dispatch_after - GCD in Swift?

Question

I've gone through the iBook from Apple, and couldn't find any definition of it:

Can someone explain the structure of dispatch_after?

dispatch_after(<#when: dispatch_time_t#>, <#queue: dispatch_queue_t?#>, <#block: dispatch_block_t?#>)

Answer 1

A clearer idea of the structure:

dispatch_after(when: dispatch_time_t, queue: dispatch_queue_t, block: dispatch_block_t?)

dispatch_time_t is a UInt64. The dispatch_queue_t is actually type aliased to an NSObject, but you should just use your familiar GCD methods to get queues. The block is a Swift closure. Specifically, dispatch_block_t is defined as () -> Void, which is equivalent to () -> ().

Example usage:

let delayTime = dispatch_time(DISPATCH_TIME_NOW, Int64(1 * Double(NSEC_PER_SEC)))
dispatch_after(delayTime, dispatch_get_main_queue()) {
    print("test")
}

EDIT:

I recommend using @matt's really nice delay function.

EDIT 2:

In Swift 3, there will be new wrappers for GCD. See here: https://github.com/apple/swift-evolution/blob/master/proposals/0088-libdispatch-for-swift3.md

The original example would be written as follows in Swift 3:

let deadlineTime = DispatchTime.now() + .seconds(1)
DispatchQueue.main.asyncAfter(deadline: deadlineTime) {
    print("test")
}

Note that you can write the deadlineTime declaration as DispatchTime.now() + 1.0 and get the same result because the + operator is overridden as follows (similarly for -):

• func +(time: DispatchTime, seconds: Double) -> DispatchTime
• func +(time: DispatchWalltime, interval: DispatchTimeInterval) -> DispatchWalltime

This means that if you don't use the DispatchTimeInterval enum and just write a number, it is assumed that you are using seconds.

Answer 2

I use dispatch_after so often that I wrote a top-level utility function to make the syntax simpler:

func delay(delay:Double, closure:()->()) {
    dispatch_after(
        dispatch_time(
            DISPATCH_TIME_NOW,
            Int64(delay * Double(NSEC_PER_SEC))
        ),
        dispatch_get_main_queue(), closure)
}

And now you can talk like this:

delay(0.4) {
    // do stuff
}

Wow, a language where you can improve the language. What could be better?

---

Update for Swift 3, Xcode 8 Seed 6

Seems almost not worth bothering with, now that they've improved the calling syntax:

func delay(_ delay:Double, closure:@escaping ()->()) {
    let when = DispatchTime.now() + delay
    DispatchQueue.main.asyncAfter(deadline: when, execute: closure)
}

Answer 3

Swift 3+

This is super-easy and elegant in Swift 3+:

DispatchQueue.main.asyncAfter(deadline: .now() + 4.5) {
    // ...
}

Older Answer:

To expand on Cezary's answer, which will execute after 1 nanosecond, I had to do the following to execute after 4 and a half seconds.

let delay = 4.5 * Double(NSEC_PER_SEC)
let time = dispatch_time(DISPATCH_TIME_NOW, Int64(delay))
dispatch_after(time, dispatch_get_main_queue(), block)

Edit: I discovered that my original code was slightly wrong. Implicit typing causes a compile error if you don't cast NSEC_PER_SEC to a Double.

If anyone can suggest a more optimal solution I'd be keen to hear it.

Answer 4

matt's syntax is very nice and if you need to invalidate the block, you may want to use this :

typealias dispatch_cancelable_closure = (cancel : Bool) -> Void

func delay(time:NSTimeInterval, closure:()->Void) ->  dispatch_cancelable_closure? {

    func dispatch_later(clsr:()->Void) {
        dispatch_after(
            dispatch_time(
                DISPATCH_TIME_NOW,
                Int64(time * Double(NSEC_PER_SEC))
            ),
            dispatch_get_main_queue(), clsr)
    }

    var closure:dispatch_block_t? = closure
    var cancelableClosure:dispatch_cancelable_closure?

    let delayedClosure:dispatch_cancelable_closure = { cancel in
        if closure != nil {
            if (cancel == false) {
                dispatch_async(dispatch_get_main_queue(), closure!);
            }
        }
        closure = nil
        cancelableClosure = nil
    }

    cancelableClosure = delayedClosure

    dispatch_later {
        if let delayedClosure = cancelableClosure {
            delayedClosure(cancel: false)
        }
    }

    return cancelableClosure;
}

func cancel_delay(closure:dispatch_cancelable_closure?) {

    if closure != nil {
        closure!(cancel: true)
    }
}

Use as follow

let retVal = delay(2.0) {
    println("Later")
}
delay(1.0) {
    cancel_delay(retVal)
}

credits

Link above seems to be down. Original Objc code from Github

Answer 5

Simplest solution in Swift 3.0 & Swift 4.0 & Swift 5.0

func delayWithSeconds(_ seconds: Double, completion: @escaping () -> ()) {
    DispatchQueue.main.asyncAfter(deadline: .now() + seconds) { 
        completion()
    }
}

Usage

delayWithSeconds(1) {
   //Do something
}

Answer 6

Apple has a dispatch_after snippet for Objective-C:

dispatch_after(dispatch_time(DISPATCH_TIME_NOW, (int64_t)(<#delayInSeconds#> * NSEC_PER_SEC)), dispatch_get_main_queue(), ^{
    <#code to be executed after a specified delay#>
});

Here is the same snippet ported to Swift 3:

DispatchQueue.main.asyncAfter(deadline: DispatchTime.now() + <#delayInSeconds#>) {
  <#code to be executed after a specified delay#>
}

Answer 7

Another way is to extend Double like this:

extension Double {
   var dispatchTime: dispatch_time_t {
       get {
           return dispatch_time(DISPATCH_TIME_NOW,Int64(self * Double(NSEC_PER_SEC)))
       }
   }
}

Then you can use it like this:

dispatch_after(Double(2.0).dispatchTime, dispatch_get_main_queue(), { () -> Void in
            self.dismissViewControllerAnimated(true, completion: nil)
    })

I like matt's delay function but just out of preference I'd rather limit passing closures around.

Answer 8

In Swift 3.0

Dispatch queues

  DispatchQueue(label: "test").async {
        //long running Background Task
        for obj in 0...1000 {
            print("async \(obj)")
        }

        // UI update in main queue
        DispatchQueue.main.async(execute: { 
            print("UI update on main queue")
        })

    }

    DispatchQueue(label: "m").sync {
        //long running Background Task
        for obj in 0...1000 {
            print("sync \(obj)")
        }

        // UI update in main queue
        DispatchQueue.main.sync(execute: {
            print("UI update on main queue")
        })
    }

Dispatch after 5 seconds

    DispatchQueue.main.after(when: DispatchTime.now() + 5) {
        print("Dispatch after 5 sec")
    }

Answer 9

Swift 3.0 version

Following closure function execute some task after delay on main thread.

func performAfterDelay(delay : Double, onCompletion: @escaping() -> Void){

    DispatchQueue.main.asyncAfter(deadline: DispatchTime.now() + delay, execute: {
       onCompletion()
    })
}

Call this function like:

performAfterDelay(delay: 4.0) {
  print("test")
}

Answer 10

1) Add this method as a part of UIViewController Extension.

extension UIViewController{
func runAfterDelay(delay: NSTimeInterval, block: dispatch_block_t) {
        let time = dispatch_time(DISPATCH_TIME_NOW, Int64(delay * Double(NSEC_PER_SEC)))
        dispatch_after(time, dispatch_get_main_queue(), block)
    }
}

Call this method on VC:

    self.runAfterDelay(5.0, block: {
     //Add code to this block
        print("run After Delay Success")
    })

2)

performSelector("yourMethod Name", withObject: nil, afterDelay: 1)

3)

override func viewWillAppear(animated: Bool) {

dispatch_after(dispatch_time(DISPATCH_TIME_NOW, 2), dispatch_get_main_queue(), { () -> () in
    //Code Here
})

//Compact Form

dispatch_after(dispatch_time(DISPATCH_TIME_NOW, 2), dispatch_get_main_queue()) {
    //Code here
 }
}

Answer 11

In Swift 5, use in the below:

 DispatchQueue.main.asyncAfter(deadline: .now() + 0.2, execute: closure) 

// time gap, specify unit is second
DispatchQueue.main.asyncAfter(deadline: .now() + .seconds(2)) {
            Singleton.shared().printDate()
        }
// default time gap is second, you can reduce it
    DispatchQueue.main.asyncAfter(deadline: .now() + 0.2) {
          // just do it!
    }

Answer 12

Although not the original question by the OP, certain NSTimer related questions have been marked as duplicates of this question, so it is worth including an NSTimer answer here.

NSTimer vs dispatch_after

• NSTimer is more high level while dispatch_after is more low level.
• NSTimer is easier to cancel. Canceling dispatch_after requires writing more code.

Delaying a task with NSTimer

Create an NSTimer instance.

var timer = NSTimer()

Start the timer with the delay that you need.

// invalidate the timer if there is any chance that it could have been called before
timer.invalidate()
// delay of 2 seconds
timer = NSTimer.scheduledTimerWithTimeInterval(2.0, target: self, selector: #selector(delayedAction), userInfo: nil, repeats: false) 

Add a function to be called after the delay (using whatever name you used for the selector parameter above).

func delayedAction() {
    print("Delayed action has now started."
}

Notes

• If you need to cancel the action before it happens, simply call timer.invalidate().
• For a repeated action use repeats: true.

• If you have a one time event with no need to cancel then there is no need to create the timer instance variable. The following will suffice:

  NSTimer.scheduledTimerWithTimeInterval(2.0, target: self, selector: #selector(delayedAction), userInfo: nil, repeats: false) 
  

• See my fuller answer here.

Answer 13

For multiple functions use this. This is very helpful to use animations or Activity loader for static functions or any UI Update.

DispatchQueue.main.asyncAfter(deadline: .now() + 0.9) {
            // Call your function 1
            DispatchQueue.main.asyncAfter(deadline: .now() + 0.5) {
                // Call your function 2
            }
        }

For example - Use a animation before a tableView reloads. Or any other UI update after the animation.

*// Start your amination* 
self.startAnimation()
DispatchQueue.main.asyncAfter(deadline: .now() + 0.9) {
                *// The animation will execute depending on the delay time*
                self.stopAnimation()
                DispatchQueue.main.asyncAfter(deadline: .now() + 0.5) {
                    *// Now update your view*
                     self.fetchData()
                     self.updateUI()
                }
            }

Answer 14

This worked for me.

Swift 3:

let time1 = 8.23
let time2 = 3.42

// Delay 2 seconds

DispatchQueue.main.asyncAfter(deadline: .now() + 2.0) {
    print("Sum of times: \(time1 + time2)")
}

Objective-C:

CGFloat time1 = 3.49;
CGFloat time2 = 8.13;

// Delay 2 seconds

dispatch_after(dispatch_time(DISPATCH_TIME_NOW, (int64_t)(2.0 * NSEC_PER_SEC)), dispatch_get_main_queue(), ^{
    CGFloat newTime = time1 + time2;
    NSLog(@"New time: %f", newTime);
});

Answer 15

Swift 3 & 4:

You can create a extension on DispatchQueue and add function delay which uses DispatchQueue asyncAfter function internally

extension DispatchQueue {
    static func delay(_ delay: DispatchTimeInterval, closure: @escaping () -> ()) {
        let timeInterval = DispatchTime.now() + delay
        DispatchQueue.main.asyncAfter(deadline: timeInterval, execute: closure)
    }
}

use:

DispatchQueue.delay(.seconds(1)) {
    print("This is after delay")
}

Answer 16

Another helper to delay your code that is 100% Swift in usage and optionally allows for choosing a different thread to run your delayed code from:

public func delay(bySeconds seconds: Double, dispatchLevel: DispatchLevel = .main, closure: @escaping () -> Void) {
    let dispatchTime = DispatchTime.now() + seconds
    dispatchLevel.dispatchQueue.asyncAfter(deadline: dispatchTime, execute: closure)
}

public enum DispatchLevel {
    case main, userInteractive, userInitiated, utility, background
    var dispatchQueue: DispatchQueue {
        switch self {
        case .main:                 return DispatchQueue.main
        case .userInteractive:      return DispatchQueue.global(qos: .userInteractive)
        case .userInitiated:        return DispatchQueue.global(qos: .userInitiated)
        case .utility:              return DispatchQueue.global(qos: .utility)
        case .background:           return DispatchQueue.global(qos: .background)
        }
    }
}

Now you simply delay your code on the Main thread like this:

delay(bySeconds: 1.5) { 
    // delayed code
}

If you want to delay your code to a different thread:

delay(bySeconds: 1.5, dispatchLevel: .background) { 
    // delayed code that will run on background thread
}

---

If you prefer a Framework that also has some more handy features then checkout HandySwift. You can add it to your project via Carthage then use it exactly like in the examples above, e.g.:

import HandySwift    

delay(bySeconds: 1.5) { 
    // delayed code
}

Answer 17

I always prefer to use extension instead of free functions.

Swift 4

public extension DispatchQueue {

  private class func delay(delay: TimeInterval, closure: @escaping () -> Void) {
    let when = DispatchTime.now() + delay
    DispatchQueue.main.asyncAfter(deadline: when, execute: closure)
  }

  class func performAction(after seconds: TimeInterval, callBack: @escaping (() -> Void) ) {
    DispatchQueue.delay(delay: seconds) {
      callBack()
    }
  }

}

Use as follow.

DispatchQueue.performAction(after: 0.3) {
  // Code Here
}

Answer 18

Delaying GCD call using asyncAfter in swift

let delayQueue = DispatchQueue(label: "com.theappmaker.in", qos: .userInitiated)
let additionalTime: DispatchTimeInterval = .seconds(2)

We can delay as **microseconds,milliseconds,nanoseconds

delayQueue.asyncAfter(deadline: .now() + 0.60) {
    print(Date())
}

delayQueue.asyncAfter(deadline: .now() + additionalTime) {
    print(Date())
}

Answer 19

In Swift 4

Use this snippet:

    let delayInSec = 1.0
    DispatchQueue.main.asyncAfter(deadline: .now() + delayInSec) {
       // code here
       print("It works")
    }

Answer 20

dispatch_after(dispatch_time(DISPATCH_TIME_NOW, (int64_t)(10 * NSEC_PER_SEC)), dispatch_get_main_queue(), ^{
    // ...
});

The dispatch_after(_:_:_:) function takes three parameters:

a delay
a dispatch queue
a block or closure

The dispatch_after(_:_:_:) function invokes the block or closure on the dispatch queue that is passed to the function after a given delay. Note that the delay is created using the dispatch_time(_:_:) function. Remember this because we also use this function in Swift.

I recommend to go through the tutorial Raywenderlich Dispatch tutorial

Answer 21

use this code to perform some UI related task after 2.0 seconds.

            let delay = 2.0
            let delayInNanoSeconds = dispatch_time(DISPATCH_TIME_NOW, Int64(delay * Double(NSEC_PER_SEC)))
            let mainQueue = dispatch_get_main_queue()

            dispatch_after(delayInNanoSeconds, mainQueue, {

                print("Some UI related task after delay")
            })

Swift 3.0 version

Following closure function execute some task after delay on main thread.

func performAfterDelay(delay : Double, onCompletion: @escaping() -> Void){

    DispatchQueue.main.asyncAfter(deadline: DispatchTime.now() + delay, execute: {
       onCompletion()
    })
}

Call this function like:

performAfterDelay(delay: 4.0) {
  print("test")
}

Answer 22

Now more than syntactic sugar for asynchronous dispatches in Grand Central Dispatch (GCD) in Swift.

add Podfile

pod 'AsyncSwift'

Then,you can use it like this.

let seconds = 3.0
Async.main(after: seconds) {
print("Is called after 3 seconds")
}.background(after: 6.0) {
print("At least 3.0 seconds after previous block, and 6.0 after Async code is called")
}

Answer 23

Swift 4 has a pretty short way of doing this:

Timer.scheduledTimer(withTimeInterval: 2, repeats: false) { (timer) in
    // Your stuff here
    print("hello")
}

Answer 24

Here is synchronous version of asyncAfter in Swift:

let deadline = DispatchTime.now() + .seconds(3)
let semaphore = DispatchSemaphore.init(value: 0)
DispatchQueue.global().asyncAfter(deadline: deadline) {
    dispatchPrecondition(condition: .onQueue(DispatchQueue.global()))
    semaphore.signal()
}

semaphore.wait()

Along with asynchronous one:

let deadline = DispatchTime.now() + .seconds(3)
DispatchQueue.main.asyncAfter(deadline: deadline) {
    dispatchPrecondition(condition: .onQueue(DispatchQueue.global()))
}

Answer 25

Preserve the current queue!

Besides good answers of this question, you may also consider preserving the current queue to prevent unnecessarily main queue operations (for example when you are trying to delay some async operations).

func after(_ delay: TimeInterval,
           perform block: @escaping ()->(),
           on queue: DispatchQueue = OperationQueue.current?.underlyingQueue ?? .main) { // So this `queue` preserves the current queue and defaulted to the `main`. Also the caller can pass in the desired queue explicitly
    queue.asyncAfter(deadline: .now() + delay, execute: block)
}

Usage:

after(3) {
    // will be executed on the caller's queue
    print(Date())
}

Answer 26

To execute a funtion or code after a delay use the next method

DispatchQueue.main.asyncAfter(deadline: .now() + 'secondsOfDelay') {
        your code here...
    }

Example - In this example the funtion getShowMovies will be executed after 1 second

DispatchQueue.main.asyncAfter(deadline: .now() + 1) {
        self.getShowMovies()
    }