Let's say my string is 10 characters long.
How do I remove the last character?
If my string is "abcdefghij" (I do not want to replace the 'j' character, since my string may contain multiple 'j' characters) I only want the last character gone. Regardless of what it is or how many times it occurs, I need to remove the last character from my string.
Simple:
my_str = "abcdefghij"
my_str = my_str[:-1]
Try the following code snippet to better understand how it works by casting the string as a list:
str1 = "abcdefghij"
list1 = list(str1)
print(list1)
list2 = list1[:-1]
print(list2)
In case, you want to accept the string from the user:
str1 = input("Enter :")
list1 = list(str1)
print(list1)
list2 = list1[:-1]
print(list2)
To make it take away the last word from a sentence (with words separated by whitespace like space):
str1 = input("Enter :")
list1 = str1.split()
print(list1)
list2 = list1[:-1]
print(list2)
What you are trying to do is an extension of string slicing in Python:
Say all strings are of length 10, last char to be removed:
>>> st[:9]
'abcdefghi'
To remove last N characters:
>>> N = 3
>>> st[:-N]
'abcdefg'
The siemples solution for you is using string slicing.
Python 2/3:
source[0: -1] # gets all string but not last char
Python 2:
source = 'ABC'
result = "{}{}".format({source[0: -1], 'D')
print(result) # ABD
Python 3:
source = 'ABC'
result = f"{source[0: -1]}D"
print(result) # ABD
my_str[:-1]from the answers in the dup link seems a bit of a jump. As the linked site appears RIGHT NOW (see thelynxcommand), it's hard to find.$ lynx -dump https://web.archive.org/web/20200826203245/https://stackguides.com/questions/663171/how-do-i-get-a-substring-of-a-string-in-python | grep -n "\[[:][-]1\]"\n540:print(a[:-1])\n542:In the above code, [:-1] declares to print from the starting till the\n 548: `Note: Here a [:-1] is also the same as a [0:-1] and a [0:len(a)-1]- bballdave025