Comparing elements of two lists in jython

Question

I am EXTREMELY new to coding and have no idea how to efficiently compare the elements in two lists/arrays in jython. I have one list of length 5 and another of length 0 to infinity. Elements are not in any kind of order. I want to find the difference between each element of the two lists. So if list1 = [30, 20, 50, 66, 2] and list2 = [6, 50, 90], I should have 15 outputs (len(list1)*len(list2)). I know how to go through and compare each element one by one, but I need an efficient way to compare all elements at once. I think I need some kind of iterator function, but have no idea how to implement it.

Answer 1

This tutorial on control flows might be helpful.

list1 = [30, 20, 50, 66, 2]
list2 = [6, 50, 90]

result = []

for item1 in list1:
    for item2 in list2:
        result.append( item1 - item2 )

print result
#[24, -20, -60, 14, -30, -70, 44, 0, -40, 60, 16, -24, -4, -48, -88]

Answer 2

I find list comprehensions easier to read:

from pprint import pprint
list1 = [30, 20, 50, 66, 2]
list2 = [6, 50, 90]

result = [[ one * two for one in list1] for two in list2]
pprint(result)

Answer 3

Another option here with list comprehensions:

compare one by one if they are equal

print [x==y for x in list2 for y in list1 ]

output:

[False, False, False, False, False, False, False, True, False, False, False, False, False, False, False]

and print matching:

print [ x for x in list2 for y in list1 if x==y ]

output:

[50]

Answer 4

I guess this should do:

list_a=[30,20,50,66,2]
list_b=[6,50,90]

for i in list_a:
    for j in list_b:
        #compare here, i am assuming a differnce is the comparision you want to do
        print i-j