112
votes

How do I run a python script from within the IDLE interactive shell?

The following throws an error:

>>> python helloworld.py
SyntaxError: invalid syntax
15
What does helloworld.py look like? - TerryA
yeah it means something is wrong with youre code post youre code! - Serial
No, not necessarily. Chances are the OP is typing python helloworld.py in an IDLE shell window and that doesn't work. - Ned Deily
Nor would it work in the standard interpreter. This issue has come up before where people mistakenly think that the interpreter prompt is a command-line prompt. - Terry Jan Reedy
You should accept the answer from Ned Deily if that answer your question correctly. This will also help fellow developers to quickly spot the correct answer. - Krishna Oza

15 Answers

158
votes

Python3:

exec(open('helloworld.py').read())

If your file not in the same dir:

exec(open('./app/filename.py').read())

See https://stackoverflow.com/a/437857/739577 for passing global/local variables.


In deprecated Python versions

Python2 Built-in function: execfile

execfile('helloworld.py')

It normally cannot be called with arguments. But here's a workaround:

import sys
sys.argv = ['helloworld.py', 'arg']  # argv[0] should still be the script name
execfile('helloworld.py')

Deprecated since 2.6: popen

import os
os.popen('python helloworld.py') # Just run the program
os.popen('python helloworld.py').read() # Also gets you the stdout

With arguments:

os.popen('python helloworld.py arg').read()

Advance usage: subprocess

import subprocess
subprocess.call(['python', 'helloworld.py']) # Just run the program
subprocess.check_output(['python', 'helloworld.py']) # Also gets you the stdout

With arguments:

subprocess.call(['python', 'helloworld.py', 'arg'])

Read the docs for details :-)


Tested with this basic helloworld.py:

import sys
if len(sys.argv) > 1:
    print(sys.argv[1])
38
votes

You can use this in python3:

exec(open(filename).read())
25
votes

The IDLE shell window is not the same as a terminal shell (e.g. running sh or bash). Rather, it is just like being in the Python interactive interpreter (python -i). The easiest way to run a script in IDLE is to use the Open command from the File menu (this may vary a bit depending on which platform you are running) to load your script file into an IDLE editor window and then use the Run -> Run Module command (shortcut F5).

6
votes

Try this

import os
import subprocess

DIR = os.path.join('C:\\', 'Users', 'Sergey', 'Desktop', 'helloword.py')

subprocess.call(['python', DIR])
6
votes

EASIEST WAY

python -i helloworld.py  #Python 2

python3 -i helloworld.py #Python 3
4
votes

execFile('helloworld.py') does the job for me. A thing to note is to enter the complete directory name of the .py file if it isnt in the Python folder itself (atleast this is the case on Windows)

For example, execFile('C:/helloworld.py')

2
votes

For example:

import subprocess

subprocess.call("C:\helloworld.py")

subprocess.call(["python", "-h"])
2
votes

In a python console, one can try the following 2 ways.

under the same work directory,

1. >> import helloworld

# if you have a variable x, you can print it in the IDLE.

>> helloworld.x

# if you have a function func, you can also call it like this.

>> helloworld.func()

2. >> runfile("./helloworld.py")

1
votes

In Python 3, there is no execFile. One can use exec built-in function, for instance:

import helloworld
exec('helloworld')
1
votes

In IDLE, the following works :-

import helloworld

I don't know much about why it works, but it does..

1
votes

To run a python script in a python shell such as Idle or in a Django shell you can do the following using the exec() function. Exec() executes a code object argument. A code object in Python is simply compiled Python code. So you must first compile your script file and then execute it using exec(). From your shell:

>>>file_to_compile = open('/path/to/your/file.py').read()
>>>code_object = compile(file_to_compile, '<string>', 'exec')
>>>exec(code_object)

I'm using Python 3.4. See the compile and exec docs for detailed info.

1
votes

I tested this and it kinda works out :

exec(open('filename').read())  # Don't forget to put the filename between ' '
1
votes

you can do it by two ways

  • import file_name

  • exec(open('file_name').read())

but make sure that file should be stored where your program is running

0
votes

On Windows environment, you can execute py file on Python3 shell command line with the following syntax:

exec(open('absolute path to file_name').read())

Below explains how to execute a simple helloworld.py file from python shell command line

File Location: C:/Users/testuser/testfolder/helloworld.py

File Content: print("hello world")

We can execute this file on Python3.7 Shell as below:

>>> import os
>>> abs_path = 'C://Users/testuser/testfolder'
>>> os.chdir(abs_path)
>>> os.getcwd()
'C:\\Users\\testuser\\testfolder'

>>> exec(open("helloworld.py").read())
hello world

>>> exec(open("C:\\Users\\testuser\\testfolder\\helloworld.py").read())
hello world

>>> os.path.abspath("helloworld.py")
'C:\\Users\\testuser\\testfolder\\helloworld.py'
>>> import helloworld
hello world
0
votes

There is one more alternative (for windows) -

    import os
    os.system('py "<path of program with extension>"')