Obtain form input fields using jQuery?

Question

I have a form with many input fields.

When I catch the submit form event with jQuery, is it possible to get all the input fields of that form in an associative array?

Answer 1

$('#myForm').submit(function() {
    // get all the inputs into an array.
    var $inputs = $('#myForm :input');

    // not sure if you wanted this, but I thought I'd add it.
    // get an associative array of just the values.
    var values = {};
    $inputs.each(function() {
        values[this.name] = $(this).val();
    });

});

---

Thanks to the tip from Simon_Weaver, here is another way you could do it, using serializeArray:

var values = {};
$.each($('#myForm').serializeArray(), function(i, field) {
    values[field.name] = field.value;
});

Note that this snippet will fail on <select multiple> elements.

It appears that the new HTML 5 form inputs don't work with serializeArray in jQuery version 1.3. This works in version 1.4+

Answer 2

Late to the party on this question, but this is even easier:

$('#myForm').submit(function() {
    // Get all the forms elements and their values in one step
    var values = $(this).serialize();

});

Answer 3

The jquery.form plugin may help with what others are looking for that end up on this question. I'm not sure if it directly does what you want or not.

There is also the serializeArray function.

Answer 4

Sometimes I find getting one at a time is more useful. For that, there's this:

var input_name = "firstname";
var input = $("#form_id :input[name='"+input_name+"']"); 

Answer 5

$('#myForm').bind('submit', function () {
  var elements = this.elements;
});

The elements variable will contain all the inputs, selects, textareas and fieldsets within the form.

Answer 6

Here is another solution, this way you can fetch all data about the form and use it in a serverside call or something.

$('.form').on('submit', function( e )){ 
   var form = $( this ), // this will resolve to the form submitted
       action = form.attr( 'action' ),
         type = form.attr( 'method' ),
         data = {};

     // Make sure you use the 'name' field on the inputs you want to grab. 
   form.find( '[name]' ).each( function( i , v ){
      var input = $( this ), // resolves to current input element.
          name = input.attr( 'name' ),
          value = input.val();
      data[name] = value;
   });

  // Code which makes use of 'data'.

 e.preventDefault();
}

You can then use this with ajax calls:

function sendRequest(action, type, data) {
       $.ajax({
            url: action,
           type: type,
           data: data
       })
       .done(function( returnedHtml ) {
           $( "#responseDiv" ).append( returnedHtml );
       })
       .fail(function() {
           $( "#responseDiv" ).append( "This failed" );
       });
}

Hope this is of any use for any of you :)

Answer 7

Had a similar issue with a slight twist and I thought I'd throw this out. I have a callback function that gets the form so I had a form object already and couldn't easy variants on $('form:input'). Instead I came up with:

    var dataValues = {};
    form.find('input').each(
        function(unusedIndex, child) {
            dataValues[child.name] = child.value;
        });

Its similar but not identical situation, but I found this thread very useful and thought I'd tuck this on the end and hope someone else found it useful.

Answer 8

This piece of code will work instead of name, email enter your form fields name

$(document).ready(function(){
  $("#form_id").submit(function(event){
    event.preventDefault();
    var name = $("input[name='name']",this).val();
    var email = $("input[name='email']",this).val();
  });
});

Answer 9

http://api.jquery.com/serializearray/

$('#form').on('submit', function() {
    var data = $(this).serializeArray();
});

This can also be done without jQuery using the XMLHttpRequest Level 2 FormData object

http://www.w3.org/TR/2010/WD-XMLHttpRequest2-20100907/#the-formdata-interface

var data = new FormData([form])

Answer 10

Associative? Not without some work, but you can use generic selectors:

var items = new Array();

$('#form_id:input').each(function (el) {
    items[el.name] = el;
});

Answer 11

jQuery's serializeArray does not include disabled fields, so if you need those too, try:

var data = {};
$('form.my-form').find('input, textarea, select').each(function(i, field) {
    data[field.name] = field.value;
});

Answer 12

Don't forget the checkboxes and radio buttons -

var inputs = $("#myForm :input");
var obj = $.map(inputs, function(n, i) {
  var o = {};
  if (n.type == "radio" || n.type == "checkbox")
    o[n.id] = $(n).attr("checked");
  else
    o[n.id] = $(n).val();
  return o;
});
return obj

Answer 13

Seems strange that nobody has upvoted or proposed a concise solution to getting list data. Hardly any forms are going to be single-dimension objects.

The downside of this solution is, of course, that your singleton objects are going to have to be accessed at the [0] index. But IMO that's way better than using one of the dozen-line mapping solutions.

var formData = $('#formId').serializeArray().reduce(function (obj, item) {
    if (obj[item.name] == null) {
        obj[item.name] = [];
    } 
    obj[item.name].push(item.value);
    return obj;
}, {});

Answer 14

I had the same problem and solved it in a different way.

var arr = new Array();
$(':input').each(function() {
 arr.push($(this).val());
});
arr;

It returns the value of all input fields. You could change the $(':input') to be more specific.

Answer 15

Same solution as given by nickf, but with array input names taken into account eg

<input type="text" name="array[]" />

values = {};
$("#something :input").each(function() {
  if (this.name.search(/\[\]/) > 0) //search for [] in name
  {
    if (typeof values[this.name] != "undefined") {
      values[this.name] = values[this.name].concat([$(this).val()])
    } else {
      values[this.name] = [$(this).val()];
    }
  } else {
    values[this.name] = $(this).val();
  }
});

Answer 16

If you need to get multiple values from inputs and you're using []'s to define the inputs with multiple values, you can use the following:

$('#contentform').find('input, textarea, select').each(function(x, field) {
    if (field.name) {
        if (field.name.indexOf('[]')>0) {
            if (!$.isArray(data[field.name])) {
               data[field.name]=new Array();
            }
            data[field.name].push(field.value);
        } else {
            data[field.name]=field.value;
        }
    }                   
});

Answer 17

Inspired by answers of Lance Rushing and Simon_Weaver, this is my favourite solution.

$('#myForm').submit( function( event ) {
    var values = $(this).serializeArray();
    // In my case, I need to fetch these data before custom actions
    event.preventDefault();
});

The output is an array of objects, e.g.

[{name: "start-time", value: "11:01"}, {name: "end-time", value: "11:11"}]

With the code below,

var inputs = {};
$.each(values, function(k, v){
    inputs[v.name]= v.value;
});

its final output would be

{"start-time":"11:01", "end-time":"11:01"}

Answer 18

I am using this code without each loop:

$('.subscribe-form').submit(function(e){
    var arr=$(this).serializeArray();
    var values={};
    for(i in arr){values[arr[i]['name']]=arr[i]['value']}
    console.log(values);
    return false;
});

Answer 19

I hope this is helpful, as well as easiest one.

 $("#form").submit(function (e) { 
    e.preventDefault();
    input_values =  $(this).serializeArray();
  });

Answer 20

When I needed to do an ajax call with all the form fields, I had problems with the :input selector returning all checkboxes whether or not they were checked. I added a new selector to just get the submit-able form elements:

$.extend($.expr[':'],{
    submitable: function(a){
        if($(a).is(':checkbox:not(:checked)'))
        {
            return false;
        }
        else if($(a).is(':input'))
        {
            return true;
        }
        else
        {
            return false;
        }
    }
});

usage:

$('#form_id :submitable');

I've not tested it with multiple select boxes yet though but It works for getting all the form fields in the way a standard submit would.

I used this when customising the product options on an OpenCart site to include checkboxes and text fields as well as the standard select box type.

Answer 21

serialize() is the best method. @ Christopher Parker say that Nickf's anwser accomplishes more, however it does not take into account that the form may contain textarea and select menus. It is far better to use serialize() and then manipulate that as you need to. Data from serialize() can be used in either an Ajax post or get, so there is no issue there.

Answer 22

Hope this helps somebody. :)

// This html:
// <form id="someCoolForm">
// <input type="text" class="form-control" name="username" value="...." />
// 
// <input type="text" class="form-control" name="profile.first_name" value="...." />
// <input type="text" class="form-control" name="profile.last_name" value="...." />
// 
// <input type="text" class="form-control" name="emails[]" value="..." />
// <input type="text" class="form-control" name="emails[]" value=".." />
// <input type="text" class="form-control" name="emails[]" value="." />
// </form>
// 
// With this js:
// 
// var form1 = parseForm($('#someCoolForm'));
// console.log(form1);
// 
// Will output something like:
// {
// username: "test2"
// emails:
//   0: "[email protected]"
//   1: "[email protected]"
// profile: Object
//   first_name: "..."
//   last_name: "..."
// }
// 
// So, function below:

var parseForm = function (form) {

    var formdata = form.serializeArray();

    var data = {};

    _.each(formdata, function (element) {

        var value = _.values(element);

        // Parsing field arrays.
        if (value[0].indexOf('[]') > 0) {
            var key = value[0].replace('[]', '');

            if (!data[key])
                data[key] = [];

            data[value[0].replace('[]', '')].push(value[1]);
        } else

        // Parsing nested objects.
        if (value[0].indexOf('.') > 0) {

            var parent = value[0].substring(0, value[0].indexOf("."));
            var child = value[0].substring(value[0].lastIndexOf(".") + 1);

            if (!data[parent])
                data[parent] = {};

            data[parent][child] = value[1];
        } else {
            data[value[0]] = value[1];
        }
    });

    return data;
};

Answer 23

All answers are good, but if there's a field that you like to ignore in that function? Easy, give the field a property, for example ignore_this:

<input type="text" name="some_name" ignore_this>

And in your Serialize Function:

if(!$(name).prop('ignorar')){
   do_your_thing;
}

That's the way you ignore some fields.

Answer 24

Try the following code:

jQuery("#form").serializeArray().filter(obje => 
obje.value!='').map(aobj=>aobj.name+"="+aobj.value).join("&")

Answer 25

For multiple select elements (<select multiple="multiple">), I modified the solution from @Jason Norwood-Young to get it working.

The answer (as posted) only takes the value from the first element that was selected, not all of them. It also didn't initialize or return data, the former throwing a JavaScript error.

Here is the new version:

function _get_values(form) {
  let data = {};
  $(form).find('input, textarea, select').each(function(x, field) {
    if (field.name) {
      if (field.name.indexOf('[]') > 0) {
        if (!$.isArray(data[field.name])) {
          data[field.name] = new Array();
        }
        for (let i = 0; i < field.selectedOptions.length; i++) {
          data[field.name].push(field.selectedOptions[i].value);
        }

      } else {
        data[field.name] = field.value;
      }
    }

  });
  return data
}

Usage:

_get_values($('#form'))

Note: You just need to ensure that the name of your select has [] appended to the end of it, for example:

<select name="favorite_colors[]" multiple="multiple">
  <option value="red">Red</option>
  <option value="green">Green</option>
  <option value="blue">Blue</option>
</select>

Answer 26

$("#form-id").submit(function (e) { 
  e.preventDefault();
  inputs={};
  input_serialized =  $(this).serializeArray();
  input_serialized.forEach(field => {
    inputs[field.name] = field.value;
  })
  console.log(inputs)
});