python - UnboundLocalError: local variable … referenced before assignment

Question

import hmac, base64, hashlib, urllib2
base = 'https://.......'

def makereq(key, secret, path, data):
    hash_data = path + chr(0) + data
    secret = base64.b64decode(secret)
    sha512 = hashlib.sha512
    hmac = str(hmac.new(secret, hash_data, sha512))

    header = {
        'User-Agent': 'My-First-test',
        'Rest-Key': key,
        'Rest-Sign': base64.b64encode(hmac),
        'Accept-encoding': 'GZIP',
        'Content-Type': 'application/x-www-form-urlencoded'
    }

    return urllib2.Request(base + path, data, header)

Error: File "C:/Python27/btctest.py", line 8, in makereq hmac = str(hmac.new(secret, hash_data, sha512)) UnboundLocalError: local variable 'hmac' referenced before assignment

Somebody knows why? Thanks

Andrew Clark Andrew Clark · Accepted Answer · 2013-06-13T21:27:47

If you assign to a variable anywhere in a function, that variable will be treated as a local variable everywhere in that function. So you would see the same error with the following code:

foo = 2
def test():
    print foo
    foo = 3

In other words, you cannot access the global or external variable if there is a local variable in the function of the same name.

To fix this, just give your local variable hmac a different name:

def makereq(key, secret, path, data):
    hash_data = path + chr(0) + data
    secret = base64.b64decode(secret)
    sha512 = hashlib.sha512
    my_hmac = str(hmac.new(secret, hash_data, sha512))

    header = {
        'User-Agent': 'My-First-test',
        'Rest-Key': key,
        'Rest-Sign': base64.b64encode(my_hmac),
        'Accept-encoding': 'GZIP',
        'Content-Type': 'application/x-www-form-urlencoded'
    }

    return urllib2.Request(base + path, data, header)

Note that this behavior can be changed by using the global or nonlocal keywords, but it doesn't seem like you would want to use those in your case.

python - UnboundLocalError: local variable … referenced before assignment

2 Answers