Solution
Simply put a semicolon (;
) after console.log(
…)
.
Explanation
The error is easily reproducible like this:
console.log()
(function(){})
It’s trying to pass function(){}
as an argument to the return value of console.log()
which itself is not a function but actually undefined
(check typeof console.log();
). This is because JavaScript interprets this as console.log()(function(){})
. console.log
however is a function.
If you didn’t have the console
object you’d see
ReferenceError: console is not defined
If you had the console
object but not the log
method you’d see
TypeError: console.log is not a function
What you have, however, is
TypeError: console.log(...) is not a function
Note the (...)
after the function name. With those it’s referring to the return value of the function.
The line break doesn’t separate these two expressions as separate statements because of JavaScript’s rules for automatic semicolon insertion (ASI).
Respect the ;
All these code snippets result in all sorts of unexpected errors if no semicolons are present:
console.log() // As covered before
() // TypeError: console.log(...) is not a function
console.log() // Accessing property 0 of property 1 of the return value…
[1][0] // TypeError: console.log(...) is undefined
console.log() // Like undefined-3
-3 // NaN
let a, b;
const array = Array.from({ length: 2 })
// Now, let’s use destructuring:
[a, b] = array; // ReferenceError: can't access lexical declaration 'array' before initialization
let a, b;
const array = Array.from({ length: 2 }).fill(1),
array2 = Array.from({ length: 2 })
// Now, let’s use destructuring. Attempt to get the two 1’s from `array` as `a` and `b`:
[a, b] = array;
console.log(a, b); // undefined undefined
Another Example
You see the (...)
oftentimes with the use of chained methods or chained property accessors:
string.match(/someRegEx/)[0]
If that RegEx isn’t found, the method will return null
and the property accessor on null
will cause a TypeError: string.match(...) is null
— the return value is null
. In the case of console.log(...)
the return value was undefined
.