How do I check if a C++ std::string starts with a certain string, and convert a substring to an int?

Question

How do I implement the following (Python pseudocode) in C++?

if argv[1].startswith('--foo='):
    foo_value = int(argv[1][len('--foo='):])

(For example, if argv[1] is --foo=98, then foo_value is 98.)

Update: I'm hesitant to look into Boost, since I'm just looking at making a very small change to a simple little command-line tool (I'd rather not have to learn how to link in and use Boost for a minor change).

Answer 1

Use rfind overload that takes the search position pos parameter, and pass zero for it:

std::string s = "tititoto";
if (s.rfind("titi", 0) == 0) { // pos=0 limits the search to the prefix
  // s starts with prefix
}

Who needs anything else? Pure STL!

Many have misread this to mean "search backwards through the whole string looking for the prefix". That would give the wrong result (e.g. string("tititito").rfind("titi") returns 2 so when compared against == 0 would return false) and it would be inefficient (looking through the whole string instead of just the start). But it does not do that because it passes the pos parameter as 0, which limits the search to only match at that position or earlier. For example:

std::string test = "0123123";
size_t match1 = test.rfind("123");    // returns 4 (rightmost match)
size_t match2 = test.rfind("123", 2); // returns 1 (skipped over later match)
size_t match3 = test.rfind("123", 0); // returns std::string::npos (i.e. not found)

Answer 2

You would do it like this:

std::string prefix("--foo=");
if (!arg.compare(0, prefix.size(), prefix))
    foo_value = std::stoi(arg.substr(prefix.size()));

Looking for a lib such as Boost.ProgramOptions that does this for you is also a good idea.

Answer 3

Just for completeness, I will mention the C way to do it:

If str is your original string, substr is the substring you want to check, then

strncmp(str, substr, strlen(substr))

will return 0 if str starts with substr. The functions strncmp and strlen are in the C header file <string.h>

^{(originally posted by Yaseen Rauf here, markup added)}

For a case-insensitive comparison, use strnicmp instead of strncmp.

This is the C way to do it, for C++ strings you can use the same function like this:

strncmp(str.c_str(), substr.c_str(), substr.size())

Answer 4

If you're already using Boost, you can do it with boost string algorithms + boost lexical cast:

#include <boost/algorithm/string/predicate.hpp>
#include <boost/lexical_cast.hpp>

try {    
    if (boost::starts_with(argv[1], "--foo="))
        foo_value = boost::lexical_cast<int>(argv[1]+6);
} catch (boost::bad_lexical_cast) {
    // bad parameter
}

This kind of approach, like many of the other answers provided here is ok for very simple tasks, but in the long run you are usually better off using a command line parsing library. Boost has one (Boost.Program_options), which may make sense if you happen to be using Boost already.

Otherwise a search for "c++ command line parser" will yield a number of options.

Answer 5

Code I use myself:

std::string prefix = "-param=";
std::string argument = argv[1];
if(argument.substr(0, prefix.size()) == prefix) {
    std::string argumentValue = argument.substr(prefix.size());
}

Answer 6

Nobody used the STL algorithm/mismatch function yet. If this returns true, prefix is a prefix of 'toCheck':

std::mismatch(prefix.begin(), prefix.end(), toCheck.begin()).first == prefix.end()

Full example prog:

#include <algorithm>
#include <string>
#include <iostream>

int main(int argc, char** argv) {
    if (argc != 3) {
        std::cerr << "Usage: " << argv[0] << " prefix string" << std::endl
                  << "Will print true if 'prefix' is a prefix of string" << std::endl;
        return -1;
    }
    std::string prefix(argv[1]);
    std::string toCheck(argv[2]);
    if (prefix.length() > toCheck.length()) {
        std::cerr << "Usage: " << argv[0] << " prefix string" << std::endl
                  << "'prefix' is longer than 'string'" <<  std::endl;
        return 2;
    }
    if (std::mismatch(prefix.begin(), prefix.end(), toCheck.begin()).first == prefix.end()) {
        std::cout << '"' << prefix << '"' << " is a prefix of " << '"' << toCheck << '"' << std::endl;
        return 0;
    } else {
        std::cout << '"' << prefix << '"' << " is NOT a prefix of " << '"' << toCheck << '"' << std::endl;
        return 1;
    }
}

---

Edit:

As @James T. Huggett suggests, std::equal is a better fit for the question: Is A a prefix of B? and is slight shorter code:

std::equal(prefix.begin(), prefix.end(), toCheck.begin())

Full example prog:

#include <algorithm>
#include <string>
#include <iostream>

int main(int argc, char **argv) {
  if (argc != 3) {
    std::cerr << "Usage: " << argv[0] << " prefix string" << std::endl
              << "Will print true if 'prefix' is a prefix of string"
              << std::endl;
    return -1;
  }
  std::string prefix(argv[1]);
  std::string toCheck(argv[2]);
  if (prefix.length() > toCheck.length()) {
    std::cerr << "Usage: " << argv[0] << " prefix string" << std::endl
              << "'prefix' is longer than 'string'" << std::endl;
    return 2;
  }
  if (std::equal(prefix.begin(), prefix.end(), toCheck.begin())) {
    std::cout << '"' << prefix << '"' << " is a prefix of " << '"' << toCheck
              << '"' << std::endl;
    return 0;
  } else {
    std::cout << '"' << prefix << '"' << " is NOT a prefix of " << '"'
              << toCheck << '"' << std::endl;
    return 1;
  }
}

Answer 7

Given that both strings — argv[1] and "--foo" — are C strings, @FelixDombek's answer is hands-down the best solution.

Seeing the other answers, however, I thought it worth noting that, if your text is already available as a std::string, then a simple, zero-copy, maximally efficient solution exists that hasn't been mentioned so far:

const char * foo = "--foo";
if (text.rfind(foo, 0) == 0)
    foo_value = text.substr(strlen(foo));

And if foo is already a string:

std::string foo("--foo");
if (text.rfind(foo, 0) == 0)
    foo_value = text.substr(foo.length());

Answer 8

With C++17 you can use std::basic_string_view & with C++20 std::basic_string::starts_with or std::basic_string_view::starts_with.

The benefit of std::string_view in comparison to std::string - regarding memory management - is that it only holds a pointer to a "string" (contiguous sequence of char-like objects) and knows its size. Example without moving/copying the source strings just to get the integer value:

#include <exception>
#include <iostream>
#include <string>
#include <string_view>

int main()
{
    constexpr auto argument = "--foo=42"; // Emulating command argument.
    constexpr auto prefix = "--foo=";
    auto inputValue = 0;

    constexpr auto argumentView = std::string_view(argument);
    if (argumentView.starts_with(prefix))
    {
        constexpr auto prefixSize = std::string_view(prefix).size();
        try
        {
            // The underlying data of argumentView is nul-terminated, therefore we can use data().
            inputValue = std::stoi(argumentView.substr(prefixSize).data());
        }
        catch (std::exception & e)
        {
            std::cerr << e.what();
        }
    }
    std::cout << inputValue; // 42
}

Answer 9

text.substr(0, start.length()) == start

Answer 10

At the risk of being flamed for using C constructs, I do think this sscanf example is more elegant than most Boost solutions. And you don't have to worry about linkage if you're running anywhere that has a Python interpreter!

#include <stdio.h>
#include <string.h>

int main(int argc, char **argv)
{
    for (int i = 1; i != argc; ++i) {
        int number = 0;
        int size = 0;
        sscanf(argv[i], "--foo=%d%n", &number, &size);
        if (size == strlen(argv[i])) {
            printf("number: %d\n", number);
        }
        else {
            printf("not-a-number\n");
        }
    }
    return 0;
}

Here's some example output that demonstrates the solution handles leading/trailing garbage as correctly as the equivalent Python code, and more correctly than anything using atoi (which will erroneously ignore a non-numeric suffix).

$ ./scan --foo=2 --foo=2d --foo='2 ' ' --foo=2'
number: 2
not-a-number
not-a-number
not-a-number

Answer 11

Using STL this could look like:

std::string prefix = "--foo=";
std::string arg = argv[1];
if (prefix.size()<=arg.size() && std::equal(prefix.begin(), prefix.end(), arg.begin())) {
  std::istringstream iss(arg.substr(prefix.size()));
  iss >> foo_value;
}

Answer 12

I use std::string::compare wrapped in utility method like below:

static bool startsWith(const string& s, const string& prefix) {
    return s.size() >= prefix.size() && s.compare(0, prefix.size(), prefix) == 0;
}

Answer 13

Starting with C++20, you can use the starts_with method.

std::string s = "abcd";
if (s.starts_with("abc")) {
    ...
}

Answer 14

In C++20 now there is starts_with available as a member function of std::string defined as:

constexpr bool starts_with(string_view sv) const noexcept;

constexpr bool starts_with(CharT c) const noexcept;

constexpr bool starts_with(const CharT* s) const;

So your code could be something like this:

std::string s{argv[1]};

if (s.starts_with("--foo="))

Answer 15

In case you need C++11 compatibility and cannot use boost, here is a boost-compatible drop-in with an example of usage:

#include <iostream>
#include <string>

static bool starts_with(const std::string str, const std::string prefix)
{
    return ((prefix.size() <= str.size()) && std::equal(prefix.begin(), prefix.end(), str.begin()));
}

int main(int argc, char* argv[])
{
    bool usage = false;
    unsigned int foos = 0; // default number of foos if no parameter was supplied

    if (argc > 1)
    {
        const std::string fParamPrefix = "-f="; // shorthand for foo
        const std::string fooParamPrefix = "--foo=";

        for (unsigned int i = 1; i < argc; ++i)
        {
            const std::string arg = argv[i];

            try
            {
                if ((arg == "-h") || (arg == "--help"))
                {
                    usage = true;
                } else if (starts_with(arg, fParamPrefix)) {
                    foos = std::stoul(arg.substr(fParamPrefix.size()));
                } else if (starts_with(arg, fooParamPrefix)) {
                    foos = std::stoul(arg.substr(fooParamPrefix.size()));
                }
            } catch (std::exception& e) {
                std::cerr << "Invalid parameter: " << argv[i] << std::endl << std::endl;
                usage = true;
            }
        }
    }

    if (usage)
    {
        std::cerr << "Usage: " << argv[0] << " [OPTION]..." << std::endl;
        std::cerr << "Example program for parameter parsing." << std::endl << std::endl;
        std::cerr << "  -f, --foo=N   use N foos (optional)" << std::endl;
        return 1;
    }

    std::cerr << "number of foos given: " << foos << std::endl;
}

Answer 16

Why not use gnu getopts? Here's a basic example (without safety checks):

#include <getopt.h>
#include <stdio.h>

int main(int argc, char** argv)
{
  option long_options[] = {
    {"foo", required_argument, 0, 0},
    {0,0,0,0}
  };

  getopt_long(argc, argv, "f:", long_options, 0);

  printf("%s\n", optarg);
}

For the following command:

$ ./a.out --foo=33

You will get

33

Answer 17

C++20 update :

• Use std::string::starts_with

https://en.cppreference.com/w/cpp/string/basic_string/starts_with

std::string str_value = /* smthg */;
const auto starts_with_foo = str_value.starts_with(std::string_view{"foo"});

Answer 18

Ok why the complicated use of libraries and stuff? C++ String objects overload the [] operator, so you can just compare chars.. Like what I just did, because I want to list all files in a directory and ignore invisible files and the .. and . pseudofiles.

while ((ep = readdir(dp)))
{
    string s(ep->d_name);
    if (!(s[0] == '.')) // Omit invisible files and .. or .
        files.push_back(s);
}

It's that simple..

Answer 19

You can also use strstr:

if (strstr(str, substr) == substr) {
    // 'str' starts with 'substr'
}

but I think it's good only for short strings because it has to loop through the whole string when the string doesn't actually start with 'substr'.

Answer 20

std::string text = "--foo=98";
std::string start = "--foo=";

if (text.find(start) == 0)
{
    int n = stoi(text.substr(start.length()));
    std::cout << n << std::endl;
}

Answer 21

With C++11 or higher you can use find() and find_first_of()

Example using find to find a single char:

#include <string>
std::string name = "Aaah";
size_t found_index = name.find('a');
if (found_index != std::string::npos) {
    // Found string containing 'a'
}

Example using find to find a full string & starting from position 5:

std::string name = "Aaah";
size_t found_index = name.find('h', 3);
if (found_index != std::string::npos) {
    // Found string containing 'h'
}

Example using the find_first_of() and only the first char, to search at the start only:

std::string name = ".hidden._di.r";
size_t found_index = name.find_first_of('.');
if (found_index == 0) {
    // Found '.' at first position in string
}

• More about find
• More about find_first_of

Good luck!

Answer 22

Since C++11 std::regex_search can also be used to provide even more complex expressions matching. The following example handles also floating numbers thorugh std::stof and a subsequent cast to int.

However the parseInt method shown below could throw a std::invalid_argument exception if the prefix is not matched; this can be easily adapted depending on the given application:

#include <iostream>
#include <regex>

int parseInt(const std::string &str, const std::string &prefix) {
  std::smatch match;
  std::regex_search(str, match, std::regex("^" + prefix + "([+-]?(?=\\.?\\d)\\d*(?:\\.\\d*)?(?:[Ee][+-]?\\d+)?)$"));
  return std::stof(match[1]);
}

int main() {
    std::cout << parseInt("foo=13.3", "foo=") << std::endl;
    std::cout << parseInt("foo=-.9", "foo=") << std::endl;
    std::cout << parseInt("foo=+13.3", "foo=") << std::endl;
    std::cout << parseInt("foo=-0.133", "foo=") << std::endl;
    std::cout << parseInt("foo=+00123456", "foo=") << std::endl;
    std::cout << parseInt("foo=-06.12e+3", "foo=") << std::endl;

//    throw std::invalid_argument
//    std::cout << parseInt("foo=1", "bar=") << std::endl;

    return 0;
}

The kind of magic of the regex pattern is well detailed in the following answer.

EDIT: the previous answer did not performed the conversion to integer.

Answer 23

if(boost::starts_with(string_to_search, string_to_look_for))
    intval = boost::lexical_cast<int>(string_to_search.substr(string_to_look_for.length()));

This is completely untested. The principle is the same as the Python one. Requires Boost.StringAlgo and Boost.LexicalCast.

Check if the string starts with the other string, and then get the substring ('slice') of the first string and convert it using lexical cast.