I've got an problem with fitting of a vector.
I have 2 curves with the same function, which I want to compare. But each curve have a other timevector because they have a different samplingrate (only tstart = 0 and tend = 8.853958 are same).
So I tried to interpolate the short vector to the same length like the long vector... But I dont get it.. In a other simulation it works... But not here...
The error-message is:
Error using chckxy (line 51) The data sites should be distinct.
Error in spline (line 54) [x,y,sizey,endslopes] = chckxy(x,y);
Error in Labor_2ndReceiver (line 434)
dInt = spline(tspline,d,t1);
My code:
tstart = 0;
tstep = 1/fs;
tend = (pi/((1/5)*2))-tstep;
tendSync = 1; %Wait for 1 sec
t0 = tstart:tstep:tendSync; %Time for synchronisation
t01 = tendSync+tstep:tstep:tend; %Time after synchronisation to Tend
t1 = [t0 t01]; %Complete Time
dInt = spline(tspline,d,t1);
where
%tspline <1x32605 double>:
%Columns 1 through 24000 all values are '1'
%and Column 24001 is 0.249041666666667
%and Column 24002 to 32605 are some increasing values to 8.852958333333334 (but without a constant sampling rate)
%d <1x32605 double>; t1 <1x424992 double>
So could you help me please? It is very important...
Thank u so much!
EDIT: Thanks, but there is still a problem... see figure...
tspline =0:t1(end)/length(d):t1(end)-t1(end)/length(d);
dInt = spline(tspline,d,t1);
So the Interpolation works... but the Values are wrong... because dInt starts too late.. it shout start like d..
How could I solve this?