How to compare strings in Bash

Question

How do I compare a variable to a string (and do something if they match)?

Answer 1

Using variables in if statements

if [ "$x" = "valid" ]; then
  echo "x has the value 'valid'"
fi

If you want to do something when they don't match, replace = with !=. You can read more about string operations and arithmetic operations in their respective documentation.

Why do we use quotes around $x?

You want the quotes around $x, because if it is empty, your Bash script encounters a syntax error as seen below:

if [ = "valid" ]; then

---

Non-standard use of == operator

Note that Bash allows == to be used for equality with [, but this is not standard.

Use either the first case wherein the quotes around $x are optional:

if [[ "$x" == "valid" ]]; then

or use the second case:

if [ "$x" = "valid" ]; then

Answer 2

Or, if you don't need else clause:

[ "$x" == "valid" ] && echo "x has the value 'valid'"

Answer 3

a="abc"
b="def"

# Equality Comparison
if [ "$a" == "$b" ]; then
    echo "Strings match"
else
    echo "Strings don't match"
fi

# Lexicographic (greater than, less than) comparison.
if [ "$a" \< "$b" ]; then
    echo "$a is lexicographically smaller then $b"
elif [ "$a" \> "$b" ]; then
    echo "$b is lexicographically smaller than $a"
else
    echo "Strings are equal"
fi

Notes:

1. Spaces between if and [ and ] are important
2. > and < are redirection operators so escape it with \> and \< respectively for strings.

Answer 4

To compare strings with wildcards, use:

if [[ "$stringA" == *$stringB* ]]; then
  # Do something here
else
  # Do something here
fi

Answer 5

I have to disagree one of the comments in one point:

[ "$x" == "valid" ] && echo "valid" || echo "invalid"

No, that is not a crazy oneliner

It's just it looks like one to, hmm, the uninitiated...

It uses common patterns as a language, in a way;

And after you learned the language.

Actually, it's nice to read

It is a simple logical expression, with one special part: lazy evaluation of the logic operators.

[ "$x" == "valid" ] && echo "valid" || echo "invalid"

Each part is a logical expression; the first may be true or false, the other two are always true.

(
[ "$x" == "valid" ] 
&&
echo "valid"
)
||
echo "invalid"

Now, when it is evaluated, the first is checked. If it is false, than the second operand of the logic and && after it is not relevant. The first is not true, so it can not be the first and the second be true, anyway.
Now, in this case is the the first side of the logic or || false, but it could be true if the other side - the third part - is true.

So the third part will be evaluated - mainly writing the message as a side effect. (It has the result 0 for true, which we do not use here)

The other cases are similar, but simpler - and - I promise! are - can be - easy to read!
(I don't have one, but I think being a UNIX veteran with grey beard helps a lot with this.)

Answer 6

The following script reads from a file named "testonthis" line by line and then compares each line with a simple string, a string with special characters and a regular expression. If it doesn't match, then the script will print the line, otherwise not.

Space in Bash is so much important. So the following will work:

[ "$LINE" != "table_name" ] 

But the following won't:

["$LINE" != "table_name"] 

So please use as is:

cat testonthis | while read LINE
do
if [ "$LINE" != "table_name" ] && [ "$LINE" != "--------------------------------" ] && [[ "$LINE" =~ [^[:space:]] ]] && [[ "$LINE" != SQL* ]]; then
echo $LINE
fi
done

Answer 7

You can also use use case/esac:

case "$string" in
 "$pattern" ) echo "found";;
esac

Answer 8

I would probably use regexp matches if the input has only a few valid entries. E.g. only the "start" and "stop" are valid actions.

if [[ "${ACTION,,}" =~ ^(start|stop)$ ]]; then
  echo "valid action"
fi

Note that I lowercase the variable $ACTION by using the double comma's. Also note that this won't work on too aged bash versions out there.

Answer 9

Bash 4+ examples. Note: not using quotes will cause issues when words contain spaces, etc. Always quote in Bash, IMO.

Here are some examples in Bash 4+:

Example 1, check for 'yes' in string (case insensitive):

    if [[ "${str,,}" == *"yes"* ]] ;then

Example 2, check for 'yes' in string (case insensitive):

    if [[ "$(echo "$str" | tr '[:upper:]' '[:lower:]')" == *"yes"* ]] ;then

Example 3, check for 'yes' in string (case sensitive):

     if [[ "${str}" == *"yes"* ]] ;then

Example 4, check for 'yes' in string (case sensitive):

     if [[ "${str}" =~ "yes" ]] ;then

Example 5, exact match (case sensitive):

     if [[ "${str}" == "yes" ]] ;then

Example 6, exact match (case insensitive):

     if [[ "${str,,}" == "yes" ]] ;then

Example 7, exact match:

     if [ "$a" = "$b" ] ;then

Enjoy.

Answer 10

I did it in this way that is compatible with Bash and Dash (sh):

testOutput="my test"
pattern="my"

case $testOutput in (*"$pattern"*)
    echo "if there is a match"
    exit 1
    ;;
(*)
   ! echo there is no coincidence!
;;esac

Answer 11

Are you having comparison problems? (like below?)

var="true"
if [[ $var == "true" ]];then
  #should be working but it is not....
else
  #it is falling here...
fi

Try like the =~ operator (regular expression operator) and it might work:

var="true"
if [[ $var =~ "true" ]];then
  #now it works here!!
else
  #no more inequality 
fi