So, I'm writing a language using flex/bison and I'm having difficulty with implementing identifiers, specifically when it comes to knowing when you're looking at an assignment or a reference, for example:
1) A = 1+2
2) B + C (where B and C have already been assigned values)
Example one I can work out by returning an ID token from flex to bison, and just following a grammar that recognizes that 1+2 is an integer expression, putting A into the symbol table, and setting its value.
examples two and three are more difficult for me because: after going through my lexer, what's being returned in ex.2 to bison is "ID PLUS ID" -> I have a grammar that recognizes arithmetic expressions for numerical values, like INT PLUS INT (which would produce an INT), or DOUBLE MINUS INT (which would produce a DOUBLE). if I have "ID PLUS ID", how do I know what type the return value is?
Here's the best idea that I've come up with so far: When tokenizing, every time an ID comes up, I search for its value and type in the symbol table and switch out the ID token with its respective information; for example: while tokenizing, I come across B, which has a regex that matches it as being an ID. I look in my symbol table and see that it has a value of 51.2 and is a DOUBLE. So instead of returning ID, with a value of B to bison, I'm returning DOUBLE with a value of 51.2
I have two different solutions that contradict each other. Here's why: if I want to assign a value to an ID, I would say to my compiler A = 5. In this situation, if I'm using my previously described solution, What I'm going to get after everything is tokenized might be, INT ASGN INT, or STRING ASGN INT, etc... So, in this case, I would use the former solution, as opposed to the latter.
My question would be: what kind of logical device do I use to help my compiler know which solution to use?
NOTE: I didn't think it necessary to post source code to describe my conundrum, but I will if anyone could use it effectively as a reference to help me understand their input on this topic.
Thank you.