18
votes

I'm trying to make my project python2.7 and 3 compatible and python 3 has the built in method int.from_bytes. Does the equivalent exist in python 2.7 or rather what would be the best way to make this code 2.7 and 3 compatible?

>>> int.from_bytes(b"f483", byteorder="big")
1714698291
4
If you're specifically looking for a cross-version solution then you should make this clear in the title. - Ignacio Vazquez-Abrams

4 Answers

26
votes

You can treat it as an encoding (Python 2 specific):

>>> int('f483'.encode('hex'), 16)
1714698291

Or in Python 2 and Python 3:

>>> int(codecs.encode(b'f483', 'hex'), 16)
1714698291

The advantage is the string is not limited to a specific size assumption. The disadvantage is it is unsigned.

9
votes
struct.unpack(">i","f483")[0]

maybe?

> means big-endian and i means signed 32 bit int

see also: https://docs.python.org/2/library/struct.html

6
votes

Use the struct module to unpack your bytes into integers.

import struct
>>> struct.unpack("<L", "y\xcc\xa6\xbb")[0]
3148270713L
0
votes
> import binascii

> barray = bytearray([0xAB, 0xCD, 0xEF])
> n = int(binascii.hexlify(barray), 16)
> print("0x%02X" % n)

0xABCDEF