How to get first N number of elements from an array

Question

I am working with Javascript(ES6) /FaceBook react and trying to get the first 3 elements of an array that varies in size. I would like do the equivalent of Linq take(n).

In my Jsx file I have the following:

var items = list.map(i => {
  return (
    <myview item={i} key={i.id} />
  );
});

Then to get the first 3 items I tried

  var map = new Map(list);
    map.size = 3;
    var items = map(i => {
      return (<SpotlightLandingGlobalInboxItem item={i} key={i.id} />);
    });

This didn't work as map doesn't have a set function.

Can you please help?

Answer 1

I believe what you're looking for is:

// ...inside the render() function

var size = 3;
var items = list.slice(0, size).map(i => {
    return <myview item={i} key={i.id} />
}

return (
  <div>
    {items}
  </div>   
)

Answer 2

To get the first n elements of an array, use

const slicedArray = array.slice(0, n);

Answer 3

arr.length = n

This might be surprising but length property of an array is not only used to get number of array elements but it's also writable and can be used to set array's length MDN link. This will mutate the array.

If you don't care about immutability or don't want to allocate memory i.e. for a game this will be the fastest way.

to empty an array

arr.length = 0

Answer 4

You can filter using index of array.

var months = ['Jan', 'March', 'April', 'June'];
months = months.filter((month,idx) => idx < 2)
console.log(months);

Answer 5

Do not try doing that using a map function. Map function should be used to map values from one thing to other. When the number of input and output match.

In this case use filter function which is also available on the array. Filter function is used when you want to selectively take values maching certain criteria. Then you can write your code like

var items = list
             .filter((i, index) => (index < 3))
             .map((i, index) => {
                   return (
                     <myview item={i} key={i.id} />
                   );
              });

Answer 6

The following worked for me.

array.slice( where_to_start_deleting, array.length )

Here is an example

var fruits = ["Banana", "Orange", "Apple", "Mango"];
fruits.slice(2, fruits.length);
//Banana,Orange  ->These first two we get as resultant

Answer 7

Using a simple example:

var letters = ["a", "b", "c", "d"];
var letters_02 = letters.slice(0, 2);
console.log(letters_02)

Output: ["a", "b"]

var letters_12 = letters.slice(1, 2);
console.log(letters_12)

Output: ["b"]

Note: slice provides only a shallow copy and DOES NOT modify the original array.

Answer 8

With lodash, take function, you can achieve this by following:

_.take([1, 2, 3]);
// => [1]
 
_.take([1, 2, 3], 2);
// => [1, 2]
 
_.take([1, 2, 3], 5);
// => [1, 2, 3]
 
_.take([1, 2, 3], 0);
// => []

Answer 9

With LInQer you can do:

Enumerable.from(list).take(3).toArray();

Answer 10

Just try this to get first n elements from list:

const slicedList = list.slice(0, n);

Example:

const list = [1,2,3,4,5]
console.log(list.slice(0, 3)) // Should return [1,2,3] 
console.log(list.slice(0, 10)) // Returns [1,2,3,4,5] since this is all we have in 1st 10 elements