108
votes

I want to send an "ajax download request" when I click on a button, so I tried in this way:

javascript:

var xhr = new XMLHttpRequest();
xhr.open("GET", "download.php");
xhr.send();

download.php:

<?
header("Cache-Control: public");
header("Content-Description: File Transfer");
header("Content-Disposition: attachment; filename= file.txt");
header("Content-Transfer-Encoding: binary");    
readfile("file.txt");
?>

but doesn't work as expected, how can I do ? Thank you in advance

13
This will not work, see [this question][1]. [1]: stackoverflow.com/questions/8771342/…olegsv
Do location.href='download.php';Musa
When you need this, it does feel like it's a common thing to ask for, and sadly with no elegant solutions.0xc0de

13 Answers

97
votes

Update April 27, 2015

Up and coming to the HTML5 scene is the download attribute. It's supported in Firefox and Chrome, and soon to come to IE11. Depending on your needs, you could use it instead of an AJAX request (or using window.location) so long as the file you want to download is on the same origin as your site.

You could always make the AJAX request/window.location a fallback by using some JavaScript to test if download is supported and if not, switching it to call window.location.

Original answer

You can't have an AJAX request open the download prompt since you physically have to navigate to the file to prompt for download. Instead, you could use a success function to navigate to download.php. This will open the download prompt but won't change the current page.

$.ajax({
    url: 'download.php',
    type: 'POST',
    success: function() {
        window.location = 'download.php';
    }
});

Even though this answers the question, it's better to just use window.location and avoid the AJAX request entirely.

54
votes

To make the browser downloads a file you need to make the request like that:

 function downloadFile(urlToSend) {
     var req = new XMLHttpRequest();
     req.open("GET", urlToSend, true);
     req.responseType = "blob";
     req.onload = function (event) {
         var blob = req.response;
         var fileName = req.getResponseHeader("fileName") //if you have the fileName header available
         var link=document.createElement('a');
         link.href=window.URL.createObjectURL(blob);
         link.download=fileName;
         link.click();
     };

     req.send();
 }
47
votes

You actually don't need ajax at all for this. If you just set "download.php" as the href on the button, or, if it's not a link use:

window.location = 'download.php';

The browser should recognise the binary download and not load the actual page but just serve the file as a download.

21
votes

Cross browser solution, tested on Chrome, Firefox, Edge, IE11.

In the DOM, add an hidden link tag:

<a id="target" style="display: none"></a>

Then:

var req = new XMLHttpRequest();
req.open("GET", downloadUrl, true);
req.responseType = "blob";
req.setRequestHeader('my-custom-header', 'custom-value'); // adding some headers (if needed)

req.onload = function (event) {
  var blob = req.response;
  var fileName = null;
  var contentType = req.getResponseHeader("content-type");

  // IE/EDGE seems not returning some response header
  if (req.getResponseHeader("content-disposition")) {
    var contentDisposition = req.getResponseHeader("content-disposition");
    fileName = contentDisposition.substring(contentDisposition.indexOf("=")+1);
  } else {
    fileName = "unnamed." + contentType.substring(contentType.indexOf("/")+1);
  }

  if (window.navigator.msSaveOrOpenBlob) {
    // Internet Explorer
    window.navigator.msSaveOrOpenBlob(new Blob([blob], {type: contentType}), fileName);
  } else {
    var el = document.getElementById("target");
    el.href = window.URL.createObjectURL(blob);
    el.download = fileName;
    el.click();
  }
};
req.send();
14
votes

It is possible. You can have the download started from inside an ajax function, for example, just after the .csv file is created.

I have an ajax function that exports a database of contacts to a .csv file, and just after it finishes, it automatically starts the .csv file download. So, after I get the responseText and everything is Ok, I redirect browser like this:

window.location="download.php?filename=export.csv";

My download.php file looks like this:

<?php

    $file = $_GET['filename'];

    header("Cache-Control: public");
    header("Content-Description: File Transfer");
    header("Content-Disposition: attachment; filename=".$file."");
    header("Content-Transfer-Encoding: binary");
    header("Content-Type: binary/octet-stream");
    readfile($file);

?>

There is no page refresh whatsoever and the file automatically starts downloading.

NOTE - Tested in the following browsers:

Chrome v37.0.2062.120 
Firefox v32.0.1
Opera v12.17
Internet Explorer v11
4
votes

I prefer location.assign(url);

Complete syntax example:

document.location.assign('https://www.urltodocument.com/document.pdf');

developer.mozilla.org/en-US/docs/Web/API/Location.assign

2
votes

For those looking a more modern approach, you can use the fetch API. The following example shows how to download a spreadsheet file. It is easily done with the following code.

fetch(url, {
    body: JSON.stringify(data),
    method: 'POST',
    headers: {
        'Content-Type': 'application/json; charset=utf-8'
    },
})
.then(response => response.blob())
.then(response => {
    const blob = new Blob([response], {type: 'application/application/vnd.openxmlformats-officedocument.spreadsheetml.sheet'});
    const downloadUrl = URL.createObjectURL(blob);
    const a = document.createElement("a");
    a.href = downloadUrl;
    a.download = "file.xlsx";
    document.body.appendChild(a);
    a.click();
})

I believe this approach to be much easier to understand than other XMLHttpRequest solutions. Also, it has a similar syntax to the jQuery approach, without the need to add any additional libraries.

Of course, I would advise checking to which browser you are developing, since this new approach won't work on IE. You can find the full browser compatibility list on the following link.

Important: In this example I am sending a JSON request to a server listening on the given url. This url must be set, on my example I am assuming you know this part. Also, consider the headers needed for your request to work. Since I am sending a JSON, I must add the Content-Type header and set it to application/json; charset=utf-8, as to let the server know the type of request it will receive.

1
votes

@Joao Marcos solution works for me but I had to modify the code to make it work on IE, below if what the code looks like

       downloadFile(url,filename) {
        var that = this;
        const extension =  url.split('/').pop().split('?')[0].split('.').pop();

        var req = new XMLHttpRequest();
        req.open("GET", url, true);
        req.responseType = "blob";
        req.onload = function (event) {
            const fileName = `${filename}.${extension}`;
            const blob = req.response;

            if (window.navigator.msSaveBlob) { // IE
                window.navigator.msSaveOrOpenBlob(blob, fileName);
            } 
            const link = document.createElement('a');
            link.href = window.URL.createObjectURL(blob);                
            link.download = fileName;
            link.click();
            URL.revokeObjectURL(link.href);

        };

        req.send();
    },
0
votes

Decoding a filename from the header is a little bit more complex...

    var filename = "default.pdf";
    var disposition = req.getResponseHeader('Content-Disposition');

    if (disposition && disposition.indexOf('attachment') !== -1) 
    {
       var filenameRegex = /filename[^;=\n]*=((['"]).*?\2|[^;\n]*)/;
       var matches = filenameRegex.exec(disposition);

       if (matches != null && matches[1]) 
           filename = matches[1].replace(/['"]/g, '');
    }
0
votes

This solution is not very different from those above, but for me it works very well and i think it's clean.

I suggest to base64 encode the file server side (base64_encode(), if you are using PHP) and send the base64 encoded data to the client

On the client you do this:

 let blob = this.dataURItoBlob(THE_MIME_TYPE + "," + response.file);
 let uri = URL.createObjectURL(blob);
 let link = document.createElement("a");
 link.download = THE_FILE_NAME,
 link.href = uri;
 document.body.appendChild(link);
 link.click();
 document.body.removeChild(link);

This code puts the encoded data in a link and simulates a click on the link, then it removes it.

0
votes

Your needs are covered by window.location('download.php');
But I think that you need to pass the file to be downloaded, not always download the same file, and that's why you are using a request, one option is to create a php file as simple as showfile.php and do a request like

var myfile = filetodownload.txt
var url = "shofile.php?file=" + myfile ;
ajaxRequest.open("GET", url, true);

showfile.php

<?php
$file = $_GET["file"] 
echo $file;

where file is the file name passed via Get or Post in the request and then catch the response in a function simply

if(ajaxRequest.readyState == 4){
                        var file = ajaxRequest.responseText;
                        window.location = 'downfile.php?file=' + file;  
                    }
                }
0
votes

there is another solution to download a web page in ajax. But I am referring to a page that must first be processed and then downloaded.

First you need to separate the page processing from the results download.

1) Only the page calculations are made in the ajax call.

$.post("CalculusPage.php", { calculusFunction: true, ID: 29, data1: "a", data2: "b" },

       function(data, status) 
       {
            if (status == "success") 
            {
                /* 2) In the answer the page that uses the previous calculations is downloaded. For example, this can be a page that prints the results of a table calculated in the ajax call. */
                window.location.href = DownloadPage.php+"?ID="+29;
            }               
       }
);

// For example: in the CalculusPage.php

    if ( !empty($_POST["calculusFunction"]) ) 
    {
        $ID = $_POST["ID"];

        $query = "INSERT INTO ExamplePage (data1, data2) VALUES ('".$_POST["data1"]."', '".$_POST["data2"]."') WHERE id = ".$ID;
        ...
    }

// For example: in the DownloadPage.php

    $ID = $_GET["ID"];

    $sede = "SELECT * FROM ExamplePage WHERE id = ".$ID;
    ...

    $filename="Export_Data.xls";
    header("Content-Type: application/vnd.ms-excel");
    header("Content-Disposition: inline; filename=$filename");

    ...

I hope this solution can be useful for many, as it was for me.

0
votes

this works for me

var dataObj = {
somekey:"someValue"
}
     $.ajax({
        method: "POST",
        url: "/someController/someMethod",
        data: dataObj,
        success: function (response) {
            const blob = new Blob([response], { type: 'text/csv' });
            const downloadUrl = URL.createObjectURL(blob);
            const a = document.createElement("a");
            a.href = downloadUrl;
            a.download = "file.csv";
            document.body.appendChild(a);
            a.click();
        }
    });