How do I transfer the items contained in one List
to another in C# without using foreach
?
344
votes
9 Answers
603
votes
You could try this:
List<Int32> copy = new List<Int32>(original);
or if you're using C# 3 and .NET 3.5, with Linq, you can do this:
List<Int32> copy = original.ToList();
I see that this answer is still getting upvotes. Well, here's a secret for ya: the above answer is still using a foreach. Please don't upvote this any further.
190
votes
40
votes
For a list of elements
List<string> lstTest = new List<string>();
lstTest.Add("test1");
lstTest.Add("test2");
lstTest.Add("test3");
lstTest.Add("test4");
lstTest.Add("test5");
lstTest.Add("test6");
If you want to copy all the elements
List<string> lstNew = new List<string>();
lstNew.AddRange(lstTest);
If you want to copy the first 3 elements
List<string> lstNew = lstTest.GetRange(0, 3);
6
votes
4
votes
This method will create a copy of your list but your type should be serializable.
Use:
List<Student> lstStudent = db.Students.Where(s => s.DOB < DateTime.Now).ToList().CopyList();
Method:
public static List<T> CopyList<T>(this List<T> lst)
{
List<T> lstCopy = new List<T>();
foreach (var item in lst)
{
using (MemoryStream stream = new MemoryStream())
{
BinaryFormatter formatter = new BinaryFormatter();
formatter.Serialize(stream, item);
stream.Position = 0;
lstCopy.Add((T)formatter.Deserialize(stream));
}
}
return lstCopy;
}
1
votes
0
votes
OK this is working well From the suggestions above GetRange( ) does not work for me with a list as an argument...so sweetening things up a bit from posts above: ( thanks everyone :)
/* Where __strBuf is a string list used as a dumping ground for data */
public List < string > pullStrLst( )
{
List < string > lst;
lst = __strBuf.GetRange( 0, __strBuf.Count );
__strBuf.Clear( );
return( lst );
}
-1
votes