I don't use moc in the project. With new signal/slot syntax it works pretty good. But became necessary to emit signal in the derived Qt class.
It is possible without using moc?
0
votes
you can create your own signal/slot-like architecture without moc (obviously something simpler, you don't have a moc pass..) and use it however you want. I did it some time ago and it worked pretty well
– Marco A.
Relevant: woboq.com/blog/reflection-in-cpp-and-qt-moc.html
– jaho
What are your reasons not to use moc?
– Frank Osterfeld
@David Kernin, Thanks for the link, there is very informative article.
– kaa
2 Answers
2
votes
No, this is not possible.
moc actually implements the signal function. If you look into the generated signal function by looking at the generated moc_myclass.cpp, you'll see that the signal function is nothing more than a call to QMetaObject::activate, and that function requires a pointer to the QMetaObject of the signal sender. Since without running moc, no metaobject is generated, you can't even call QMetaObject::activate manually.
