Replace line after match

Question

Given this file

$ cat foo.txt
AAA
111
BBB
222
CCC
333

I would like to replace the first line after BBB with 999. I came up with this command

awk '/BBB/ {f=1; print; next} f {$1=999; f=0} 1' foo.txt

but I am curious to any shorter commands with either awk or sed.

Answer 1

This might work for you (GNU sed)

sed '/BBB/!b;n;c999' file

If a line contains BBB, print that line and then change the following line to 999.

!b negates the previous address (regexp) and breaks out of any processing, ending the sed commands, n prints the current line and then reads the next into the pattern space, c changes the current line to the string following the command.

Answer 2

This is some shorter:

awk 'f{$0="999";f=0}/BBB/{f=1}1' file

f {$0="999";f=0} if f is true, set line to 999 and f to 0
/BBB/ {f=1} if pattern match set f to 1
1 print all lines, since 1 is always true.

Answer 3

can use sed also, it's shorter

sed '/BBB/{n;s/.*/999/}'

Answer 4

$ awk '{print (f?999:$0); f=0} /BBB/{f=1}' file    
AAA
111
BBB
999
CCC
333

Answer 5

awk '/BBB/{print;getline;$0="999"}1' your_file

Answer 6

sed 's/\(BBB\)/\1\
999/'

works on mac