Get String in YYYYMMDD format from JS date object?

Question

I'm trying to use JS to turn a date object into a string in YYYYMMDD format. Is there an easier way than concatenating Date.getYear(), Date.getMonth(), and Date.getDay()?

Answer 1

Altered piece of code I often use:

Date.prototype.yyyymmdd = function() {
  var mm = this.getMonth() + 1; // getMonth() is zero-based
  var dd = this.getDate();

  return [this.getFullYear(),
          (mm>9 ? '' : '0') + mm,
          (dd>9 ? '' : '0') + dd
         ].join('');
};

var date = new Date();
date.yyyymmdd();

Answer 2

I didn't like adding to the prototype. An alternative would be:

var rightNow = new Date();
var res = rightNow.toISOString().slice(0,10).replace(/-/g,"");

<!-- Next line is for code snippet output only -->
document.body.innerHTML += res;

Answer 3

You can use the toISOString function :

var today = new Date();
today.toISOString().substring(0, 10);

It will give you a "yyyy-mm-dd" format.

Answer 4

Moment.js could be your friend

var date = new Date();
var formattedDate = moment(date).format('YYYYMMDD');

Answer 5

new Date('Jun 5 2016').
  toLocaleString('en-us', {year: 'numeric', month: '2-digit', day: '2-digit'}).
  replace(/(\d+)\/(\d+)\/(\d+)/, '$3-$1-$2');

// => '2016-06-05'

Answer 6

This is a single line of code that you can use to create a YYYY-MM-DD string of today's date.

var d = new Date().toISOString().slice(0,10);

Answer 7

If you don't need a pure JS solution, you can use jQuery UI to do the job like this :

$.datepicker.formatDate('yymmdd', new Date());

I usually don't like to import too much libraries. But jQuery UI is so useful, you will probably use it somewhere else in your project.

Visit http://api.jqueryui.com/datepicker/ for more examples

Answer 8

I don't like modifying native objects, and I think multiplication is clearer than the string padding the accepted solution.

function yyyymmdd(dateIn) {
  var yyyy = dateIn.getFullYear();
  var mm = dateIn.getMonth() + 1; // getMonth() is zero-based
  var dd = dateIn.getDate();
  return String(10000 * yyyy + 100 * mm + dd); // Leading zeros for mm and dd
}

var today = new Date();
console.log(yyyymmdd(today));

Fiddle: http://jsfiddle.net/gbdarren/Ew7Y4/

Answer 9

In addition to o-o's answer I'd like to recommend separating logic operations from the return and put them as ternaries in the variables instead.

Also, use concat() to ensure safe concatenation of variables

Date.prototype.yyyymmdd = function() {
  var yyyy = this.getFullYear();
  var mm = this.getMonth() < 9 ? "0" + (this.getMonth() + 1) : (this.getMonth() + 1); // getMonth() is zero-based
  var dd = this.getDate() < 10 ? "0" + this.getDate() : this.getDate();
  return "".concat(yyyy).concat(mm).concat(dd);
};

Date.prototype.yyyymmddhhmm = function() {
  var yyyymmdd = this.yyyymmdd();
  var hh = this.getHours() < 10 ? "0" + this.getHours() : this.getHours();
  var min = this.getMinutes() < 10 ? "0" + this.getMinutes() : this.getMinutes();
  return "".concat(yyyymmdd).concat(hh).concat(min);
};

Date.prototype.yyyymmddhhmmss = function() {
  var yyyymmddhhmm = this.yyyymmddhhmm();
  var ss = this.getSeconds() < 10 ? "0" + this.getSeconds() : this.getSeconds();
  return "".concat(yyyymmddhhmm).concat(ss);
};

var d = new Date();
document.getElementById("a").innerHTML = d.yyyymmdd();
document.getElementById("b").innerHTML = d.yyyymmddhhmm();
document.getElementById("c").innerHTML = d.yyyymmddhhmmss();

<div>
  yyyymmdd: <span id="a"></span>
</div>
<div>
  yyyymmddhhmm: <span id="b"></span>
</div>
<div>
  yyyymmddhhmmss: <span id="c"></span>
</div>

Answer 10

Plain JS (ES5) solution without any possible date jump issues caused by Date.toISOString() printing in UTC:

var now = new Date();
var todayUTC = new Date(Date.UTC(now.getFullYear(), now.getMonth(), now.getDate()));
return todayUTC.toISOString().slice(0, 10).replace(/-/g, '');

This in response to @weberste's comment on @Pierre Guilbert's answer.

Answer 11

Local time:

var date = new Date();
date = date.toJSON().slice(0, 10);

UTC time:

var date = new Date().toISOString();
date = date.substring(0, 10);

date will print 2020-06-15 today as i write this.

toISOString() method returns the date with the ISO standard which is YYYY-MM-DDTHH:mm:ss.sssZ

The code takes the first 10 characters that we need for a YYYY-MM-DD format.

If you want format without '-' use:

var date = new Date();
date = date.toJSON().slice(0, 10).split`-`.join``;

In .join`` you can add space, dots or whatever you'd like.

Answer 12

// UTC/GMT 0
document.write('UTC/GMT 0: ' + (new Date()).toISOString().slice(0, 19).replace(/[^0-9]/g, "")); // 20150812013509

// Client local time
document.write('<br/>Local time: ' + (new Date(Date.now()-(new Date()).getTimezoneOffset() * 60000)).toISOString().slice(0, 19).replace(/[^0-9]/g, "")); // 20150812113509

Answer 13

Another way is to use toLocaleDateString with a locale that has a big-endian date format standard, such as Sweden, Lithuania, Hungary, South Korea, ...:

date.toLocaleDateString('se')

To remove the delimiters (-) is just a matter of replacing the non-digits:

console.log( new Date().toLocaleDateString('se').replace(/\D/g, '') );

This does not have the potential error you can get with UTC date formats: the UTC date may be one day off compared to the date in the local time zone.

Answer 14

var someDate = new Date();
var dateFormated = someDate.toISOString().substr(0,10);

console.log(dateFormated);

Answer 15

dateformat is a very used package.

How to use:

Download and install dateformat from NPM. Require it in your module:

const dateFormat = require('dateformat');

and then just format your stuff:

const myYYYYmmddDate = dateformat(new Date(), 'yyyy-mm-dd');

Answer 16

You can simply use This one line code to get date in year

var date = new Date().getFullYear() + "-" + (parseInt(new Date().getMonth()) + 1) + "-" + new Date().getDate();

Answer 17

This guy here => http://blog.stevenlevithan.com/archives/date-time-format wrote a format() function for the Javascript's Date object, so it can be used with familiar literal formats.

If you need full featured Date formatting in your app's Javascript, use it. Otherwise if what you want to do is a one off, then concatenating getYear(), getMonth(), getDay() is probably easiest.

Answer 18

Shortest

.toJSON().slice(0,10).split`-`.join``;

let d = new Date();

let s = d.toJSON().slice(0,10).split`-`.join``;

console.log(s);

Answer 19

Little bit simplified version for the most popular answer in this thread https://stackoverflow.com/a/3067896/5437379 :

function toYYYYMMDD(d) {
    var yyyy = d.getFullYear().toString();
    var mm = (d.getMonth() + 101).toString().slice(-2);
    var dd = (d.getDate() + 100).toString().slice(-2);
    return yyyy + mm + dd;
}

Answer 20

This code is fix to Pierre Guilbert's answer:

(it works even after 10000 years)

YYYYMMDD=new Date().toISOString().slice(0,new Date().toISOString().indexOf("T")).replace(/-/g,"")

Answer 21

How about Day.js?

It's only 2KB, and you can also dayjs().format('YYYY-MM-DD').

https://github.com/iamkun/dayjs

Answer 22

It seems that mootools provides Date().format(): https://mootools.net/more/docs/1.6.0/Types/Date

I'm not sure if it worth including just for this particular task though.

Answer 23

Use padStart:

Date.prototype.yyyymmdd = function() {
    return [
        this.getFullYear(),
        (this.getMonth()+1).toString().padStart(2, '0'), // getMonth() is zero-based
        this.getDate().toString().padStart(2, '0')
    ].join('-');
};

Answer 24

[day,,month,,year]= Intl.DateTimeFormat(undefined, { year: 'numeric', month: '2-digit', day: '2-digit' }).formatToParts(new Date()),year.value+month.value+day.value

or

new Date().toJSON().slice(0,10).replace(/\/|-/g,'')

Answer 25

Working from @o-o's answer this will give you back the string of the date according to a format string. You can easily add a 2 digit year regex for the year & milliseconds and the such if you need them.

Date.prototype.getFromFormat = function(format) {
    var yyyy = this.getFullYear().toString();
    format = format.replace(/yyyy/g, yyyy)
    var mm = (this.getMonth()+1).toString(); 
    format = format.replace(/mm/g, (mm[1]?mm:"0"+mm[0]));
    var dd  = this.getDate().toString();
    format = format.replace(/dd/g, (dd[1]?dd:"0"+dd[0]));
    var hh = this.getHours().toString();
    format = format.replace(/hh/g, (hh[1]?hh:"0"+hh[0]));
    var ii = this.getMinutes().toString();
    format = format.replace(/ii/g, (ii[1]?ii:"0"+ii[0]));
    var ss  = this.getSeconds().toString();
    format = format.replace(/ss/g, (ss[1]?ss:"0"+ss[0]));
    return format;
};

d = new Date();
var date = d.getFromFormat('yyyy-mm-dd hh:ii:ss');
alert(date);

I don't know how efficient that is however, especially perf wise because it uses a lot of regex. It could probably use some work I do not master pure js.

NB: I've kept the predefined class definition but you might wanna put that in a function or a custom class as per best practices.

Answer 26

I usually use the code below when I need to do this.

var date = new Date($.now());
var dateString = (date.getFullYear() + '-'
    + ('0' + (date.getMonth() + 1)).slice(-2)
    + '-' + ('0' + (date.getDate())).slice(-2));
console.log(dateString); //Will print "2015-09-18" when this comment was written

To explain, .slice(-2) gives us the last two characters of the string.

So no matter what, we can add "0" to the day or month, and just ask for the last two since those are always the two we want.

So if the MyDate.getMonth() returns 9, it will be:

("0" + "9") // Giving us "09"

so adding .slice(-2) on that gives us the last two characters which is:

("0" + "9").slice(-2)

"09"

But if date.getMonth() returns 10, it will be:

("0" + "10") // Giving us "010"

so adding .slice(-2) gives us the last two characters, or:

("0" + "10").slice(-2)

"10"

Answer 27

Answering another for Simplicity & readability.
Also, editing existing predefined class members with new methods is not encouraged:

function getDateInYYYYMMDD() {
    let currentDate = new Date();

    // year
    let yyyy = '' + currentDate.getFullYear();

    // month
    let mm = ('0' + (currentDate.getMonth() + 1));  // prepend 0 // +1 is because Jan is 0
    mm = mm.substr(mm.length - 2);                  // take last 2 chars

    // day
    let dd = ('0' + currentDate.getDate());         // prepend 0
    dd = dd.substr(dd.length - 2);                  // take last 2 chars

    return yyyy + "" + mm + "" + dd;
}

var currentDateYYYYMMDD = getDateInYYYYMMDD();
console.log('currentDateYYYYMMDD: ' + currentDateYYYYMMDD);

Answer 28

From ES6 onwards you can use template strings to make it a little shorter:

var now = new Date();
var todayString = `${now.getFullYear()}-${now.getMonth()}-${now.getDate()}`;

This solution does not zero pad. Look to the other good answers to see how to do that.

Answer 29

If you don't mind including an additional (but small) library, Sugar.js provides lots of nice functionality for working with dates in JavaScript. To format a date, use the format function:

new Date().format("{yyyy}{MM}{dd}")

Answer 30

If using AngularJs (up to 1.5) you can use the date filter:

var formattedDate = $filter('date')(myDate, 'yyyyMMdd')