I need to convert series of images drawn as white on black background letters to images where white and black are inverted (as negative). How can I achieve this using PIL?
5 Answers
Try the following from the docs: http://effbot.org/imagingbook/imageops.htm
from PIL import Image
import PIL.ImageOps
image = Image.open('your_image.png')
inverted_image = PIL.ImageOps.invert(image)
inverted_image.save('new_name.png')
Note: "The ImageOps module contains a number of 'ready-made' image processing operations. This module is somewhat experimental, and most operators only work on L and RGB images."
If the image is RGBA transparent this will fail... This should work though:
from PIL import Image
import PIL.ImageOps
image = Image.open('your_image.png')
if image.mode == 'RGBA':
r,g,b,a = image.split()
rgb_image = Image.merge('RGB', (r,g,b))
inverted_image = PIL.ImageOps.invert(rgb_image)
r2,g2,b2 = inverted_image.split()
final_transparent_image = Image.merge('RGBA', (r2,g2,b2,a))
final_transparent_image.save('new_file.png')
else:
inverted_image = PIL.ImageOps.invert(image)
inverted_image.save('new_name.png')
For anyone working with an image in "1" mode (i.e., 1-bit pixels, black and white, stored with one pixel per byte -- see docs), you need to convert it into "L" mode before calling PIL.ImageOps.invert
.
Thus:
im = im.convert('L')
im = ImageOps.invert(im)
im = im.convert('1')
In case someone is inverting a CMYK
image, the current implementations of PIL and Pillow don't seem to support this and throw an error. You can, however, easily circumvent this problem by inverting your image's individual bands using this handy function (essentially an extension of Greg Sadetsky's post above):
def CMYKInvert(img) :
return Image.merge(img.mode, [ImageOps.invert(b.convert('L')) for b in img.split()])