I have "I love Suzi and Marry" and I want to change "Suzi" to "Sara".
#!/bin/bash
firstString="I love Suzi and Marry"
secondString="Sara"
# do something...
The result must be like this:
firstString="I love Sara and Marry"
I have "I love Suzi and Marry" and I want to change "Suzi" to "Sara".
#!/bin/bash
firstString="I love Suzi and Marry"
secondString="Sara"
# do something...
The result must be like this:
firstString="I love Sara and Marry"
To replace the first occurrence of a pattern with a given string, use ${parameter/pattern/string}
:
#!/bin/bash
firstString="I love Suzi and Marry"
secondString="Sara"
echo "${firstString/Suzi/$secondString}"
# prints 'I love Sara and Marry'
To replace all occurrences, use ${parameter//pattern/string}
:
message='The secret code is 12345'
echo "${message//[0-9]/X}"
# prints 'The secret code is XXXXX'
(This is documented in the Bash Reference Manual, §3.5.3 "Shell Parameter Expansion".)
Note that this feature is not specified by POSIX — it's a Bash extension — so not all Unix shells implement it. For the relevant POSIX documentation, see The Open Group Technical Standard Base Specifications, Issue 7, the Shell & Utilities volume, §2.6.2 "Parameter Expansion".
This can be done entirely with bash string manipulation:
first="I love Suzy and Mary"
second="Sara"
first=${first/Suzy/$second}
That will replace only the first occurrence; to replace them all, double the first slash:
first="Suzy, Suzy, Suzy"
second="Sara"
first=${first//Suzy/$second}
# first is now "Sara, Sara, Sara"
For Dash all previous posts aren't working
The POSIX sh
compatible solution is:
result=$(echo "$firstString" | sed "s/Suzi/$secondString/")
This will replace the first occurrence on each line of input. Add a /g
flag to replace all occurrences:
result=$(echo "$firstString" | sed "s/Suzi/$secondString/g")
It's better to use bash than sed
if strings have RegExp characters.
echo ${first_string/Suzi/$second_string}
It's portable to Windows and works with at least as old as Bash 3.1.
To show you don't need to worry much about escaping let's turn this:
/home/name/foo/bar
Into this:
~/foo/bar
But only if /home/name
is in the beginning. We don't need sed
!
Given that bash gives us magic variables $PWD
and $HOME
, we can:
echo "${PWD/#$HOME/\~}"
EDIT: Thanks for Mark Haferkamp in the comments for the note on quoting/escaping ~
.*
Note how the variable $HOME
contains slashes but this didn't break anything.
Further reading: Advanced Bash-Scripting Guide.
If using sed
is a must, be sure to escape every character.
Pure POSIX shell method, which unlike Roman Kazanovskyi's sed
-based answer needs no external tools, just the shell's own native parameter expansions. Note that long file names are minimized so the code fits better on one line:
f="I love Suzi and Marry"
s=Sara
t=Suzi
[ "${f%$t*}" != "$f" ] && f="${f%$t*}$s${f#*$t}"
echo "$f"
Output:
I love Sara and Marry
How it works:
Remove Smallest Suffix Pattern. "${f%$t*}"
returns "I love
" if the suffix $t
"Suzi*
" is in $f
"I love
Suzi and Marry
".
But if t=Zelda
, then "${f%$t*}"
deletes nothing, and returns the whole string "I love Suzi and Marry
".
This is used to test if $t
is in $f
with [ "${f%$t*}" != "$f" ]
which will evaluate to true if the $f
string contains "Suzi*
" and false if not.
If the test returns true, construct the desired string using Remove Smallest Suffix Pattern ${f%$t*}
"I love
" and Remove Smallest Prefix Pattern ${f#*$t}
"and Marry
", with the 2nd string $s
"Sara
" in between.