search, but this won't allow to trigger React rendering on changes. If your (non-functional) component is not a direct child of a Switch you need to use withRouter to access any of the router provided props.

React Router v3

React Router already parses the location for you and passes it to your RouteComponent as props. You can access the query (after ? in the url) part via

this.props.location.query.__firebase_request_key

If you are looking for the path parameter values, separated with a colon (:) inside the router, these are accessible via

this.props.match.params.redirectParam

This applies to late React Router v3 versions (not sure which). Older router versions were reported to use this.props.params.redirectParam.

General

nizam.sp's suggestion to do

console.log(this.props)

will be helpful in any case.

232
votes

React Router v4

Using component

<Route path="/users/:id" component={UserPage}/> 
this.props.match.params.id

The component is automatically rendered with the route props.


Using render

<Route path="/users/:id" render={(props) => <UserPage {...props} />}/> 
this.props.match.params.id

Route props are passed to the render function.

178
votes

React Router v3

With React Router v3, you can get query-string from this.props.location.search (?qs1=naisarg&qs2=parmar). For example, with let params = queryString.parse(this.props.location.search), would give { qs1 : 'naisarg', qs2 : 'parmar'}

React Router v4

With React Router v4, the this.props.location.query does not exist anymore. You need to use this.props.location.search instead and parse the query parameters either by yourself or using an existing package such as query-string.

Example

Here is a minimal example using React Router v4 and the query-string library.

import { withRouter } from 'react-router-dom';
import queryString from 'query-string';
    
class ActivateAccount extends Component{
    someFunction(){
        let params = queryString.parse(this.props.location.search)
        ...
    }
    ...
}
export default withRouter(ActivateAccount);

Rational

The React Router's team rational for removing the query property is:

There are a number of popular packages that do query string parsing/stringifying slightly differently, and each of these differences might be the "correct" way for some users and "incorrect" for others. If React Router picked the "right" one, it would only be right for some people. Then, it would need to add a way for other users to substitute in their preferred query parsing package. There is no internal use of the search string by React Router that requires it to parse the key-value pairs, so it doesn't have a need to pick which one of these should be "right".

[...]

The approach being taken for 4.0 is to strip out all the "batteries included" kind of features and get back to just basic routing. If you need query string parsing or async loading or Redux integration or something else very specific, then you can add that in with a library specifically for your use case. Less cruft is packed in that you don't need and you can customize things to your specific preferences and needs.

You can find the full discussion on GitHub.

117
votes

As far as I know there are three methods you can do that.

1.use regular expression to get query string.

2.you can use the browser api. image the current url is like this:

http://www.google.com.au?token=123

we just want to get 123;

First

 const query = new URLSearchParams(this.props.location.search);

Then

const token = query.get('token')
console.log(token)//123

3. use a third library called 'query-string'. First install it

npm i query-string

Then import it to the current javascript file:

 import queryString from 'query-string'

Next step is to get 'token' in the current url, do the following:

const value=queryString.parse(this.props.location.search);
const token=value.token;
console.log('token',token)//123

Hope it helps.

Updated on 25/02/2019

  1. if the current url looks like the following:

http://www.google.com.au?app=home&act=article&aid=160990

we define a function to get the parameters:

function getQueryVariable(variable)
{
        var query = window.location.search.substring(1);
        console.log(query)//"app=article&act=news_content&aid=160990"
        var vars = query.split("&");
        console.log(vars) //[ 'app=article', 'act=news_content', 'aid=160990' ]
        for (var i=0;i<vars.length;i++) {
                    var pair = vars[i].split("=");
                    console.log(pair)//[ 'app', 'article' ][ 'act', 'news_content' ][ 'aid', '160990' ] 
        if(pair[0] == variable){return pair[1];}
         }
         return(false);
}

We can get 'aid' by :

getQueryVariable('aid') //160990
79
votes

React Router v4 no longer has the props.location.query object (see github discussion). So the accepted answer will not work for newer projects.

A solution for v4 is to use an outside library query-string to parse the props.location.search

const qs = require('query-string');
//or
import * as qs from 'query-string';

console.log(location.search);
//=> '?foo=bar'

const parsed = qs.parse(location.search);
console.log(parsed);
//=> {foo: 'bar'}
63
votes

When using React hooks there is no access to access to this.props.location. To capture url parameters use window object.

const search = window.location.search;
const params = new URLSearchParams(search);
const foo = params.get('bar');
43
votes

React Router 5.1+

5.1 introduced various hooks like useLocation and useParams that could be of use here.

Example:

<Route path="/test/:slug" component={Dashboard} />

Then if we visited say

http://localhost:3000/test/signin?_k=v9ifuf&__firebase_request_key=blablabla

You could retrieve it like

import { useLocation } from 'react-router';
import queryString from 'query-string';

const Dashboard: React.FC = React.memo((props) => {
    const location = useLocation();

    console.log(queryString.parse(location.search));

    // {__firebase_request_key: "blablabla", _k: "v9ifuf"}

    ...

    return <p>Example</p>;
}
32
votes

With this one-liner, you can use it anywhere in both React Hook and React Class Component with plain JavaScript.

https://www.hunterisgod.com/?city=Leipzig

let city = (new URLSearchParams(window.location.search)).get("city")
30
votes

React Router v4

const urlParams = new URLSearchParams(this.props.location.search)
const key = urlParams.get('__firebase_request_key')

Please note that it is currently experimental.

Check browser compatibility here: https://developer.mozilla.org/en-US/docs/Web/API/URLSearchParams/URLSearchParams#Browser_compatibility

20
votes

you can check the react-router, in simple,you can use the code to get query parameter as long as you defined in your router:

this.props.params.userId
18
votes

If your Router is like this

<Route exact path="/category/:id" component={ProductList}/>

You will get that id like this

this.props.match.params.id
13
votes

If you aren't getting the this.props... you were expecting based on the other answers, you may need to use withRouter (docs v4):

import React from 'react'
import PropTypes from 'prop-types'
import { withRouter } from 'react-router'

// A simple component that shows the pathname of the current location
class ShowTheLocation extends React.Component {
  static propTypes = {
    match: PropTypes.object.isRequired,
    location: PropTypes.object.isRequired,
    history: PropTypes.object.isRequired
  }

  render() {
    const { match, location, history } = this.props

    return (
      <div>You are now at {location.pathname}</div>
    )
  }
}

// Create a new component that is "connected" (to borrow redux terminology) to the router.  
const TwitterSsoButton = withRouter(ShowTheLocation)  

// This gets around shouldComponentUpdate
withRouter(connect(...)(MyComponent))

// This does not
connect(...)(withRouter(MyComponent))
12
votes

Say there is a url as follows

http://localhost:3000/callback?code=6c3c9b39-de2f-3bf4-a542-3e77a64d3341

If we want to extract the code from that URL, below method will work.

const authResult = new URLSearchParams(window.location.search); 
const code = authResult.get('code')
11
votes

I had a hard time solving this issue. If none of the above work you can try this instead. I am using the create-react-app

Requirements

react-router-dom": "^4.3.1"

Solution

At the location where router is specified

<Route path="some/path" ..../>

Add the parameter name that you would want to pass in like this

<Route path="some/path/:id" .../>

At the page where you are rendering some/path you can specify this to view the parameter name call id like this

componentDidMount(){
  console.log(this.props);
  console.log(this.props.match.params.id);
}

At the end where you export default

export default withRouter(Component);

Remember to include import

import { withRouter } from 'react-router-dom'

When console.log(this.props) you would be able what has been passed down. Have fun!

11
votes

do it all in one line without 3rd party libraries or complicated solutions. Here is how

let myVariable = new URLSearchParams(history.location.search).get('business');

the only thing you need to change is the word 'business' with your own param name.

example url.com?business=hello

the result of myVariable will be hello

11
votes

Not the react way, but I beleive that this one-line function can help you :)

const getQueryParams = () => window.location.search.replace('?', '').split('&').reduce((r,e) => (r[e.split('=')[0]] = decodeURIComponent(e.split('=')[1]), r), {});

Example:
URL:  ...?a=1&b=c&d=test
Code:  

>  getQueryParams()
<  {
     a: "1",
     b: "c",
     d: "test"
   }
8
votes

React router from v4 onwards no longer gives you the query params directly in its location object. The reason being

There are a number of popular packages that do query string parsing/stringifying slightly differently, and each of these differences might be the "correct" way for some users and "incorrect" for others. If React Router picked the "right" one, it would only be right for some people. Then, it would need to add a way for other users to substitute in their preferred query parsing package. There is no internal use of the search string by React Router that requires it to parse the key-value pairs, so it doesn't have a need to pick which one of these should be "right".

Having included that, It would just make more sense to just parse location.search in your view components that are expecting a query object.

You can do this generically by overriding the withRouter from react-router like

customWithRouter.js

import { compose, withPropsOnChange } from 'recompose';
import { withRouter } from 'react-router';
import queryString from 'query-string';

const propsWithQuery = withPropsOnChange(
    ['location', 'match'],
    ({ location, match }) => {
        return {
            location: {
                ...location,
                query: queryString.parse(location.search)
            },
            match
        };
    }
);

export default compose(withRouter, propsWithQuery)
8
votes

React Router v5.1 introduced hooks:

For

<Route path="/posts/:id">
  <BlogPost />
</Route>

You can access params / id with hook:

const { id } = useParams();

More here.

7
votes
componentDidMount(){
    //http://localhost:3000/service/anas
    //<Route path="/service/:serviceName" component={Service} />
    const {params} =this.props.match;
    this.setState({ 
        title: params.serviceName ,
        content: data.Content
    })
}
7
votes

Maybe a bit late but this react hook can help you get/set values in URL query: https://github.com/rudyhuynh/use-url-search-params (written by me).

It works with or without react-router. Below is code sample in your case:

import React from "react";
import { useUrlSearchParams } from "use-url-search-params";

const MyComponent = () => {
  const [params, setParams] = useUrlSearchParams()
  return (
    <div>
      __firebase_request_key: {params.__firebase_request_key}
    </div>
  )
}
7
votes
function useQueryParams() {
    const params = new URLSearchParams(
      window ? window.location.search : {}
    );

    return new Proxy(params, {
        get(target, prop) {
            return target.get(prop)
        },
    });
}

React hooks are amazing

If your url looks like /users?page=2&count=10&fields=name,email,phone

const { page, fields, count } = useQueryParams();

console.log(params)
6
votes

this.props.params.your_param_name will work.

This is the way to get the params from your query string.
Please do console.log(this.props); to explore all the possibilities.

5
votes

You could create simple hook for extracting search params from current location:

import React from 'react';
import { useLocation } from 'react-router-dom';

export function useSearchParams<ParamNames extends string[]>(...parameterNames: ParamNames): Record<ParamNames[number], string | null> {
    const { search } = useLocation();
    return React.useMemo(() => { // recalculate only when 'search' or arguments changed
        const searchParams = new URLSearchParams(search);
        return parameterNames.reduce((accumulator, parameterName: ParamNames[number]) => {
            accumulator[ parameterName ] = searchParams.get(parameterName);
            return accumulator;
        }, {} as Record<ParamNames[number], string | null>);
    }, [ search, parameterNames.join(',') ]); // join for sake of reducing array of strings to simple, comparable string
}

then you could use it inside your functional component like this:

// current url: http://localhost:8000/#/signin?_k=v9ifuf&__firebase_request_key=blablabla
const { __firebase_request_key } = useSearchParams('__firebase_request_key');
// current url: http://localhost:3000/home?b=value
const searchParams = useSearchParameters('a', 'b'); // {a: null, b: 'value'}
5
votes

Actually there is no need to use 3rd party library. We can make with pure JavaScript.

consider the following URL:

https://example.com?yourParamName=yourParamValue

Now we get:

const url = new URL(window.location.href);
const yourParamName = url.searchParams.get('yourParamName');

In short

const yourParamName = new URL(window.location.href).searchParams.get('yourParamName')

Another Smart Solution (Recommended)

const params = new URLSearchParams(window.location.search);
const yourParamName = params.get('yourParamName');

In short

const yourParamName = new URLSearchParams(window.location.search).get('yourParamName')

NOTE:

use "getAll" instead of "get" for Params having multiple value

https://example.com?yourParamName[]=yourParamValue1&yourParamName[]=yourParamValue2

const yourParamName = new URLSearchParams(window.location.search).getAll('yourParamName[]')

Result will be like:

["yourParamValue1", "yourParamValue2"]
4
votes

In the component where you need to access the parameters you can use

this.props.location.state.from.search

which will reveal the whole query string (everything after the ? sign)

4
votes

Maybe someone can help clarify why but if you're attempting to hit props to find location from a fresh install of Create React App on the App.js page you get:

TypeError: Cannot read property 'search' of undefined

Even though I have App.js as the home route:

<Route exact path='/' render={props => (

On App.js only, using window.location worked for me:

import queryString from 'query-string';
...
const queryStringParams = queryString.parse(window.location.search);
3
votes

I used an external package called query-string to parse url parameter like so.

import React, {Component} from 'react'
import { parse } from 'query-string';

resetPass() {
    const {password} = this.state;
    this.setState({fetching: true, error: undefined});
    const query = parse(location.search);
    return fetch(settings.urls.update_password, {
        method: 'POST',
        headers: {'Content-Type': 'application/json', 'Authorization': query.token},
        mode: 'cors',
        body: JSON.stringify({password})
    })
        .then(response=>response.json())
        .then(json=>{
            if (json.error)
                throw Error(json.error.message || 'Unknown fetch error');
            this.setState({fetching: false, error: undefined, changePassword: true});
        })
        .catch(error=>this.setState({fetching: false, error: error.message}));
}
3
votes

When you work with react route dom then will empty object with for match but if you do the following code then it will for es6 component as well as it works directly for function component

import { Switch, Route, Link } from "react-router-dom";

<Route path="/profile" exact component={SelectProfile} />
<Route
  path="/profile/:profileId"
  render={props => {
    return <Profile {...props} loading={this.state.loading} />;
  }}
/>
</Switch>
</div>

This way you can get props and match params and profile id

This worked for me after a lot of research on es6 component.

3
votes

in typescript, see snippet below for example:

const getQueryParams = (s?: string): Map<string, string> => {
  if (!s || typeof s !== 'string' || s.length < 2) {
    return new Map();
  }

  const a: [string, string][] = s
    .substr(1) // remove `?`
    .split('&') // split by `&`
    .map(x => {
      const a = x.split('=');
      return [a[0], a[1]];
    }); // split by `=`

  return new Map(a);
};

in react with react-router-dom, you can do

const {useLocation} from 'react-router-dom';
const s = useLocation().search;
const m = getQueryParams(s);

see example below

// below is the transpiled and minified ts functions from above
const getQueryParams=t=>{if(!t||"string"!=typeof t||t.length<2)return new Map;const r=t.substr(1).split("&").map(t=>{const r=t.split("=");return[r[0],r[1]]});return new Map(r)};
   
// an example query string
const s = '?arg1=value1&arg2=value2'

const m = getQueryParams(s)
console.log(m.get('arg1'))
console.log(m.get('arg2'))
console.log(m.get('arg3')) // does not exist, returns undefined
2
votes

In React Router v4 only withRoute is correct way

You can get access to the history object’s properties and the closest 's match via the withRouter higher-order component. withRouter will pass updated match, location, and history props to the wrapped component whenever it renders.

import React from 'react'
import PropTypes from 'prop-types'
import { withRouter } from 'react-router'

// A simple component that shows the pathname of the current location
class ShowTheLocation extends React.Component {
  static propTypes = {
    match: PropTypes.object.isRequired,
    location: PropTypes.object.isRequired,
    history: PropTypes.object.isRequired
  }

  render() {
    const { match, location, history } = this.props

    return (
      <div>You are now at {location.pathname}</div>
    )
  }
}

// Create a new component that is "connected" (to borrow redux
// terminology) to the router.
const ShowTheLocationWithRouter = withRouter(ShowTheLocation)

https://reacttraining.com/react-router/web/api/withRouter