Migrating from FOSUserBundle to Django

Question

I'm in the process of migrate a php site with FOSUserBundle to a Django user model.

The content of app/config/security.yml:

security:
    encoders:
        FOS\UserBundle\Model\UserInterface: sha512

Values of password/salt from a user test at the PHP site:

• password: 3EBoIIMrD73n2y+4hMUpCq2lmJ8tHStrBweonQClP+/Jhmaw7ipLbamQJQfB87Acg45sBH3HlgnpKI+QZN7m/Q==
• salt: 2n4fxtazv1us0csgg8s880ck4skcskg
• The password used is amdpower

I've tried to generate the same hash with this code:

raw_password = 'amdpower'
salt = '2n4fxtazv1us0csgg8s880ck4skcskg'

salted = '%s{%s}' % (raw_password, salt)
digest =  hashlib.sha512(salted).digest()
for i in range(5000):
   digest = hashlib.sha512(digest).digest()
print base64.b64encode(digest)
>>> wqgbbFZ/IPvwZktbmYz7inffofmT5HbRNf04BQ+w33Jgman8uVYbjWyiKzfp5EIFX2wqYGOb7hRzi5BdZlzDKw==

What's wrong with the hashing code I've tried? How can I generate the same hash?

Update:

The PHP funcs are:

• FOSUserBundle: https://github.com/FriendsOfSymfony/FOSUserBundle/blob/master/Model/UserManager.php#L180

• Symfony: https://github.com/symfony/symfony/tree/master/src/Symfony/Component/Security/Core/Encoder

Solved:

raw_password = 'amdpower'
salt = '2n4fxtazv1us0csgg8s880ck4skcskg'

salted = '%s{%s}' % (raw_password, salt)
digest =  hashlib.sha512(salted).digest()
for i in range(4999):
    digest = hashlib.sha512('%s%s' % (digest, salted)).digest()
print base64.b64encode(digest)
>>> 3EBoIIMrD73n2y+4hMUpCq2lmJ8tHStrBweonQClP+/Jhmaw7ipLbamQJQfB87Acg45sBH3HlgnpKI+QZN7m/Q==

Answer 1

Over here, I've recreated the scenario over how Symfony hashes the password.

http://codepad.org/AhC64q4r

Now it's all about converting it to python, which I know you can do it Juan :)