I am currently using underscorejs for sort my json sorting. Now I have asked to do an ascending and descending sorting using underscore.js. I do not see anything regarding the same in the documentation. How can I achieve this?
5 Answers
You can use .sortBy, it will always return an ascending list:
_.sortBy([2, 3, 1], function(num) {
return num;
}); // [1, 2, 3]
But you can use the .reverse method to get it descending:
var array = _.sortBy([2, 3, 1], function(num) {
return num;
});
console.log(array); // [1, 2, 3]
console.log(array.reverse()); // [3, 2, 1]
Or when dealing with numbers add a negative sign to the return to descend the list:
_.sortBy([-3, -2, 2, 3, 1, 0, -1], function(num) {
return -num;
}); // [3, 2, 1, 0, -1, -2, -3]
Under the hood .sortBy uses the built in .sort([handler]):
// Default is alphanumeric ascending:
[2, 3, 1].sort(); // [1, 2, 3]
// But can be descending if you provide a sort handler:
[2, 3, 1].sort(function(a, b) {
// a = current item in array
// b = next item in array
return b - a;
});
Descending order using underscore can be done by multiplying the return value by -1.
//Ascending Order:
_.sortBy([2, 3, 1], function(num){
return num;
}); // [1, 2, 3]
//Descending Order:
_.sortBy([2, 3, 1], function(num){
return num * -1;
}); // [3, 2, 1]
If you're sorting by strings not numbers, you can use the charCodeAt() method to get the unicode value.
//Descending Order Strings:
_.sortBy(['a', 'b', 'c'], function(s){
return s.charCodeAt() * -1;
});
The Array prototype's reverse method modifies the array and returns a reference to it, which means you can do this:
var sortedAsc = _.sortBy(collection, 'propertyName');
var sortedDesc = _.sortBy(collection, 'propertyName').reverse();
Also, the underscore documentation reads:
In addition, the Array prototype's methods are proxied through the chained Underscore object, so you can slip a
reverseor apushinto your chain, and continue to modify the array.
which means you can also use .reverse() while chaining:
var sortedDescAndFiltered = _.chain(collection)
.sortBy('propertyName')
.reverse()
.filter(_.property('isGood'))
.value();
Underscore Mixins
Extending on @emil_lundberg's answer, you can also write a "mixin" if you're using Underscore to make a custom function for sorting if it's a kind of sorting you might repeat in an application somewhere.
For example, maybe you have a controller or view sorting results with sort order of "ASC" or "DESC", and you want to toggle between that sort, you could do something like this:
Mixin.js
_.mixin({
sortByOrder: function(stooges, prop, order) {
if (String(order) === "desc") {
return _.sortBy(stooges, prop).reverse();
} else if (String(order) === "asc") {
return _.sortBy(stooges, prop);
} else {
return stooges;
}
}
})
Usage Example
var sort_order = "asc";
var stooges = [
{name: 'moe', age: 40},
{name: 'larry', age: 50},
{name: 'curly', age: 60},
{name: 'July', age: 35},
{name: 'mel', age: 38}
];
_.mixin({
sortByOrder: function(stooges, prop, order) {
if (String(order) === "desc") {
return _.sortBy(stooges, prop).reverse();
} else if (String(order) === "asc") {
return _.sortBy(stooges, prop);
} else {
return stooges;
}
}
})
// find elements
var banner = $("#banner-message");
var sort_name_btn = $("button.sort-name");
var sort_age_btn = $("button.sort-age");
function showSortedResults(results, sort_order, prop) {
banner.empty();
banner.append("<p>Sorting: " + prop + ', ' + sort_order + "</p><hr>")
_.each(results, function(r) {
banner.append('<li>' + r.name + ' is '+ r.age + ' years old.</li>');
})
}
// handle click and add class
sort_name_btn.on("click", function() {
sort_order = (sort_order === "asc") ? "desc" : "asc";
var sortedResults = _.sortByOrder(stooges, 'name', sort_order);
showSortedResults(sortedResults, sort_order, 'name');
})
sort_age_btn.on('click', function() {
sort_order = (sort_order === "asc") ? "desc" : "asc";
var sortedResults = _.sortByOrder(stooges, 'age', sort_order);
showSortedResults(sortedResults, sort_order, 'age');
})
Here's a JSFiddle demonstrating this: JSFiddle for SortBy Mixin
sortByfunction can bereturn -nbut that won't work for strings; hence the question about what sorts of things you're sorting. - mu is too short_.sortBy([1,4,3,2]).reverse()or_.chain([1,4,3,2]).sortBy().reverse().value()if you don't want to use thereverse()prototype of Array. - GFoley83