Convert Begin and End Coordinates into Spatial Lines in R

13
votes

I have a set of begin and end coordinates that look like this:

begin.coord <- data.frame(lon=c(-85.76,-85.46,-85.89), lat=c(38.34,38.76,38.31))
end.coord <- data.frame(lon=c(-85.72,-85.42,-85.85), lat=c(38.38,38.76,38.32))

I am trying to create a set of 3 line segments by connecting each begin point to its corresponding end point. I would like the end product to be a SpatialLines object so that I can use the it with over function in the sp package.

3
rspatial

3 Answers

13
votes

Here's a way: 

## raw list to store Lines objects
l <- vector("list", nrow(begin.coord))
library(sp)
for (i in seq_along(l)) {
    l[[i]] <- Lines(list(Line(rbind(as.matrix(begin.coord[i, ], end.coord[i,])))), as.character(i))
}

SpatialLines(l)

This makes a separate Lines object (each with a unique ID) for each pair, you otherwise might want a single object?

And just for fun, build as a spatstat psp object first and then coerce with methods in maptools:

library(spatstat)
p <- psp(begin.coord[,1], begin.coord[,2], end.coord[,1], end.coord[,2],     owin(range(c(begin.coord[,1], end.coord[,1])), range(c(begin.coord[,2], end.coord[,2]))))

library(maptools)
as(p, "SpatialLines")
6
votes

One could also use the sf package to build a list of sfc class and then convert it to SpatialLines object:

# the given data
begin.coord <- data.frame(lon=c(-85.76,-85.46,-85.89), lat=c(38.34,38.76,38.31))
end.coord <- data.frame(lon=c(-85.72,-85.42,-85.85), lat=c(38.38,38.76,38.32))

library(sf)

# Create list of simple feature geometries (linestrings)
l_sf <- vector("list", nrow(begin.coord))
for (i in seq_along(l_sf)){
  l_sf[[i]] <- st_linestring(as.matrix(rbind(begin.coord[i, ], end.coord[i,])))
}
# Create simple feature geometry list column
l_sfc <- st_sfc(l_sf, crs = "+proj=longlat +datum=WGS84")

# Convert to `sp` object if needed
lines_sp <- as(l_sfc, "Spatial")

Extra/Optional:

# - create a sf object from the `sfc` list of linestrings
lines_sf = st_sf(id = 1:3, geometry = l_sfc)
# - visualize the `sfc` list of linestrings
plot(l_sfc)
library(mapview)
mapview(l_sfc, lwd = 5) 
# or mapview(lines_sp, lwd = 5)
# or mapview(lines_sf, lwd = 5)

enter image description here

3
votes

These days (2020) I would do this with sfheaders: 

begin.coord <- data.frame(lon=c(-85.76,-85.46,-85.89), lat=c(38.34,38.76,38.31))
end.coord <- data.frame(lon=c(-85.72,-85.42,-85.85), lat=c(38.38,38.76,38.32))
begin.coord$linestring_id <- end.coord$linestring_id <- seq_len(nrow(begin.coord))
library(dplyr)

sfheaders::sf_linestring(bind_rows(begin.coord, end.coord) %>% arrange(linestring_id), 
                         x = "lon", y = "lat", linestring_id = "linestring_id")
#>   linestring_id                     geometry
#> 1             1 -85.76, -85.72, 38.34, 38.38
#> 2             2 -85.46, -85.42, 38.76, 38.76
#> 3             3 -85.89, -85.85, 38.31, 38.32

Created on 2020-04-01 by the reprex package (v0.3.0)