python - Unpack list to variables

Question

I have a list:

row = ["Title", "url", 33, "title2", "keyword"]

Is there a more pythonic way to unpack this values like:

title, url, price, title2, keyword = row[0], row[1], row[2], row[3], row[4]

Answer 1

Something like this ?

>>> row = ["Title", "url", 33, "title2", "keyword"]
>>> title, url, price, title2, keyword = row

Also and for the record, note that your example will fail with an IndexError (Python's lists are zero-based).

EDIT : the above note was written before the OP example was fixed...

Answer 2

Also if you need only few first variables, in Python 3 you can use:

row = ["Title", "url", 33, "title2", "keyword"]
title, url, *_ = row

It's a nice way to extract few first values without using explicit indices

Answer 3

In fact, python automatically unpacks containers when variables are separated by commas. This assigns each element in row to the variables on the left:

title, url, price, title2, keyword = row

After this assignment, title has the value of "Title", price has the value of 33, etc.

Answer 4

You could also unpack it easily to a class or namedtuple:

from collections import namedtuple

row = ["Title", "url", 33, "title2", "keyword"]

Entry = namedtuple("Entry", "title url price title2 keyword")
new_entry  = Entry(*row)
print(new_entry.title) # Title

Answer 5

Another way simple tuple/list packing - Note ',' after *row

*row, = ["Title", "url", 33, "title2", "keyword"]  # creates a tuple of row elements
title, url, price, title2, keyword = row  # list unpacking unpacked here
for i in range(len(row)):
    print(row[i])
print()
print(title)

Title
url
33
title2
keyword

Title